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ch12.problems jh.131. take the lower center as rotation center then: m2 (l/4) = m3 (3l/4) m2= 3 m3...

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  • CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
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CH12.Problems JH.131

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Page 1: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)

CH12.Problems

JH.131

Page 2: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 3: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 4: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 5: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 6: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 7: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)

Take the lower center as rotation center then:M2 (L/4) = M3 (3L/4) M2= 3 M3

Now the upper center:

M1 (L/4) = (M2+M3) (3 L/4)

M1 = 3(M2+M3) = 3* 4 = 12kg

Only Torques, no forces!

Page 8: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)

-Ta + Tc cos30 = 0

Tc Sin30 -240 = 0

Only forces no torques

Page 9: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)

Project!

Mg (L/2 sin alpha) is cw torque

2Mg (L) Sin(90-alpha) is CCW torque

Then 2 Cos(alpha) = Sin(alpha) /2

Or Tan (alpha) = 4 alpha = 76 deg

Page 10: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 11: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 12: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 13: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)

Any triangle =180; so, beam makes 60 with vertical

Page 14: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)
Page 15: CH12.Problems JH.131. Take the lower center as rotation center then: M2 (L/4) = M3 (3L/4) M2= 3 M3 Now the upper center: M1 (L/4) = (M2+M3)

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