ch15 answers.pdf
TRANSCRIPT
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Chapter 15
Answers
15.1 Familiarization answers
Subject questionand Chapter
Questionnumber
Answer
API 570(Chapter 3)
123456789101112131415
abcdcbdbbcbaddd
API 574(Chapter 4)
12345
cabcc
API 574 (sections 6and 10)
(Chapter 4)
12345678910
acdbbdbcdc
API 578(Chapter 5)
123
bcc
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Subject questionand Chapter
Questionnumber
Answer
45678910
abbcbda
API 571 (set 1)(Chapter 6)
12345678910
bccacbcbbb
API 571 (set 2)(Chapter 6)
12345678910
bbabddddbb
API 571 (set 3)(Chapter 6)
12345678910
dacabcbbdd
API 577: weldingprocess
(Chapter 7)
123
abb
Answers
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Subject questionand Chapter
Questionnumber
Answer
45678910
addccbb
API 577: weldingconsumables(Chapter 7)
12345678910
abbaadccbd
API 570: generalwelding rules(Chapter 8)
12345678910
abcdabddbd
ASME B31.3(Chapter 8)
12345
abcba
ASME IX articles Iand II
(Chapter 9)
12345678
ccdacabb
Quick Guide to API 570
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Subject questionand Chapter
Questionnumber
Answer
910
dc
ASME IX articles IIIand IV
(Chapter 9)
12345678910
dddbaaaacd
API 577(Chapter 10)
12345678910
ccbdabcddd
API 570 and ASMEB31.3(1)
(Chapter 10)
12345678910
addabcaacb
ASME B31.3 (2)(Chapter 10)
12345678
adbdabca
Answers
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Subject questionand Chapter
Questionnumber
Answer
910
dc
ASME V articles 1, 2and 6
(Chapter 11)
12345
ddddc
ASME V articles 7and 9
(Chapter 11)
12345678910
badddabcaa
ASME B31.3:pressure design(Chapter 12)
123456789101112131415
bccabcabdccbcdd
ASME B16.5: angedesign
(Chapter 13)
12345678
bcdcdadc
Quick Guide to API 570
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Subject questionand Chapter
Questionnumber
Answer
910
bc
15.2 Example open-book answers
Question 1. B31.3: minimum design temperaturesB31.3 graph 323.2.1, as this is a Category D uid. Note 1 of thetable says that any carbon steel can be used down to 29 8C(ANS) (as long as its a Category D uid).
Question 2. B31.3: Barlow equationAPI 570 7.2 and using the simple Barlow equation P = 2SE t/Dfor the MAWP calculations,E= 1 for seamless, wall thickness t for a 20 in std pipe (API 574)= 0.375 in, OD (D) of pipe = 20 in, P = 2 20 000 0.375/20= 750 psi (ANS).
Question 3. Flange test pressuresB16.5 table 1A and table 2 show that A350 LF2 material is table1-1. At 250 8C, a Cl 1500 ange has a maximum workingpressure of 209.7 bar = 3041.2 psi (ANS).
Question 4. Degradation mechanismsAPI 574 section 10.2.1.5.2: suffers graphitization above 800 8F(ANS).
Question 5. B31.3: wall thickness equationsB31.3 section 304.1.2 equation 3(a). Using t = PD/[2(SE+PY)]in equation 3(a), note that for a 10 in NB pipe, the OD is10.75 in, not 10 in; S= 18.9 ksi for API 5L at 260 8C (500 8F), Y= 0.4 for ferritic steel (table 304.1.1), E = 0.85 for ERW pipefrom table 302.3.4, t = (348 10.75)/{2 [(18 900 0.85)+(348 0.4)]} = 0.115 in = 2.93 mm + 2 mm rounded up= 5 mm (ANS).
Question 6. B31.3: design stressFrom the other materials section of B31.3, 302.3.2 (d), thedesign stress shall not exceed:
. one-third of the minimum UTS at room temperature (ST)or at temperature;
Answers
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. two-thirds of the minimum yield at room temperature (SY)or at temperature,
so in this case its the lower of 4300 kPa/3 = 1433 kPa or23 2070 kPa = 1380 kPa (ANS).Question 7. B31.3: casting factorsRead from the table in B31.3 section 302.3.3c. The answer is 0.85(ANS) as no surface nish is given in the question.
Question 8. B31.3: blank thicknessUsing the blank formula in B31.3 section 304.5.3, t = d SQRT[3P/(16SE)] + c, D = 278 mm = 10.94 in, P = 670 psi, S =A182 F304L material at 400 8C (752 8F) = 13.2 ksi, t =10.94 SQRT [(3 670)/(16 13 200)] = 1.06 in = 27 mm(ANS).
Question 9. Flange test pressuresB16.5 table 1A and table 2-1.9. For a class 300 ange the tableshows a maximum temperature of 250 8C (ANS).
Question 10. B31.3: blank thicknessUsing the blank formula in B31.3 section 304.5.3, t = d SQRT[3P/(16SE)] + c, D= 10 in, P = 170 psi, S= A105 material at500 8F = 19.4 ksi, t = 10 SQRT [(3 170)/(16 19 400)] =0.4 in =10.29 mm; to go for the next size up 15 mm (ANS).
Question 11. B31.3: minimum design temperaturesB31.3 graph 323.3.2A. Curve C at 30 mm thick shows 15 8C(ANS).
Question 12. B31.3: minimum design temperaturewithout impact testingB31.3 graph 323.3.2B. Stress ratio = 62/130 = 0.467 gives atemperature reduction of 60 8F (36 8C) (ANS).
Question 13. B31.3: allowable reductions in designtemperatureB31.3 graph 323.3.2B. Stress ratio = 64/160 = 0.4 gives atemperature reduction of 60 8C (ANS).
Quick Guide to API 570
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Question 14. B31.3: minimum Charpy valuesMethod: B31.3 section 323.3.5. Checking strength from B31.3table A-1 gives 20 ksi. Looking in table 323.3.5 for 65 ksi and lessgives a minimum Charpy value of 16 J (ANS).
Question 15. B31.3: thermal expansionFrom B31.3 appendix C table, temperature rise from 70 to 5008F gives an expansion of carbon steel (API 5L is carbon steel) of3.62 in/100 ft. Pipe is 900.68 in = 75 feet so expansion =3.62 0.75 = 2.71 in = 69 mm (ANS).Question 16. B31.3: thermal expansionFrom B31.3 appendix C table, temperature rise from 70 to950 8F gives an expansion of stainless steel (API 5L is carbonsteel) of 10.8 in/100 ft. Pipe is 1801.36 in = 150 feet so expansion= 10.8 1.5 = 16.2 in = 411 mm (ANS).Question 17. API 570: corrosion ratesMethod: API 570 section 7.2. 18 in std has wall thickness of0.375 in = 9.525 mm. A515 Gr 50 has S= 15.8 ksi at 600 8F. E= 0.6 for furnace butt welded pipe Y = 0.4 for ferritic pipe.Using t = PD/[2(SE+PY)], t = 300 18 /2 [(15 800 0.6) +(300 0.4)] = 5400/19 200 = 0.28 in = 7.14 mm. Hence it has9.525 7.14 mm = 2.385 mm to corrode at 0.254 mm/yr = 9.4years. It should be inspected after half of this = 4.7 years (ANS).
Question 18. API 570: corrosion ratesAPI 570 section 7.1.1. Hence it has 10 6 mm = 4 mm tocorrode at 0.25 mm/yr = 16 years. It should be replaced afterthis 16 years (ANS).
Question 19. Flange and pipe test pressuresMethod: B31.3 section 345.2.1. Pipe size details are not required.It is simply Pt = 1.5 PStest/Stemp = 1.5 254 = 381 psi(ANS).
Question 20. API 570: corrosion ratesMethod: API 570 section 7.1.1. Check 10 in Sch 140 has a wallthickness of 1 in = 25.4 mm. So it has corroded 10 mm in 10years = 1 mm/year (ANS).
Question 21. API 570: corrosion ratesMethod: API 570 section 7.1.1. So it has corroded 2 mm in 4years = 0.5 mm/year (ANS).
Answers
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Question 22. API 574: Barlow formulaMethod: API 574 section 11.1. Answer is (b) (ANS).
Question 23. API 574: valve wall thicknessAPI 574 section 11.2 species that a valve must have 1.5wallthickness of a pipe connected to it. Hence thickness = 1.5 10mm = 15 mm (ANS).
Question 24. API 574: anged connection thicknessAPI 574 section 11.2 species that a anged tting (like a valve)must have 1.5wall thickness of a pipe connected to it. So if theanged tting is 30 mm the pipe must be 20 mm (ANS).
Question 25. API 570: pipe classesAPI 570 table 6.1, class 1 pipe. Thickness measurements arerequired every 5 years (ANS).
Question 26. API 570: pipe classesAPI 570 table 6.1, class 2 for hydrogen. Thickness measurementsare required every 10 years (ANS).
Question 27. API 570: pipe classesAPI 570 table 6.1, class 2 for strong acids and caustics. Externalvisual is required every 5 years (ANS).
Question 28. API 570: pipe classes CUIMethod: API 570 table 6.2 and table 6.2, class 3. Requiredexamination is 25 % (ANS).
Question 29. API 570: pipe classes CUIAPI 570 table 6.2, class 1 but no damaged lagging. Requiredexamination is 50 % (ANS).
Question 30. API 570: pipe classes inspection periodAPI 570 section 6.6.1, class 2 small-bore secondary pipework.Code says inspection is optional (ANS).
Quick Guide to API 570
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