chapter 2: energy and the 1st law of...
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Chapter 2 Energy and the 1st Law of Thermodynamics
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Dr. Mohammad Suliman Abuhaiba, PE 1
Homework Assignment # 2
Problems: 1, 7, 14, 20, 30, 36,
42, 49, 56
Design and open end
problem: 2.1D
Due Monday 22/12/2014
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Dr. Mohammad Suliman Abuhaiba, PE
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Work and Kinetic Energy
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Potential Energy
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Conservation of Energy in Mechanics
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Broadening Our Understanding of Work
Thermodynamic definition of work: Work is done by a system on its
surroundings if the sole effect on
everything external to the system
could have been the raising of a
weight.
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Modeling Expansion or
Compression Work
dVp
V
V
2
1
Work is process (path)
dependent, and is NOT a
property of the system
Expansion / Compression
Work (Moving Boundary
Work)
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Sign Convention – Work
W > 0: Work done by system
W < 0: Work done on system
Power: Time rate of work
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Example 2.1
A gas in a piston–cylinder assembly
undergoes an expansion process for which
the relationship between pressure &
volume is given by p.Vn = Constant.
The initial pressure is 3 bar, the initial volume
is 0.1 m3, and the final volume is 0.2 m3.
Determine the work for the process, in kJ, if
a. n = 1.5
b. n = 1.0
c. n = 0
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Broadening Our
Understanding of Energy
Mechanical Energy: KE, PE, E
Work is done by energy transfer
Heat is another form of energy
Expand the conservation of energy
principle to accommodate thermal
systems.
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Broadening Our
Understanding of Energy In engineering TD change in total energy of a system
is made up of three macroscopic contributions:
1. change in kinetic energy, associated with motion
of system as a whole relative to an external
coordinate frame.
2. change in gravitational potential energy,
associated with position of system as a whole in
the earth’s gravitational field.
3. All other energy changes are lumped together in
the internal energy of the system. internal energy
is an extensive property of the system.
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Common Units: J(N·m) or kJ, ft·lbf, Btu
)(2
1 2
1
2
2 VVmKE
)( 12 zzgmPE
Kinetic Energy
Potential Energy
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Broadening Our
Understanding of Energy
Total Energy: An extensive property of a
system
Kinetic Energy (Mechanical)
Potential Energy (Mechanical)
Internal Energy: U or u
• Represents all other forms of energy
• Includes all microscopic forms of energy
E KE PE U
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Broadening Our
Understanding of Energy
Microscopic Interpretation of Internal Energy
Consider a system consisting of a gas contained
in a tank.
Think about the energy attributed to motions and
configurations of individual molecules, atoms,
and subatomic particles making up the matter in
the system
Gas molecules move about, encountering other
molecules or walls of container.
Part of internal energy of gas is translational
kinetic energy of molecules.
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Microscopic Interpretation of Internal Energy
kinetic energy due to rotation of molecules
relative to their centers of mass & kinetic energy
associated with vibrational motions within
molecules.
energy is stored in chemical bonds between
atoms that make up the molecules.
Energy storage on the atomic level includes
energy associated with electron orbital states,
nuclear spin, and binding forces in the nucleus.
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Sign Convention,
Notation, and Heat Transfer Rate
Q > 0: Heat transfer
into the system
Q < 0: Heat transfer
out of the system
Rate of heat
transfer:
Q
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Energy Transfer by Heat
Heat Transfer Modes
Conduction
Radiation
Emissivity, e, is a property of surface that
indicates how effectively the surface
radiates (0< e <1.0)
s = Stefan–Boltzmann constant
x
dTQ A
dx
4
beQ ATes
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Heat Transfer Modes
Convection ( )b fcQ hA T T
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1st Law of Thermodynamics
Consider a system of a
piston and cylinder with an
enclosed dilute gas
characterized by P,V,T & n.
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What happens to
the gas if the piston
is moved inwards?
1st Law of Thermodynamics
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If the container is
insulated the
temperature will rise,
the atoms move faster
and the pressure rises.
Is there more internal
energy in the gas?
1st Law of Thermodynamics
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External agent did
work in pushing the
piston inward.
W = Fd = (PA)x
W = PV
x
1st Law of Thermodynamics
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Work done on the
gas equals the
change in the gases
internal energy,
W = U
x
1st Law of Thermodynamics
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Let’s change the situation:
Keep the piston fixed at its original location.
Place the cylinder on a hot plate.
What happens to gas?
1st Law of Thermodynamics
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Heat flows into the gas.
Atoms move faster, internal
energy increases.
Q = heat in Joules
U = change in internal
energy in Joules.
Q = U
1st Law of Thermodynamics
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What if we added
heat and pushed
the piston in at the
same time?
F
1st Law of Thermodynamics
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Work is done on the
gas, heat is added to
the gas and the
internal energy of the
gas increases!
Q = W + U
F
1st Law of Thermodynamics
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For the gases perspective:
heat added is positive, heat
removed is negative.
Work done on gas is positive, work
done by the gas is negative.
Temperature increase means internal
energy change is positive.
1st Law of Thermodynamics
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Conservation of Energy: 1st Law
of Thermodynamics
KE PE U Q W
Change in amount
of energy contained
within the system
during some time
interval =
Net amount of
energy transferred
in across the
system boundary
by heat transfer
during the time
interval
-
Net amount of
energy transferred
out across the
system boundary
by work during the
time interval
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Alternative Forms of the Energy
Balance
Differential Form:
dE Q W
dEQ W
dt
Time Rate Form:
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Example 2.2 Cooling a Gas in a Piston–Cylinder
Four kilograms of a certain gas is contained within
a piston–cylinder assembly. The gas undergoes a
process for which the pressure–volume relationship
is pV1.5 = constant . The initial pressure is 3 bar, the
initial volume is 0.1 m3, and the final volume is 0.2
m3. The change in specific internal energy of the
gas in the process is u2 - u1 = - 4.6 kJ/kg. There are
no significant changes in kinetic or potential
energy. Determine the net heat transfer for the
process, in kJ.
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Example 2.3 Considering Alternative Systems
Air is contained in a vertical piston–cylinder assembly fitted with
an electrical resistor. The atmosphere exerts a pressure of 1 bar
on the top of the piston, which has a mass of 45 kg and a face
area of .09 m2. Electric current passes through the resistor, and the volume of the air slowly increases by .045 m3 while its
pressure remains constant. The mass of the air is 0.27 kg, and its
specific internal energy increases by 42 kJ/kg. The air and piston
are at rest initially and finally. The piston–cylinder material is a ceramic composite and thus a good insulator. Friction between
the piston and cylinder wall can be ignored, and the local
acceleration of gravity is g 9.81 m/s2. Determine the heat
transfer from the resistor to the air, in kJ, for a system consisting of
a. the air alone
b. the air and the piston
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Example 2.4 Gearbox at Steady State During steady-state operation, a gearbox receives
60 kW through the input shaft and delivers power
through the output shaft. For the gearbox as the
system, the rate of energy transfer by convection is
where h = 0.171 kW/m2 K is the heat transfer
coefficient, A =1.0 m2 is outer surface area of
gearbox, Tb = 300 K is the temperature at the outer
surface, and Tf = 293 K is the temperature of the
surrounding air away from the immediate vicinity of
the gearbox. For the gearbox, evaluate the heat
transfer rate and power delivered through the
output shaft, each in kW.
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Example 2.5 Silicon Chip at Steady State
A silicon chip measuring 5 mm on a side and 1
mm in thickness is embedded in a ceramic
substrate. At steady state, the chip has an
electrical power input of 0.225 W. The top
surface of the chip is exposed to a coolant whose temperature is 20°C. The heat transfer
coefficient for convection between the chip
and the coolant is 150 W/m2 K. If heat transfer
by conduction between the chip and the
substrate is negligible, determine the surface temperature of the chip, in °C.
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Example 2.6 Transient Operation of a Motor
The rate of heat transfer between a certain
electric motor and its surroundings varies with time
as , where t is in seconds and is
in kW. The shaft of the motor rotates at a constant
speed of 100 rad/s and applies a constant torque
of 18 N.m to an external load. The motor draws a
constant electric power input equal to 2.0 kW. For
the motor, plot , each in kW, and the
change in energy E, in kJ, as functions of time from
t = 0 to t = 120 s. Discuss.
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Cycle Analysis
Power Cycles
Refrigeration & Heat
Pump Cycles
cycle cycle cycleE Q W cycle cycleQ W
cycle
in
W
Q
in
cycle
Q
W
out
cycle
Q
W
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