chapter 25 wave optics lecture 19 - purdue university
TRANSCRIPT
Chapter 25 Wave Optics – Lecture 19
25.1 Coherence and Conditions for Interference
25.2 The Michelson Interferometer
25.3 Thin-Film Interference
25.4 Light through a Single-Slit: Qualitative Behavior
25.5 Double-Slit Interference: Young’s Experiment
25.6 Single-Slit Diffraction: Interference of Light frm a Single
Slit
25.7 Diffraction Gratings
25.8 Optical Resolution and Rayleigh Criterion
Wave Optics vs. Geometric Optics
• When discussing image characteristics over
distances much greater than the wavelength,
geometric optics is extremely accurate
• When dealing with sizes comparable to or smaller
than the wavelength, wave optics is required
• Examples include interference effects and propagation
through small openings
Introduction
Interference
• One property unique to waves is interference
• Interference is a wave phenomenon
• Interference of sound waves can be produced by two speakers
Section 25.1
Constructive Interference
• Require the phase difernece of 0,
2, 4 .... or a path difference x given by
+
=
0, 1, 2,...x m m m m
Destructive Interference
• Here the phase difference between the
two waves is radians, 180, or /2
1
0, 1, 2,...2
x m m m m
+
=
Summary - Interference
• If light waves are traveling from some point, then the
phase difference can be related to the path difference between
the two waves
• The criterion for constructive interference is given by a path
difference x given by
• Destructive interference will take place if the path difference x
is a half wavelength plus an integer times the wavelength
• The inter m is called the order of the fringe
0, 1, 2,...x m m m m
1
0, 1, 2,...2
x m m m m
Summary- Interference Conditions
• For constructive interference, Δx = m λ
• For destructive interference, Δx = (m + ½) λ
• m is an integer in both cases
• If the interference is constructive, the light
intensity at the detector is large
• Called a bright fringe
• If the interference is destructive, the light
intensity at the detector is zero
• Called a dark fringe
Section 25.2
Interference
• Sunlight is composed of light containing a broad range
of frequencies and corresponding wavelengths
• We often see different colors
separated out of sunlight by
refraction in rainbows
• We also sometimes see various
colors from sunlight due to
constructive and destructive
interference phenomena on the
surface of DVD’s or CD’s
or in thin layers of oil or water
Michelson Interferometer
• The Michelson
interferometer is based
on the interference of
reflected waves
• Two reflecting mirrors
are mounted at right
angles
• A third mirror is partially
reflecting
• Called a beam splitter
Section 25.2
Michelson Interferometer, cont.
• The incident light hits the beam splitter and is divided
into two waves
• The waves reflect from the mirrors at the top and right
and recombine at the beam splitter
• After being reflected again from the
beam splitter, portions of the waves
combine at the detector
• The only difference between the two
waves is that they travel different
distances between their respective
mirrors and the beam splitter
• The path length difference is
ΔL = 2L2 – 2L1 Section 25.2
Michelson Interferometer, final
• The path length
difference is related to the
wavelength of the light
• If N is an integer, the two
waves are in phase and
produce constructive
interference
• If N is a half-integer the
waves will produce
destructive interference
LN
D=
l
Section 25.2
Measuring Length with a Michelson
Interferometer • Use the light from a laser and adjust the mirror to give
constructive interference
• This corresponds to one of the bright fringes
• The mirror is then moved, changing the path length
• The intensity changes from high to zero and back to high,
every time the path length changes by one wavelength
• If the mirror moves through N bright fringes, the distance
d traveled by the mirror is (for round trip) or N
d =2
l
Section 25.2
• The accuracy of the measurement depends on the
accuracy with which the wavelength is known
• Many laboratories use helium-neon lasers to make very
precise length measurements
d N2
He Ne nm632.99139822
• When a light wave
passes from one
medium to another, the
waves must stay in
phase at the interface
• The frequency must be
the same on both sides
of the interface
Section 25.3
Light Traveling in an Optical Medium (1)
Light Traveling in an Optical Medium (2)
• We have seen that the wavelength of light changes when traveling in an optical medium with index of refraction greater than one
• Taking with case 1 as a vacuum and case 2 as a medium with index of refraction n, we have found out that we can write
• Remembering that v = f we can write the frequency fn of light traveling in a medium as
• So the frequency does not change !
n
v
c n
/ ( / )n
n
v cf v v c f
1 2
1 2
tv v
nf f
Light Traveling in an Optical Medium (3)
• So the frequency of light traveling in an optical medium with n >
1 is the same as the frequency of that light traveling in vacuum
• We perceive color by frequency rather than wavelength
• Thus placing an object under water does not change our
perception of the color of the object
• Easy to demonstrate: take a colored object and put it in a jar of
water. Water has index of refraction n = 1.33. The object
appears to have the same color under water as in air
Phase Change and Reflection
• When a light wave reflects from a surface it may be
inverted
• Inversion corresponds to a phase change of 180°
• There is a phase change whenever the index of
refraction on the incident side is less than the index
of refraction of the opposite side
• If the index of refraction is larger on the incident side
the reflected ray is not inverted and there is no
phase change
Section 25.3
Phase Change and Reflection, Diagram
Section 25.3
Phase Changes in a Thin Film
• The total phase change in a thin film must be
accounted for
• The phase difference due to the extra distance
traveled by the ray
• Any phase change due to reflection
• For a soap film on glass, nair < nfilm < nglass
• There are phase changes for both reflections at the
soap-film interfaces
• The reflections at both the top and bottom surfaces
undergo a 180° phase change no phase change !
• The nature of the interference is determine only by
the extra path length
Section 25.3
Thin-Film Interference (1)
• Assume a thin soap film rests on a flat glass
surface (Fig. A and Fig. B)
• The upper surface of the soap film is similar to
the beam splitter in the interferometer
• It reflects part of the incoming light and allows the
rest to be transmitted into the soap layer after
refraction at the air-soap interface Section 25.3
Thin-Film Interference (2)
• The transmitted ray is partially reflected at the bottom
surface
• The two outgoing rays meet the conditions for interference
• They travel through different regions
• One travels the extra distance through the soap film
• They recombine when they leave the film
• They are coherent because they originated from the same
source and initial ray Section 25.3
Thin-Film Interference (3), nair < nfilm > nair
• Assume the soap bubble is
surrounded by air
• There is a phase change at the top
of the bubble
• There is no phase change at the
bottom of the bubble
• Since only one wave undergoes a
phase change, the interference
conditions are
film
film
m
d constructive interferencen
md destructive interference
n
æ ö+ç ÷
è ø=
=
1
22
2
l
l
Section 25.3
Thin-Film Interference (4), White Light
• Each color can interfere
constructively, but at
different angles
• Blue will interfere
constructively at a
different angle than
red
• When you look at the
soap film the white light
illuminates the film over
a range of angles
Section 25.3
Thin Film Interference (5) • When light travels from an optical medium with an index of refraction n1 into
a second optical medium with index of refraction n2,
(1) The light can be transmitted through the boundary
no change of the phase of light
(2) The light can be reflected
• If n1 < n2, the phase of the reflected wave will be changed by or
• If n1 > n2 then there will be no phase change
/ 2
Oil floating on water: The color seen corresponds to the
wavelength of light that is interfering constructively
n2
n1
n1
n2
• Due to the phase change of 1800, the criterion for
constructive interference is given by
• The minimum thickness tmin that will produce contructive
interference corresponds to (for m=0)
• Note that this result applies only to the case where we
have a material with index of refraction n and air on both
sides, like a soap bubble
min4
airtn
1
2 0, 1, 2,...2
x m t m m m
min min
12 0 4 =
2 4 4
airx m t m t tn
Thin Film Interference (6), nair < nfilm > nair
• The criterion for destructive interference is given by
• The minimum thickness tmin that will produce destructive
interference corresponds to (for m=1)
• Note that this result applies only to the case where we
have a material with index of refraction n and air on both
sides, like a soap bubble
min2
airtn
2 , 1 0, 1, 2,...x m t m m m m
1 1 1 2
2 2 2 1
/
/
v c n n
v c n n
2 2, 1
air
air air
n
n n
1 2
1 2
tv v
min min2 1 2 = 2 2
airx m t m t tn
Thin Film Interference (7), nair < nfilm > nair
Thin-Film Interference, nair < nfilm > nair
• Equations are
• These equations apply whenever
nair < nfilm > n(substance below the film)
film
film
md constructive interference
n
m
d destructive interferencen
2
1
22
Section 25.3
Thin Film Interference (8) - Demo
• The reflected wave undergoes a phase shift
of half a wavelength when it is reflected
because nair < n
• The light that is transmitted has no phase
shift and continues to the back surface of the
film
• At the back surface, again part of the
wave is transmitted and part of the wave is
reflected
• The reflected light has no phase shift because n >
nair and travels back to the front surface of the film
• The transmitted light has traveled a longer distance
than the originally reflected light and has a phase
shift given by the path length difference that is
twice the film thickness t
soap bubble
Phase Changes in a Thin Film, nair < nfilm < nglass
• For a soap film on glass, nair < nfilm < nglass
• There are phase changes for both reflections at the
soap-film interfaces
• The reflections at both the top and bottom surfaces
undergo a 180° phase change no phase change
!
• For nair < nfilm < n(substance below the film)
Section 25.3
film
film
md constructive interference
n
m
d destructive interferencen
2
1
22
Antireflection Coatings (1)
• Nearly any flat piece of
glass may act like a
partially reflecting mirror
• To avoid reductions in
intensity due to this
reflection, antireflective
coatings may be used
• The coating makes a
lens appear slightly dark
in color when viewed in
reflected light
Section 25.3
Antireflective Coatings (2)
• Many coatings are
made from MgF2
• nMgF2 = 1.38
• There is a 180° phase
change at both
interfaces
• Destructive interference
occurs when
Section 25.3
MgF MgF
m
d dn n
2 2
1
22
4
• The light transmitted through the
coating has no phase change: When it
is reflected from the lens, it will
undergo a phase change
• the criterion for destructive interference
is
n=1
n=1.38 n=1.51
1
2 0, 1, 2,...2
air
coating
m t m m mn
min
4
air
coating
tn
• Light reflected at the surface of
the coating will undergo a phase
change of half a wavelength
because nair < ncoating
Antireflective Coatings (3) – more details
• The criterion for destructive interference is given by
• The minimum thickness tmin that will produce destructive
interference corresponds to (for m=0)
• Note that this result applies to the case where we have a
material with index of refraction n coated on a lens and
air on one side, like a coated lens.
min4
airtn
1
2 0, 1, 2,...2
x m t m m m
min min
12 0 4 =
2 4 4
airx m t m t tn
Antireflective Coatings (4) – more details
Summary - Thin-Film Interference
• For nair < nfilm < n(substance below the film)
• For nair < nfilm > n(substance below the film)
Section 25.3
film
film
md destructive interference
n
m
d costructive interferencen
2
1
22
film
film
md constructive interference
n
m
d destructive interferencen
2
1
22
Light Through a Single Slit
• Light passes through a slit or opening and then
illuminates a screen
• As the width of the slit becomes closer to the
wavelength of the light, the intensity pattern on the
screen and additional maxima become noticeable
Section 25.4
Single-Slit Diffraction
• Water wave example of
single-slit diffraction
• All types of waves
undergo single-slit
diffraction
• Water waves have a
wavelength easily
visible
• Diffraction is the
bending or spreading of
a wave when it passes
through an opening
Section 25.4
Huygen’s Principle
• It is useful to draw the
wave fronts and rays for
the incident and
diffracting waves
• Huygen’s Principle
can be stated as all
points on a wave front
can be thought of as
new sources of
spherical waves
Section 25.4