chapter 4: imperfections in solids issues to ... - materialsmatclass/101/pdffiles/lecture_7.pdf ·...
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CHAPTER 4:IMPERFECTIONS IN SOLIDS
ISSUES TO ADDRESS...
• What types of defects arise in solids?
• Can the number and type of defects be variedand controlled?
• How do defects affect material properties?
• Are defects undesirable?
TYPES OF IMPERFECTIONS
• Vacancy atoms• Interstitial atoms• Substitutional atoms
Point defects
Line defects
Area defects
• Dislocations
• Grain Boundaries
POINT DEFECTS
• Vacancies:-vacant atomic sites in a structure.
Vacancydistortion of planes
• Self-Interstitials:-"extra" atoms positioned between atomic sites.
self-interstitialdistortion
of planes
EQUIL. CONCENTRATION:POINT DEFECTS
• Equilibrium concentration varies with temperature!
Boltzmann's constant
(1.38 x 10-23 J/atom K)
(8.62 x 10-5 eV/atom K)
⎜ ⎟ NDN
= exp−QDkT
⎛
⎝ ⎜ ⎞
⎠ ⎟
No. of defects
No. of potential defect sites.
Activation energy
Temperature
Each lattice site is a potential vacancy site
MEASURING ACTIVATION ENERGY
⎜ ⎟ NDN
= exp−QDkT
⎛
⎝ ⎜ ⎞
⎠ ⎟ • We can get Q from
an experiment.
• Measure this... • Replot it...
1/T
N
NDln 1
-QD/k
slopeND
N
T
exponential dependence!
defect concentration
ESTIMATING VACANCY CONC.
• Find the equil. # of vacancies in 1 m3 of Cu at 1000°C.
ACu = 63.5g/molρ = 8.4 g/cm3
QV = 0.9eV/atom NA = 6.02 x 1023 atoms/mole
8.62 x 10-5 eV/atom-K
0.9eV/atom
1273K
⎜ ⎟ NDN
= exp−QDkT
⎛
⎝ ⎜ ⎞
⎠ ⎟
For 1m3, N =NAACu
ρ x x 1m3 = 8.0 x 1028 sites
= 2.7 · 10-4
• Answer:
ND = 2.7 · 10-4 · 8.0 x 1028 sites = 2.2x 1025 vacancies
POINT DEFECTS IN ALLOYSTwo outcomes if impurity (B) added to host (A):
• Solid solution of B in A (i.e., random dist. of point defects)
Substitutional alloy(e.g., Cu in Ni)
Interstitial alloy(e.g., C in Fe)
OR
• Solid solution of B in A plus particles of a newphase (usually for a larger amount of B)
Second phase particle--different composition--often different structure.
Alloy CompositionWeight Percentage
Ternary, Quaternary, …(3, 4, … components)
Binary(2 components)
10021
11 ×
+=
mmmC 100×
∑=
ii
jj m
mC
Atomic or Mole Percentage
10021
1'1 ×
+=
mm
m
nnnC 100' ×
∑=
imi
mjj n
nC
1
'1
1 Amnm =
100
100
2'21
'1
1'1
1
1221
21'1
×+
=
×+
=
ACACACC
ACACACC
Conversion formulas
Dislocations
DislocationsLine defectsMost important class of defects for ductile crystalline materials (metals!)
Burgers vector bBasic lattice deformation
Edge Dislocationsb perpendicular tothe dislocation line
Schematic atomic structure of an edge dislocation
Screw Dislocations
Schematic perspective view
View of plane ABCD
Screw dislocation line
Burgers vector bBasic lattice deformation
Screw Dislocationsb parallel tothe dislocation line
Mixed Dislocations
Schematic perspective view
View of plane ABCD
Edge
Mixed
Schematic of dislocation line
Screw
Images of Dislocations
~1 µm
Surface
GaN
Sapphire
Dislocations in GaNDislocations in Ti alloy
Interfacial DefectsTwo-dimensional defects – also referred to as planar defects
Free surfacesSurfaces are ‘defects’ – typical energies 0.1 – 1 J/cm2
Grain BoundariesBorders between crystalswith different orientation
High angle grain boundaryLarge misorientation
Low-angle grain boundarySmall misorientationConsists of walls of dislocations
Low Angle Grain Boundaries
Grain 1 Grain 2
Example of a tilt boundary
d
Low angle boundaries
θ ≈ b/d
θ = Grain-Grain misorientationb = Burgers vectord = dislocation spacing
Edge dislocations
Grain Boundary
Observation of MicrostructuresOptical Microscopy (referred to as metallography, ceramography, …)
1 mm = 1000 µm
Optical micrograph of brass
Resolution of optical microscopy ≈ λlight ≈ 500 nm
Observation of MicrostructuresOptical Microscope Transmission Electron Microscope
FEI Tecnai F30 300 kV FE TEM/STEM
(UCSB)
TEM/STEM Resolution~ 1 Å
Observation of MicrostructuresScanning Electron Microscope
Typical SEM Image
SEM Resolution~ 10 Å
Observation of Microstructures
Scanning Probe Microscopy (SPM)
Common modesScanning Tunneling Microscopy (STM)Atomic Force Microscopy (AFM)
AFM Image: GaNSPM Resolution: ~ 1 Å
CHAPTER 6: MECHANICAL PROPERTIES
ISSUES TO ADDRESS...• Stress and strain: What are they and why are
they used instead of load and deformation?
• Elastic behavior: When loads are small, how much deformation occurs? What materials deform least?
• Plastic behavior: At what point do dislocationscause permanent deformation? What materials aremost resistant to permanent deformation?
• Toughness and ductility: What are they and howdo we measure them?
ELASTIC DEFORMATION
F
δ
bonds stretch
return to initial
1. Initial 2. Small load 3. Unload
Elastic means reversible!
F
δ
Linear- elastic
Non-Linear-elastic
PLASTIC DEFORMATION (METALS)
1. Initial 2. Small load 3. Unload
Plastic means permanent!
F
δlinear elastic
linear elastic
δplastic
planes still sheared
F
δelastic + plastic
bonds stretch & planes shear
δplastic
ENGINEERING STRESS
• Tensile stress, σ: • Shear stress, τ:
Area, A
Ft
Ft
σ =FtAo
original area before loading
Area, A
Ft
Ft
Fs
F
F
Fs
τ = FsAo
Stress has units:N/m2 or lb/in2
COMMON STATES OF STRESS
• Simple tension: cable
oσ =
FA
• Simple shear: drive shaft
Ao = cross sectional
Area (when unloaded)
FF
σσ
oτ =
FsA
τ
Note: τ = M/AcR here.
Ski lift (photo courtesy P.M. Anderson)
M
M Ao
2R
FsAc
OTHER COMMON STRESS STATES (1)
Canyon Bridge, Los Alamos, NM
• Simple compression:
Ao
Balanced Rock, Arches National Park o
σ =FA
Note: compressivestructure member(σ < 0 here).
(photo courtesy P.M. Anderson)
(photo courtesy P.M. Anderson)
OTHER COMMON STRESS STATES (2)
• Bi-axial tension: • Hydrostatic compression:
Fish under waterPressurized tank
σ < 0h
(photo courtesyP.M. Anderson)
σz > 0
σθ > 0(photo courtesyP.M. Anderson)
ENGINEERING STRAIN
• Tensile strain: • Lateral strain:
• Shear strain:θ/2
π/2
π/2 - θ
θ/2
δ/2
δ/2
δL/2δL/2
Lowo
ε = δLo
εL =−δL
wo
γ = tan θ Strain is alwaysdimensionless.
STRESS-STRAIN TESTING
• Typical tensile specimen
• Other types of tests:--compression: brittle
materials (e.g., concrete)--torsion: cylindrical tubes,
shafts.
gauge length
(portion of sample with reduced cross section)=
• Typical tensiletest machine
load cell
extensometerspecimen
moving cross head
Adapted from Fig. 6.2,Callister 6e.
Adapted from Fig. 6.3, Callister 6e.(Fig. 6.3 is taken from H.W. Hayden, W.G. Moffatt, and J. Wulff, The Structure and Properties of Materials, Vol. III, Mechanical Behavior, p. 2, John Wiley and Sons, New York, 1965.)
LINEAR ELASTIC PROPERTIES
• Modulus of Elasticity, E:(also known as Young's modulus)
• Hooke's Law:
σ = E ε• Poisson's ratio, ν:
metals: ν ~ 0.33ceramics: ~0.25polymers: ~0.40
εν = − Lε
εL
ε
1-ν
F
Fsimple tension test
σ
Linear- elastic
1E
ε
Units:E: [GPa] or [psi]ν: dimensionless
OTHER ELASTIC PROPERTIES
• Elastic Shearmodulus, G:
τ
1G
γτ = G γ
• Elastic Bulkmodulus, K:
P= -K∆VVo
P
∆V
1-K Vo
• Special relations for isotropic materials:
P
P P
M
M
G =
E2(1+ ν)
K =E
3(1− 2ν)
simpletorsiontest
pressuretest: Init.vol =Vo. Vol chg.= ∆V
11
YOUNG’S MODULI: COMPARISON
0.2
8
0.6
1
Magnesium,Aluminum
Platinum
Silver, Gold
Tantalum
Zinc, Ti
Steel, NiMolybdenum
Graphite
Si crystal
Glass-soda
Concrete
Si nitrideAl oxide
PC
Wood( grain)
AFRE( fibers)*
CFRE*
GFRE*
Glass fibers only
Carbon fibers only
Aramid fibers only
Epoxy only
0.4
0.8
2
46
10
20
406080
100
200
600800
10001200
400
Tin
Cu alloys
Tungsten
<100>
<111>
Si carbide
Diamond
PTFE
HDPE
LDPE
PP
Polyester
PSPET
CFRE( fibers)*
GFRE( fibers)*
GFRE(|| fibers)*
AFRE(|| fibers)*
CFRE(|| fibers)*
MetalsAlloys
GraphiteCeramicsSemicond
PolymersComposites
/fibers
E(GPa)
Eceramics > Emetals >> Epolymers
109 Pa
Based on data in Table B2,Callister 6e.Composite data based onreinforced epoxy with 60 vol%of alignedcarbon (CFRE),aramid (AFRE), orglass (GFRE)fibers.