chapter 14

30
Chapter 14 Chemical Kinetics

Upload: lluvia

Post on 14-Jan-2016

46 views

Category:

Documents


0 download

DESCRIPTION

Chapter 14. Chemical Kinetics. What does ‘kinetics’ mean?. What can make a reaction speed up or slow down? Chemical nature / contact ability (solids / liquids / gases) Concentration Temperature Presence of a Catalyst - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Chapter 14

Chapter 14

Chemical Kinetics

Page 2: Chapter 14

What does ‘kinetics’ mean?

Page 3: Chapter 14

Factors governing reaction rates: What can make a reaction speed up or slow down?

Chemical nature / contact ability (solids / liquids / gases)

Concentration

Temperature

Presence of a Catalyst

Consider a mixture of gaseous molecules A and B in a sealed container. A and B react with each other; what will happen to the reaction rate if the pressure in the container increases?

Page 4: Chapter 14

The Reaction Rate How fast are products formed / reactants used up? Reaction of A (red) B (blue) Reaction rate = concentration / time Units of rate?

Page 5: Chapter 14

Calculating Average Rates

Average rate of disappearance of A over 20 s?

Average rate of formation of B over 40 s?

Page 6: Chapter 14

Instantaneous Rates Look at the rate of a reaction over time:

C4H9Cl (aq) + H2O (l) C4H9OH (aq) + HCl (aq)

Is the rate constant?

Tangent lines show therates at specified times(instantaneous rates)

What is the instantaneous rate at t=600s?

Units of rate?

Page 7: Chapter 14

Instantaneous Rates Looked at one component of a reaction

Rate expression that includes all reactants

A + B Products

Rate [A]m [B]n (exponents m and n determined experimentally- look at very soon)

Rate Law: Shows how initial reaction rate changes wrt concentration of species involved; introduces rate constant, k

Rate = k [A]m[B]n

Calculate rate with k, m and n (any concentration of A and B)

Page 8: Chapter 14

Reaction Rates and Stoichiometry C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(g)

propane

In a particular experiment, rate of loss of C3H8 is 3.55 x 10-3 mol / L.s

How can we calculate the corresponding rate of formation of CO2?

Rate of formation of H2O?

Page 9: Chapter 14

Reaction Rates and Stoichiometry

Dinitrogen pentoxide (N2O5) decomposes to NO2 and O2 (all are gases). Balanced equation for this?

Rate of decomposition of N2O5 at a particular instant is 4.2 x 10-7 M/s – what are the rates of formation of NO2 and O2?

Page 10: Chapter 14

The Rate Law

Rate potentially depends on both [NH4+] and [NO2

-]

Rate Law: Rate = k [NH4+]x [NO2

-]y

x and y (exponents): indicate how the initial rate is affected by change in concentration of the reactants. Can be determined.

k = Rate constant (shows how temperature affects rate)

NH4+(aq) + NO2

-(aq) N2(g) + 2H2O(l)

Page 11: Chapter 14

Exponents and Rate Laws A + B C; Rate = k[A]n[B]m; values of n and m?

Vary concs. of A and B separately, and observe effect on rate.

Expt. # Initial Concs (mol/L) Initial Rate (mol L-1 s-1)[A] [B]

1 0.10 0.10 4.0 x 10-5

2 0.10 0.20 4.0 x 10-5

3 0.20 0.10 16.0 x 10-5

Rate Law: Rate = k

What is the value of the rate constant? (remember units!)

What is the rate of the reaction when [A] = 0.050 M, and [B] = 0.010 M?

Page 12: Chapter 14

What is the rate law? Consider the reaction of nitric oxide with hydrogen:

2 NO(g) + 2H2(g) N2(g) + 2H2O(g)

Expt. # Initial Concs (mol/L) Initial Rate (mol L-1 s-1)

[NO] [H2]

1 0.10 0.10 1.23 x 10-3

2 0.10 0.20 2.46 x 10-3

3 0.20 0.10 4.92 x 10-3

(a) What is the rate law for this reaction?

(b) Calculate the rate constant.

(c) Calculate the rate when [NO]=0.050 M and [H2] = 0.150 M.

Page 13: Chapter 14

The rate constant, k

Let’s compare the rate constants (and their units) for the previous two problems just worked.

What do you notice about the two that looks a little odd?

Page 14: Chapter 14

The Integrated Rate Law Rate Law: Shows how initial rate varies with concentration.

Integrated Rate Law: Shows what the concentration of products or reactants is at a particular time during the reaction.

1st order reactions: Rate = - [A] / t = k [A]

ln [A]t = -kt + ln[A]o

2N2O5 2N2O4 + O2; Rate = k[N2O5] At 45 °C, k = 6.22 x 10-4 s-1. If initial conc. Of N2O5 is 0.10M,

how many minutes for [N2O5] to drop to 0.01 M?

Page 15: Chapter 14

Integrated Rate Law – 2nd order 2nd order reactions; Rate = - [A] / t = k [A]2

1/ [A]t = kt + 1/[A]o

Decomposition of NO2(g) NO(g) + ½ O2(g)

2nd order in NO2, with k = 0.543 L / mol.s. [NO2]o = 0.050 M

What is the remaining concentration after 0.500 h?

Page 16: Chapter 14

Graphical representations How to tell if a reaction is 1st order:

Insert Figure 14.8

Page 17: Chapter 14

Graphical Representations How to tell if a reaction is 2nd order:

Page 18: Chapter 14

Half-life (t1/2) – 1st order reactions Half-life of a particular chemical t for ½ reactant to disappear 3g A

t1/2 = 0.693 / k

Page 19: Chapter 14

Half-life (t1/2) – 1st order reactions t1/2 = 0.693 / k

131I; t1/2 = 8 days. 10g sample of 131I, after 8 days….decayed down to….

Radioactive emission (-, -, -, X-rays) to stable isotope

Fraction of 131I present after 24 days? Amount of 131I?

Page 20: Chapter 14

Half-life (t1/2) – 2nd order reactions t1/2 = 1/ k[A]o

2HI(g) I2(g) + H2(g); Rate = k[HI]2; k = 0.079 Lmol-1 s-1

Initial conc. of HI = 0.050M; t1/2 = ?

Page 21: Chapter 14

Temperature and Rate

Value of k varies with change in T

Light sticks in hot vs. ice water

Page 22: Chapter 14

How do reactions occur? Model for Chemical Kinetics Collision Model (Collision Theory) Molecules must successfully collide to react.

2 reasons for ineffective collisions:

1. Insufficient K.E to overcome Ea (Activation Energy) barrier

2. Orientation issues

Page 23: Chapter 14

Orientation Issues

Cl + NOCl NO + Cl2

Page 24: Chapter 14

Activation Energy (Ea)

Page 25: Chapter 14

Activation Energy (Ea) Changing T changes rate; also changes k Extent of k variation with T depends on Ea.

To calculate Ea for a reaction:

ln (k1/k2) = -Ea/RT (1/T2 – 1/T1)

Decomposition of HI has rate constants: k = 0.079 L mol-1 s-1 at 508 °C k = 0.24 L mol-1 s-1 at 540 °C What is the Ea for the reaction, in kJ / mol?

Page 26: Chapter 14

The Reaction Mechanism What happens during a chemical reaction?

NO(g) + O3(g) NO2(g) + O2(g)

Occurs in a single step. Rate Law = k

This is an elementary reaction

What is the molecularity of this elementary reaction?

NO(g) + Cl2(g) NOCl(g) + Cl(g)

Page 27: Chapter 14

The Reaction Mechanism Multi-Step Reactions

NO2(g) + CO(g) NO(g) + CO2(g) Rate = k[NO2]2; Single step?

Possible Mechanism:

Step 1: NO2(g) + NO2(g) NO3(g) + NO(g)

Step 2: NO3(g) + CO(g) NO2(g) + CO2(g)

If mechanism is correct, Step 1 + Step 2 = overall reaction

Intermediates?

Rate Determining Step?

Page 28: Chapter 14

Mechanism problem Decomposition of N2O (nitrous oxide) occurs by a 2-step

mechanism:

Step 1: N2O(g) N2(g) + O(g) (slow)

Step 2: N2O(g) + O(g) N2(g) + O2(g) (fast)

What is the overall equation for the reaction?

Write the rate law for the reaction.

Page 29: Chapter 14

Catalysts Change rates of reactions without being used up Lowers activation energy of reaction (changing mechanism)

Homogeneous catalysts Heterogeneous catalysts

Page 30: Chapter 14

Catalytic Convertors