chapter 1.6 probability

9
Chapter 1.6 Probability Objective: Students set up probability equations appropriately

Upload: rowan-mcconnell

Post on 30-Dec-2015

28 views

Category:

Documents


0 download

DESCRIPTION

Chapter 1.6 Probability. Objective: Students set up probability equations appropriately. Experimental Probability. Probability of event = Number of times event occurs Number of trials. Example 1. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Chapter 1.6 Probability

Chapter 1.6 Probability

Objective: Students set up probability equations appropriately

Page 2: Chapter 1.6 Probability

Experimental Probability

Probability of event =

Number of times event occurs

Number of trials

Page 3: Chapter 1.6 Probability

Example 1

A player hit the bull’s eye on a circular dartboard 8 times out of 50. Find the experimental probability that the player hits the bull’s eye.

Page 4: Chapter 1.6 Probability

We need to use the formula.

Number of times event occurs =

Number of trials

816%

50

Page 5: Chapter 1.6 Probability

Example 2

Find the theoretical probability of rolling a multiple of 3 with a number cube? How about rolling an odd?

The Cube is a normal six sided di.

Page 6: Chapter 1.6 Probability

A) How many numbers on the cube are a multiple of 3? Yes 2 numbers, 3 and 6.

So we get… 2 = 1 6 3 B) How many numbers are odd?

Yes 3 numbers, 1,3,5

So we get… 3 = 1 6 2

Page 7: Chapter 1.6 Probability

Example 3 Suppose that all the points on the circular

dartboard shown below are equally likely to be hit by a dart you have thrown. Find the probability of only scoring 2 points with one throw.

Note: The radius of each circle is one unit larger than the one below it. 2020

1052

Experimental Probability

Page 8: Chapter 1.6 Probability

First we need to find the area of the whole dart board. This is the denominator because any throw can hit any where on the dart board.

To find the area of the green we need to subtract the areas of the others. So we get (using area πr2 of a circle)

π(4r)2 – π(3r)2

π(4r)2

= 16πr2 - 9πr2

16πr2 = 7πr2 16πr2

202010

52

7

16

Page 9: Chapter 1.6 Probability

P. 42 (1- 19) oddOmit 3 and 5