chapter 2 kinematics in one dimension. mechanics: study of motion in relation to force and energy,...
TRANSCRIPT
![Page 1: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/1.jpg)
Chapter 2
Kinematics in One Dimension
![Page 2: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/2.jpg)
Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of an object.
Kinematics – Mechanics that describes how an object moves, no reference to the cause (force) or mass of the object. [Gk: kinema = movement].
Dynamics– Mechanics that deals with force: why objects move.
![Page 3: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/3.jpg)
• To describe motion of an object, we need to specify its position, displacement, velocity and acceleration.
• Chap 2: Motion in one dimension only – along a straight line.
• Horizontal direction: position = x, displacement x, velocity vx, acceleration ax.
• Vertical direction: position = y, displacement y, velocity vy, acceleration ay.
• Chap 4 will discuss kinematics in 2-dimension [circular motion, projectile motion].
Introduction
![Page 4: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/4.jpg)
0 x
+
- +
-
y
![Page 5: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/5.jpg)
0 x
+
- +
-
y
![Page 6: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/6.jpg)
• Consider a car driven at a perfectly steady 60 miles per hour on a long and straight section of the highway.
• In the first hour it will travel 60 mi. In the second hour it will cover another 60 mi. etc. We say the car is moving with uniform motion.
Uniform Motion
![Page 7: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/7.jpg)
Uniform Motion
Uniform motion is a straight line motion where:
• Equal displacements are covered in any successive equal intervals of time.
• The velocity is constant.
• The graph of position versus time is a straight line.
![Page 8: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/8.jpg)
Uniform Motion
t
x
x
x
1 2 3 4
60
120
180
240
00
position
velocity
t
v
1 2 3 4
20
40
60
80
00
![Page 9: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/9.jpg)
Non-uniform Motion• An object in non-uniform motion – means
velocity does not stay uniform (constant) during the motion.
• Either its magnitude or direction changes.
• Moving along a straight line with varying speed, or moving along a curved path.
x(t)
t t
v(t)
![Page 10: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/10.jpg)
Average Velocity
• Velocity is the rate of change of position with time.
• The average velocity is displacement divided by the change in time.
vave = x/t
vave = slope of position vs time graph
vave = (xf – xi)/(tf – ti)x
t
x
t
![Page 11: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/11.jpg)
• Instantaneous velocity is the limit of average velocity as t gets small.
• It is the slope of the tangent line to the graph of x(t) versus t.
• It is the derivative of x(t) with respect to t.
dt
dx
t
xlimv
0Δtinst
Instantaneous Velocity
dt
dg
dt
dfg)(f
dt
d
nctdt
df(t)then,ctf(t) If 1nn
![Page 12: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/12.jpg)
Graphs for Instantaneous Velocity
x
tt1 t3
v3>0
v1<0
v2=0
t2
![Page 13: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/13.jpg)
Determine the velocity of the car at times A, B, C and D.
A Positive Zero Negative
B Positive Zero Negative
C Positive Zero Negative
D Positive Zero Negative
x(t)
t
A
B C D
![Page 14: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/14.jpg)
To find position from velocity
f
i
t
t
if
0Δtinst
vdtxx
t
xlim vFrom
dt
dx
xf = xi + Area under velocity-time curve between ti and tf
Final position:
![Page 15: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/15.jpg)
The position of an object changes with time according to the expression
x = t2 + 3t - 9
(a) What is the velocity of the object at t = 3 s?
(b) What is the position of the object when its velocity is 11 m/s?
Example
![Page 16: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/16.jpg)
Area Under velocity-time Graph
Area under the velocity-time graph = magnitude of the displacement over the time interval.
time (s)
velo
city
(m
/s)
uniform (constant) velocity
t1 t2
Area = v(t2-t1) = (x2 – x1) = x
time (s)
velo
city
(m
/s)
![Page 17: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/17.jpg)
Example
A sprinter starts from rest and runs with a constant acceleration for 6 s before reaching his maximum speed. He then runs at the maximum speed the rest of the way. If he ran the 200 m in 25.0 s, at what speed did he cross the finish line?
![Page 18: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/18.jpg)
Average acceleration =t
v a ave
Motion with Constant Acceleration
• Constant acceleration – straight line motion where the speed changes at a constant rate.
• A car moving north. At time t=2sec, its speed is 4 m/s. At t=4 sec, its speed is 8 m/s. At t=6 sec, its speed is 12 m/s. Every 2 sec, its speed changes by 4 m/s. OR, every 1 sec, its speed changes by 2 m/s. It is moving with constant acceleration:
a = 2 m/s/s = 2 m/s2 north.
• Uniformly accelerated motion – when an object moves with constant acceleration.
![Page 19: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/19.jpg)
Uniform (Constant) Acceleration
• An object moving with uniform acceleration – means acceleration stays uniform (constant) throughout the motion.
• Its magnitude and direction stays the same.
• Its velocity changes uniformly.
• Moving along a straight line.
a = slope
t
a(t)v(t)
t
v
t
![Page 20: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/20.jpg)
Graphical Representationve
loci
ty, v
(m
/s)
Time, t (s)
Slope of the line = average acceleration
O
If the slope is zero, the object is moving with zero acceleration (constant velocity)
![Page 21: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/21.jpg)
Motion with Constant Acceleration
t
v
a = slope of the velocity-time graph
T/F? If the acceleration of an object is zero, it must be at rest.
T/F? If an object is at rest, its acceleration must be zero.
a<0
a>0
![Page 22: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/22.jpg)
![Page 23: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/23.jpg)
Slope of the line = average acceleration = v/t
velo
city
, v
(m/s
)
Time, t (s)O
A B
C D
E
1. When is a = 0?
2. When is a < 0?
3. When is a = maximum?
(A) OA
(B) AB
(C) BC
(D) CD
(E) DE
![Page 24: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/24.jpg)
Kinematic Equations for Const. Acceleration
Consider an object moving with constant acceleration a.
As the object moves, its velocity changes.
a aTime = 0
Initial position = xi
Initial velocity = vi
Time = t
Final position = xf
Final velocity = vf
vi vf
a
![Page 25: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/25.jpg)
Kinematic Equations for Const. Acceleration
• aave = ainst
• Initial time = ti , final time = tf Time interval = t = tf - ti
• Initial position = xi , final position = xf
Displacement x = xf - xi
• Initial velocity = vi , final velocity vf
Change in velocity v = vf - vi
Uniformly accelerated motion: a = const.
![Page 26: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/26.jpg)
Kinematic Equations for Constant Acceleration
vf = vi + atxf = xi +vit + ½at2
vf2 = vi
2 + 2axAverage velocity vave = (vi + vf)/2
Uniformly accelerated motion: a = constant.
Time: Initial = ti, final = tf
Positions: Initial = xi, final = xf Velocity: Initial = vi, final = vf
![Page 27: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/27.jpg)
Example
A train traveling at a constant speed of 22 m/s, comes to an incline with a constant slope. While going up the incline the train slows down with a constant acceleration of magnitude 1.4 m/s2.
• Draw a graph of vx versus t.
• What is the speed of the train after 8.0s on the incline?
• How far has the train traveled up the incline after 8.0 s?
![Page 28: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/28.jpg)
Free Fall• Free fall: Only force of gravity acting on an
object making it fall.
• Effect of air resistance is negligible. Motion in vacuum.
• Motion of objects in air where air resistance is negligible (not feather).
• Force of gravity acting on an object near the surface of the earth is F = W = mg.
• Acceleration of any object in free fall:
a = 9.8 m/s2 down (ay = -9.8 m/s2).
• g = 9.8 m/s2 hence ay = -g
![Page 29: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/29.jpg)
Free Fall
+y
+x
ay = -9.8 m/s2
ax = 0
![Page 30: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/30.jpg)
Free Fall contd…
1. ay = -g, regardless of mass of object.
![Page 31: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/31.jpg)
2. ay = -g, regardless of initial velocity
+y
+x
ay = -9.8 m/s2, ax = 0
v0 = 0 v0 = -15 m/s v0 = +15 m/s
![Page 32: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/32.jpg)
3. Free Fall: Motion is symmetric.
+y
+x
ay = -9.8 m/s2, ax = 0
v0 = +5 m/s
At the maximum height:
• vy = 0
• Speed at equal heights will be equal.
• Equal time going up and down.
![Page 33: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/33.jpg)
Example:
A stone is launched straight up by a slingshot. Its initial speed is 19.6 m/s and the stone is 1.5 m above the ground when launched.
(a) How high above the ground does the stone rise?
(b) How much time elapses before the
stone hits the ground?
![Page 34: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/34.jpg)
In the figure above showing a graph of position (x) versus time (t), when is the object
(A) at rest?
(B) moving to the left?
(C) moving fastest?
(D) moving slowest?
![Page 35: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/35.jpg)
A car moves at a constant velocity of magnitude 20 m/s. At time t = 0, its position is 50 m from a reference point. What is its position at
(i) t = 2s? (ii) t = 4s (iii) t = 10s?
Example
![Page 36: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/36.jpg)
A stray dog ran 3 km due north and then 4 km due east. What is the magnitude of its average velocity if it took 45 min?
Example
![Page 37: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/37.jpg)
Which position-versus-time graph represents the motion shown in the motion diagram?
![Page 38: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/38.jpg)
Which position-versus-time graph goes with the velocity-versus-time graph at the top? The particle’s position at ti = 0 s is xi = –10 m.
![Page 39: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/39.jpg)
• The average acceleration is the change in velocity divided by the change in time.
• SI unit = m/s2
• Slope of velocity-time graph.
t
v
tt
vv
tt
vv
timeinchange
velocityinchangea
ifif
if
12
t
v(t)
t
vA
C
EB
D
Acceleration (a)
![Page 40: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/40.jpg)
The instantaneous acceleration as at a specific instant of time t is given by the derivative of the velocity
Instantaneous Acceleration
![Page 41: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/41.jpg)
To find velocity from acceleration
f
i
t
t
instif
0Δtinst
dtavv
t
vlima From
dt
dv
vf = vi + Area under acceleration-time curve between ti and tf
OR graphically:
If we know the initial velocity, vi, and the instantaneous acceleration, ainst, as a function of time, t, then the final velocity can be obtained:
![Page 42: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/42.jpg)
Finding velocity from acceleration
![Page 43: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/43.jpg)
Finding velocity from acceleration
![Page 44: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/44.jpg)
Example
The velocity of an object varies as
v(t) = 2t2 - 10t + 18
(a)Find the acceleration of the object at t = 3 s
(b) At what time is the velocity of the object 9 m/s
(c) What is the displacement of the object from t = 0s to t = 2s?
![Page 45: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/45.jpg)
A car moving south slows down with at a constant acceleration of 3.0 m/s2. At t = 0, its velocity is 26 m/s. What is its velocity at t = 3 s?
A. B. C. D. E.
0% 0% 0%0%0%
A. 35 m/s south
B. 17 m/s south
C. 23 m/s south
D. 29 m/s south
E. 17 m/s north
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
61 62 63 64 65
![Page 46: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/46.jpg)
A car initially traveling at 18.6 m/s begins to slow down with a uniform acceleration of 3.00 m/s2. How long will it take to come to a stop?
A. B. C. D. E.
0% 0% 0%0%0%
A. 55.8 s
B. 15.6 s
C. 6.20 s
D. 221.6 s
E. None of these
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
61 62 63 64 65
![Page 47: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/47.jpg)
A ball is kicked straight up from ground level with initial velocity of 22.6 m/s. How high above the ground will the ball rise?
A. B. C. D. E.
5% 3%8%
73%
13%
A. 9.8 m
B. 3.00 m
C. 1.15 m
D. 26.1 m
E. 19.6 m
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55
![Page 48: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/48.jpg)
A ball is kicked straight up from ground level with initial velocity of 22.6 m/s. How high above the ground will the ball rise?
A. B. C. D. E.
8% 8%10%
69%
5%
A. 9.8 m
B. 3.00 m
C. 1.15 m
D. 26.1 m
E. 19.6 m
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
61 62 63 64 65
![Page 49: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/49.jpg)
1. A car initially traveling at a velocity vo begins to slow down with a uniform deceleration of 1.20 m/s2 and comes to a stop in 26.0 seconds. Determine the value of vo.
A. B. C. D. E.
95%
5%0%0%0%
A. 31.2 m/s
B. 21.7 m/s
C. 27.2 m/s
D. 24.8 m/s
E. None of these
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
61 62 63 64 65
![Page 50: Chapter 2 Kinematics in One Dimension. Mechanics: Study of motion in relation to force and energy, ie, the effects of force and energy on the motion of](https://reader035.vdocuments.us/reader035/viewer/2022062421/56649e0c5503460f94af5c51/html5/thumbnails/50.jpg)
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60
61 62 63 64 65
The minimum stopping distance for a car traveling at a speed of 30 m/s is 60 m, including the distance traveled during the driver’s reaction time of 0.5 s. What is the minimum stopping distance for the same car traveling at a speed of 40 m/s?
Example