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Chapter 12 Stoichiometry

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Chapter 12. Stoichiometry. Reaction – Stoichiometry Problems. Identify the information given Identify the unknown , the information you are expected to find. Given  Unknown. Given amount in moles  Mole to Mole Ratio Unknown amount in moles. Given amount in grams (A)  - PowerPoint PPT Presentation

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Page 1: Chapter 12

Chapter 12

Stoichiometry

Page 2: Chapter 12

Reaction – Stoichiometry Problems

Identify the information given

Identify the unknown, the information you are expected to find.

Given Unknown

Page 3: Chapter 12

Given amount in moles

Mole to Mole Ratio

Unknown amount in moles

Page 4: Chapter 12

Given amount in grams (A)Given amount in moles (A)

Mole B / Mole A

Unknown amount in moles (B)

Page 5: Chapter 12

Given amount in grams (A) Molar Mass AGiven amount in moles (A)

Mole B / Mole A

Unknown amount in moles (B)

Page 6: Chapter 12

Grams A

Moles A

Moles B

Page 7: Chapter 12

Grams A

Moles A

Moles B

Grams B

Page 8: Chapter 12

Grams A Molar Mass A

Moles A Mole B/ Mole A

Moles B Molar Mass B Grams B

Page 9: Chapter 12

Problem

In photosynthesis, plants use energy from the sun to produce glucose, C6H12O6, and oxygen from the reaction of carbon dioxide and water.

What mass, in grams, of glucose is produced when 3.00 moles of water react with carbon dioxide?

Page 10: Chapter 12

Answer 3.00 mole H2O

x 1 mole C6H12O6 =

6 mole H2O

x 180.16 g C6H12O6 = 90.1 g C6H12O6

1 mole C6H12O6

Page 11: Chapter 12

Problem NH3(g) + O2(g) NO (g) + H2O (g)

Balance this equation!!

If the reaction is run with 824 g of NH3, and excess oxygen, how many moles of NO and H2O are formed?

Page 12: Chapter 12

Answer 4NH3(g) + 5O2(g) 4NO (g) + 6H2O (g)

824 g x 1 mole NH3 x 4 mole NO

17.031 g NH3 4 mole NH3

= 48.4 mole NO

Page 13: Chapter 12

Answer

824 g x 1 mole NH3 x 6 mole H2O

17.031 g NH3 4 mole NH3

= 72.6 mole H2O