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Challenge 1

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Physical Science. Mass. Challenge 1. Can you figure out how to make the balance even?. If 2 diamonds = 1 circle and 2 squares = 3 circles, what do you need to balance out 1 square?. Can you figure out how to make the balance even?. If 2 diamonds = 1 circle and - PowerPoint PPT Presentation

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Page 1: Challenge 1

Challenge 1

Page 2: Challenge 1

Can you figure out how to make the balance even?

If 2 diamonds = 1 circle and 2 squares = 3 circles, what do you need to

balance out 1 square?

Page 3: Challenge 1

Can you figure out how to make the balance even?

If 2 diamonds = 1 circle and 2 squares = 3 circles, what do you need to

balance out 1 square?

Page 4: Challenge 1

Can you figure out how to make the balance even?

If 2 diamonds = 1 circle and 2 squares = 3 circles, what do you need to

balance out 1 square?

Page 5: Challenge 1

Can you figure out how to make the balance even?

If 2 diamonds = 1 circle and 2 squares = 3 circles, what do you need to

balance out 1 square?

Equations to solve problem:

If 2 d = 1 c and 2 s = 3 c then 2 s = 3(2 d)2 s = 6 d, or 1 s = 3 d

1s = (d + d) + d, therefore 1s = (1c) + d

Page 6: Challenge 1

Challenge 2L. LaRosa http://www.middleschoolscience.com for T. Trimpe 2008 http://sciencespot.net/

Page 7: Challenge 1

1 g

10 g

20 g

50 g

100 g

197 g 5 g

Using a total of 7 brass weights, can you balance this balance?

Some weights can be used more than once

Page 8: Challenge 1

1 g

10 g

20 g

50 g

100 g

Using a total of 7 brass weights, can you balance this balance?

197 g

5 g

100 g

20 g

50 g

1 g1 g

5 g

20 g

Page 9: Challenge 1

Challenge 3L. LaRosa http://www.middleschoolscience.com for T. Trimpe 2008 http://sciencespot.net/

Page 10: Challenge 1

1 g

10 g

20 g

50 g

100 g

63 g 5 g

Can you balance the balance below by using the fewest number of weights?

Some weights can be used more than once

14 g

Page 11: Challenge 1

1 g

10 g

20 g

50 g

100 g

63 g

5 g

Can you balance the balance below by using the fewest number of weights?

Some weights can be used more than once

14 g

Page 12: Challenge 1

Challenge 4L. LaRosa http://www.middleschoolscience.com for T. Trimpe 2008 http://sciencespot.net/

Page 13: Challenge 1

100 g 20 g 10 g10 g

5 g5 g 5 g

5 g

1 g1 g

10 g

What is the total mass? Where should the riders be?

Page 14: Challenge 1

100 g 20 g 10 g10 g

5 g5 g 5 g

5 g

1 g1 g

10 g

What is the total mass? Where should the riders be?

172 g

http://www.ohaus.com/products/education/weblab/TBBread.html

Page 15: Challenge 1

Challenge 5L. LaRosa http://www.middleschoolscience.com for T. Trimpe 2008 http://sciencespot.net/

Page 16: Challenge 1

Complete the following conversions for grams and kilograms:

5,250 g = ____ kg 1,998 g = ____ kg 610 g = ____ kg 40 g = _____ kg

8.1 kg = ______ g 2.92 kg = ______ g 0.73 kg = ______ g 0.01 kg = ______ g

Page 17: Challenge 1

Complete the following conversions for grams and kilograms:

5,250 g = 5.25 kg 1,998 g = 1.998 kg 610 g = 0.61 kg 40 g = 0.04 kg

8.1 kg = 8,100 g 2.92 kg = 2,920 g 0.73 kg = 730 g 0.01 kg = 10 g

÷ 1,000 x 1,000

Page 18: Challenge 1

Challenge 6L. LaRosa http://www.middleschoolscience.com for T. Trimpe 2008 http://sciencespot.net/

Page 19: Challenge 1

Unscramble the following words related to mass

a. amrsgb. msliaokrgc. elncabad. rridse e. maeb f. napg. rtpeion

Page 20: Challenge 1

Unscramble the following words related to mass

a. amrsgb. msliaokrgc. elncabad. rridse e. maeb f. napg. rtpeion

a. Gramsb. Kilogramsc. Balanced. Riders e. Beam f. Pang. Pointer

Page 21: Challenge 1

Challenge 7L. LaRosa http://www.middleschoolscience.com for T. Trimpe 2008 http://sciencespot.net/

Page 22: Challenge 1

Complete the following conversions for grams and milligrams:

7,165 mg = ____ g 3,110 mg = ____ g 430 mg = ____ g 88 mg = _____ g

9.56 g = _____ mg 4.2 g = _____ mg 0.18 g = _____ mg 0.007 g = ____ mg

Page 23: Challenge 1

Complete the following conversions for grams and milligrams:

7,165 mg = 7.165 g 3,110 mg = 3.11 g 430 mg = 0.43 g 88 mg = 0.088 g

9.56 g = 9,560 mg 4.2 g = 4,200 mg 0.18 g = 180 mg 0.007 g = 7 mg

÷ 1,000 x 1,000