chapter 25 wave optics lecture 19 - purdue university

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Chapter 25 Wave Optics Lecture 19 25.1 Coherence and Conditions for Interference 25.2 The Michelson Interferometer 25.3 Thin-Film Interference 25.4 Light through a Single-Slit: Qualitative Behavior 25.5 Double-Slit Interference: Young’s Experiment 25.6 Single-Slit Diffraction: Interference of Light frm a Single Slit 25.7 Diffraction Gratings 25.8 Optical Resolution and Rayleigh Criterion

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Page 1: Chapter 25 Wave Optics Lecture 19 - Purdue University

Chapter 25 Wave Optics – Lecture 19

25.1 Coherence and Conditions for Interference

25.2 The Michelson Interferometer

25.3 Thin-Film Interference

25.4 Light through a Single-Slit: Qualitative Behavior

25.5 Double-Slit Interference: Young’s Experiment

25.6 Single-Slit Diffraction: Interference of Light frm a Single

Slit

25.7 Diffraction Gratings

25.8 Optical Resolution and Rayleigh Criterion

Page 2: Chapter 25 Wave Optics Lecture 19 - Purdue University

Wave Optics vs. Geometric Optics

• When discussing image characteristics over

distances much greater than the wavelength,

geometric optics is extremely accurate

• When dealing with sizes comparable to or smaller

than the wavelength, wave optics is required

• Examples include interference effects and propagation

through small openings

Introduction

Page 3: Chapter 25 Wave Optics Lecture 19 - Purdue University

Interference

• One property unique to waves is interference

• Interference is a wave phenomenon

• Interference of sound waves can be produced by two speakers

Section 25.1

Page 4: Chapter 25 Wave Optics Lecture 19 - Purdue University

Constructive Interference

• Require the phase difernece of 0,

2, 4 .... or a path difference x given by

+

=

0, 1, 2,...x m m m m

Destructive Interference

• Here the phase difference between the

two waves is radians, 180, or /2

1

0, 1, 2,...2

x m m m m

+

=

Page 5: Chapter 25 Wave Optics Lecture 19 - Purdue University

Summary - Interference

• If light waves are traveling from some point, then the

phase difference can be related to the path difference between

the two waves

• The criterion for constructive interference is given by a path

difference x given by

• Destructive interference will take place if the path difference x

is a half wavelength plus an integer times the wavelength

• The inter m is called the order of the fringe

0, 1, 2,...x m m m m

1

0, 1, 2,...2

x m m m m

Page 6: Chapter 25 Wave Optics Lecture 19 - Purdue University

Summary- Interference Conditions

• For constructive interference, Δx = m λ

• For destructive interference, Δx = (m + ½) λ

• m is an integer in both cases

• If the interference is constructive, the light

intensity at the detector is large

• Called a bright fringe

• If the interference is destructive, the light

intensity at the detector is zero

• Called a dark fringe

Section 25.2

Page 7: Chapter 25 Wave Optics Lecture 19 - Purdue University

Interference

• Sunlight is composed of light containing a broad range

of frequencies and corresponding wavelengths

• We often see different colors

separated out of sunlight by

refraction in rainbows

• We also sometimes see various

colors from sunlight due to

constructive and destructive

interference phenomena on the

surface of DVD’s or CD’s

or in thin layers of oil or water

Page 8: Chapter 25 Wave Optics Lecture 19 - Purdue University

Michelson Interferometer

• The Michelson

interferometer is based

on the interference of

reflected waves

• Two reflecting mirrors

are mounted at right

angles

• A third mirror is partially

reflecting

• Called a beam splitter

Section 25.2

Page 9: Chapter 25 Wave Optics Lecture 19 - Purdue University

Michelson Interferometer, cont.

• The incident light hits the beam splitter and is divided

into two waves

• The waves reflect from the mirrors at the top and right

and recombine at the beam splitter

• After being reflected again from the

beam splitter, portions of the waves

combine at the detector

• The only difference between the two

waves is that they travel different

distances between their respective

mirrors and the beam splitter

• The path length difference is

ΔL = 2L2 – 2L1 Section 25.2

Page 10: Chapter 25 Wave Optics Lecture 19 - Purdue University

Michelson Interferometer, final

• The path length

difference is related to the

wavelength of the light

• If N is an integer, the two

waves are in phase and

produce constructive

interference

• If N is a half-integer the

waves will produce

destructive interference

LN

D=

l

Section 25.2

Page 11: Chapter 25 Wave Optics Lecture 19 - Purdue University

Measuring Length with a Michelson

Interferometer • Use the light from a laser and adjust the mirror to give

constructive interference

• This corresponds to one of the bright fringes

• The mirror is then moved, changing the path length

• The intensity changes from high to zero and back to high,

every time the path length changes by one wavelength

• If the mirror moves through N bright fringes, the distance

d traveled by the mirror is (for round trip) or N

d =2

l

Section 25.2

• The accuracy of the measurement depends on the

accuracy with which the wavelength is known

• Many laboratories use helium-neon lasers to make very

precise length measurements

d N2

He Ne nm632.99139822

Page 12: Chapter 25 Wave Optics Lecture 19 - Purdue University

• When a light wave

passes from one

medium to another, the

waves must stay in

phase at the interface

• The frequency must be

the same on both sides

of the interface

Section 25.3

Light Traveling in an Optical Medium (1)

Page 13: Chapter 25 Wave Optics Lecture 19 - Purdue University

Light Traveling in an Optical Medium (2)

• We have seen that the wavelength of light changes when traveling in an optical medium with index of refraction greater than one

• Taking with case 1 as a vacuum and case 2 as a medium with index of refraction n, we have found out that we can write

• Remembering that v = f we can write the frequency fn of light traveling in a medium as

• So the frequency does not change !

n

v

c n

/ ( / )n

n

v cf v v c f

1 2

1 2

tv v

nf f

Page 14: Chapter 25 Wave Optics Lecture 19 - Purdue University

Light Traveling in an Optical Medium (3)

• So the frequency of light traveling in an optical medium with n >

1 is the same as the frequency of that light traveling in vacuum

• We perceive color by frequency rather than wavelength

• Thus placing an object under water does not change our

perception of the color of the object

• Easy to demonstrate: take a colored object and put it in a jar of

water. Water has index of refraction n = 1.33. The object

appears to have the same color under water as in air

Page 15: Chapter 25 Wave Optics Lecture 19 - Purdue University

Phase Change and Reflection

• When a light wave reflects from a surface it may be

inverted

• Inversion corresponds to a phase change of 180°

• There is a phase change whenever the index of

refraction on the incident side is less than the index

of refraction of the opposite side

• If the index of refraction is larger on the incident side

the reflected ray is not inverted and there is no

phase change

Section 25.3

Page 16: Chapter 25 Wave Optics Lecture 19 - Purdue University

Phase Change and Reflection, Diagram

Section 25.3

Page 17: Chapter 25 Wave Optics Lecture 19 - Purdue University

Phase Changes in a Thin Film

• The total phase change in a thin film must be

accounted for

• The phase difference due to the extra distance

traveled by the ray

• Any phase change due to reflection

• For a soap film on glass, nair < nfilm < nglass

• There are phase changes for both reflections at the

soap-film interfaces

• The reflections at both the top and bottom surfaces

undergo a 180° phase change no phase change !

• The nature of the interference is determine only by

the extra path length

Section 25.3

Page 18: Chapter 25 Wave Optics Lecture 19 - Purdue University

Thin-Film Interference (1)

• Assume a thin soap film rests on a flat glass

surface (Fig. A and Fig. B)

• The upper surface of the soap film is similar to

the beam splitter in the interferometer

• It reflects part of the incoming light and allows the

rest to be transmitted into the soap layer after

refraction at the air-soap interface Section 25.3

Page 19: Chapter 25 Wave Optics Lecture 19 - Purdue University

Thin-Film Interference (2)

• The transmitted ray is partially reflected at the bottom

surface

• The two outgoing rays meet the conditions for interference

• They travel through different regions

• One travels the extra distance through the soap film

• They recombine when they leave the film

• They are coherent because they originated from the same

source and initial ray Section 25.3

Page 20: Chapter 25 Wave Optics Lecture 19 - Purdue University

Thin-Film Interference (3), nair < nfilm > nair

• Assume the soap bubble is

surrounded by air

• There is a phase change at the top

of the bubble

• There is no phase change at the

bottom of the bubble

• Since only one wave undergoes a

phase change, the interference

conditions are

film

film

m

d constructive interferencen

md destructive interference

n

æ ö+ç ÷

è ø=

=

1

22

2

l

l

Section 25.3

Page 21: Chapter 25 Wave Optics Lecture 19 - Purdue University

Thin-Film Interference (4), White Light

• Each color can interfere

constructively, but at

different angles

• Blue will interfere

constructively at a

different angle than

red

• When you look at the

soap film the white light

illuminates the film over

a range of angles

Section 25.3

Page 22: Chapter 25 Wave Optics Lecture 19 - Purdue University

Thin Film Interference (5) • When light travels from an optical medium with an index of refraction n1 into

a second optical medium with index of refraction n2,

(1) The light can be transmitted through the boundary

no change of the phase of light

(2) The light can be reflected

• If n1 < n2, the phase of the reflected wave will be changed by or

• If n1 > n2 then there will be no phase change

/ 2

Oil floating on water: The color seen corresponds to the

wavelength of light that is interfering constructively

n2

n1

n1

n2

Page 23: Chapter 25 Wave Optics Lecture 19 - Purdue University

• Due to the phase change of 1800, the criterion for

constructive interference is given by

• The minimum thickness tmin that will produce contructive

interference corresponds to (for m=0)

• Note that this result applies only to the case where we

have a material with index of refraction n and air on both

sides, like a soap bubble

min4

airtn

1

2 0, 1, 2,...2

x m t m m m

min min

12 0 4 =

2 4 4

airx m t m t tn

Thin Film Interference (6), nair < nfilm > nair

Page 24: Chapter 25 Wave Optics Lecture 19 - Purdue University

• The criterion for destructive interference is given by

• The minimum thickness tmin that will produce destructive

interference corresponds to (for m=1)

• Note that this result applies only to the case where we

have a material with index of refraction n and air on both

sides, like a soap bubble

min2

airtn

2 , 1 0, 1, 2,...x m t m m m m

1 1 1 2

2 2 2 1

/

/

v c n n

v c n n

2 2, 1

air

air air

n

n n

1 2

1 2

tv v

min min2 1 2 = 2 2

airx m t m t tn

Thin Film Interference (7), nair < nfilm > nair

Page 25: Chapter 25 Wave Optics Lecture 19 - Purdue University

Thin-Film Interference, nair < nfilm > nair

• Equations are

• These equations apply whenever

nair < nfilm > n(substance below the film)

film

film

md constructive interference

n

m

d destructive interferencen

2

1

22

Section 25.3

Page 26: Chapter 25 Wave Optics Lecture 19 - Purdue University

Thin Film Interference (8) - Demo

• The reflected wave undergoes a phase shift

of half a wavelength when it is reflected

because nair < n

• The light that is transmitted has no phase

shift and continues to the back surface of the

film

• At the back surface, again part of the

wave is transmitted and part of the wave is

reflected

• The reflected light has no phase shift because n >

nair and travels back to the front surface of the film

• The transmitted light has traveled a longer distance

than the originally reflected light and has a phase

shift given by the path length difference that is

twice the film thickness t

soap bubble

Page 27: Chapter 25 Wave Optics Lecture 19 - Purdue University

Phase Changes in a Thin Film, nair < nfilm < nglass

• For a soap film on glass, nair < nfilm < nglass

• There are phase changes for both reflections at the

soap-film interfaces

• The reflections at both the top and bottom surfaces

undergo a 180° phase change no phase change

!

• For nair < nfilm < n(substance below the film)

Section 25.3

film

film

md constructive interference

n

m

d destructive interferencen

2

1

22

Page 28: Chapter 25 Wave Optics Lecture 19 - Purdue University

Antireflection Coatings (1)

• Nearly any flat piece of

glass may act like a

partially reflecting mirror

• To avoid reductions in

intensity due to this

reflection, antireflective

coatings may be used

• The coating makes a

lens appear slightly dark

in color when viewed in

reflected light

Section 25.3

Page 29: Chapter 25 Wave Optics Lecture 19 - Purdue University

Antireflective Coatings (2)

• Many coatings are

made from MgF2

• nMgF2 = 1.38

• There is a 180° phase

change at both

interfaces

• Destructive interference

occurs when

Section 25.3

MgF MgF

m

d dn n

2 2

1

22

4

Page 30: Chapter 25 Wave Optics Lecture 19 - Purdue University

• The light transmitted through the

coating has no phase change: When it

is reflected from the lens, it will

undergo a phase change

• the criterion for destructive interference

is

n=1

n=1.38 n=1.51

1

2 0, 1, 2,...2

air

coating

m t m m mn

min

4

air

coating

tn

• Light reflected at the surface of

the coating will undergo a phase

change of half a wavelength

because nair < ncoating

Antireflective Coatings (3) – more details

Page 31: Chapter 25 Wave Optics Lecture 19 - Purdue University

• The criterion for destructive interference is given by

• The minimum thickness tmin that will produce destructive

interference corresponds to (for m=0)

• Note that this result applies to the case where we have a

material with index of refraction n coated on a lens and

air on one side, like a coated lens.

min4

airtn

1

2 0, 1, 2,...2

x m t m m m

min min

12 0 4 =

2 4 4

airx m t m t tn

Antireflective Coatings (4) – more details

Page 32: Chapter 25 Wave Optics Lecture 19 - Purdue University

Summary - Thin-Film Interference

• For nair < nfilm < n(substance below the film)

• For nair < nfilm > n(substance below the film)

Section 25.3

film

film

md destructive interference

n

m

d costructive interferencen

2

1

22

film

film

md constructive interference

n

m

d destructive interferencen

2

1

22

Page 33: Chapter 25 Wave Optics Lecture 19 - Purdue University

Light Through a Single Slit

• Light passes through a slit or opening and then

illuminates a screen

• As the width of the slit becomes closer to the

wavelength of the light, the intensity pattern on the

screen and additional maxima become noticeable

Section 25.4

Page 34: Chapter 25 Wave Optics Lecture 19 - Purdue University

Single-Slit Diffraction

• Water wave example of

single-slit diffraction

• All types of waves

undergo single-slit

diffraction

• Water waves have a

wavelength easily

visible

• Diffraction is the

bending or spreading of

a wave when it passes

through an opening

Section 25.4

Page 35: Chapter 25 Wave Optics Lecture 19 - Purdue University

Huygen’s Principle

• It is useful to draw the

wave fronts and rays for

the incident and

diffracting waves

• Huygen’s Principle

can be stated as all

points on a wave front

can be thought of as

new sources of

spherical waves

Section 25.4