chapter 13 gases chemistry b2a. gases t ↑ move faster kinetic energy ↑
TRANSCRIPT
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Chapter 13
Gases
Chemistry B2A
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Gases
T ↑ move fasterKinetic energy ↑
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Gases
Physical sate of matter depends on:
Keeps molecules apartBrings molecules together
Attractive forces Kinetic energy
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Gases
Gas High kinetic energy (move fast)
Low attractive forces
Liquid Medium kinetic energy (move slow)
medium attractive forces
Solid Low kinetic energy (move slower)
High attractive forces
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Melting
Boiling
Physical Changes
Change of states
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Ideal Gases
Kinetic molecular theory:
1. Particles move in straight lines, randomly.2. Average Kinetic energy of particles depends on temperature.3. Particles collide and change direction (they may exchange
kinetic energies). Their collisions with walls cause the pressure.4. Gas particles have no volume.5. No attractive forces (or repulsion) between gas particles.6. More collision = greater pressure.
In reality, no gas is ideal (all gases are real).
At low pressure (around 1 atm or lower) and at 0°C or higher, we can consider real gases as ideal gases.
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Pressure (P)
Pressure (P) = Force (F)
Area (A)
A ↓ P ↑
Atmosphere (atm)Millimeters of mercury (mm Hg)torrin. HgPascal
1.000 atm = 760.0 mm Hg = 760.0 torr = 101,325 pascals = 29.92 in. Hg
F: constant
F ↑ P ↑
A: constant
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At STP: Standard Temperature & Pressure
Pressure (P)
1 standard atmosphere = 1.000 atm = 760.0 mm Hg = 760.0 torr = 101,325 pa
Pounds per square inch (psi)
1.000 atm = 14.69 psi
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Pressure (P)
barometeratmospheric pressure
manometerpressure of gas in a container
Hg
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Boyle’s Law
Boyle’s law: m,T: constant
P 1/α V PV = k (a constant)
P1V1 = P2V2
P2 =P1V1
V2
V2 =P1V1
P2
P1V1 = k (a constant)
P2V2 = k (a constant)
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Boyle’s Law
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Charles’s law: m,P: constant
T α V = k (a constant)
V2 =V1T2
T1
T2 =T1V2
V1
VT
V1
T1
V2
T2
=
V1
T1
V2
T2
= k (a constant)
= k (a constant)
Charles’s Law
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Charles’s Law
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Gay-Lussac’s law: m,V: constant
P α T = k (a constant)
P2 =P1T2
T1
T2 =T1P2
P1
PT
P1
T1
P2
T2
=
P1
T1
P2
T2
= k (a constant)
= k (a constant)
Gay-Lussac’s Law
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Gay-Lussac’s LawP
res
su
re (
P)
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Combined gas law:
= k (a constant) =P2V2
T2
PVT
P1V1
T1
Combined Gas Law
m (or n): constant
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Avogadro’s Law
V α n = k (a constant)Vn
V1
n1
V2
n2
=
V1
n1
V2
n2
= k (a constant)
= k (a constant)
Avogadro’s law: P,T: constant
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T = 0.00°C (273 K)P = 1.000 atm
Ideal gas law:
1 mole → V = 22.4 L
PV = nRT
n: number of moles (mol)R: universal gas constantV: volume (L)P: pressure (atm)T: temperature (K)
R =PV
nT=
(1.000 atm) (22.4 L)
(1 mol) (273 K)= 0.0821
L.atm
mol.K
Ideal Gas Law
Standard Temperature and Pressure (STP)
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Dalton’s law of partial pressure:
PT = P1 + P2 + P3 + …
Dalton’s Law
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Dalton’s Law
P1P2 P3
P1=n1RT
VP2=
n2RT
VP3=
n3RT
V
PT = P1 + P2 + P3
PT = n1(RT/V) + n2(RT/V) + n3(RT/V)
PT = (n1 + n2+ n3) (RT/V)
PT= ntotal ( )RT
V
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Dalton’s Law
1.75 mol He V=5LT=20C
PT = 8.4 atm
1.75 mol
V=5LT=20C
PT = 8.4 atm
0.75 mol H2
0.75 mol He
0.25 mol Ne
1.75 mol
V=5LT=20C
PT = 8.4 atm
1.00 mol N2
0.50 mol O2
0.25 mol Ar
For a mixture of ideal gases, the total number of moles is important.(not the identity of the individual gas particles)
1. Volume of the individual gas particles must not be very important.
2. Forces among the particles must not be very important.
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Gas Stoichiometry
Only at STP: 1 mole gas = 22.4 L
Ex 13.15 (page:433)
2KClO3(s) + 2KCl(s) + 3O2(g)
10.5 g KClO3 = ? Volume O2
10.5 g KClO3 (1 mole KClO3
122.6 g KClO3
) = 0.128 mole O2
3 mole O2
2 mole KClO3
)(
BA
P = 1.00 atmT = 25.0°C
PV = nRT
T = 25.0°C + 273 = 298 K
1.00V = 0.128 0.0821 298
V = 3.13 L