ch 6a 2nd law
TRANSCRIPT
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Heat always flows from
high temperature to low
temperature.
So, a cup of hot coffee
does not get hotter in a
cooler room.
Yet, doing so does not
violate the first law as long
as the energy lost by air is
the same as the energy
gained by the coffee.Room at
25° C
!?
Example 1
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It is clear from the previous
examples that..
Processes proceed in certain direction and not in the reverse direction.
The first law places no restriction on the direction of a process.
• Therefore we need another law (the second law of thermodynamics) to determine the direction of a process.
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Thermal Energy Reservoir
• If it supplies heat then it
is called a source.
• It is defined as a body to which and from
which heat can be transferred without a
change in its temperature.
• If it absorbs heat then it
is called a sink.
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• Some obvious examples
are solar energy, oil
furnace, atmosphere,
lakes, and oceans
• Another
example is two-
phase systems,
• and even the air in a room if the heat added or absorbed is small compared to the air thermal capacity (e.g. TV heat in a room).
Air
Thermal Pollution- disrupt marine life!
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We all know that doing work on the water will generate heat.
However transferring heat to the liquid will not generate work.
Yet, doing so does not violate the first law as long as the heat added to the water is the same as the work gained by the shaft.
Heat Engines
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Previous example leads to the concept of Heat Engine!.
We have seen that work always converts directly and completely to heat, but converting heat to work requires the use of some special devices.
These devices are called Heat Engines and
can be characterized by the following:
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Characteristics of Heat
Engines..
They receive heat from high-temperature source.
They convert part of this heat to work.
They reject the remaining waste heat to a low-temperature sink.
They operate on (a thermodynamic) cycle.
High-temperature
Reservoir at TH
Low-temperature
Reservoir at TL
QH
QL
WHE
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Difference between Thermodynamic
and Mechanical cycles
A heat engine is a device that operates in a thermodynamic cycle and does a certain amount of net positive work through the transfer of heat from a high-temperature body to a low-temperature body.
A thermodynamic cycle involves a fluid to and from which heat is transferred while undergoing a cycle. This fluid is called the working fluid.
Internal combustion engines operate on a mechanical cycle (the piston returns to its starting position at the end of each revolution) but not on a thermodynamic cycle.
However, they are still called heat engines
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Thermal efficiency
Thermal Efficiency
< 100 %
in
out
Q
Q1
input Required
output DesiredePerformanc
in
out,net
thQ
W
in
outin
Q
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Thermal efficiency
Thermal Efficiency
< 100 %1 L
H
Q
Q
,net out
th
H
W
Q H L
H
Q Q
Q
QH= magnitude of heat transfer between the cycle
device and the H-T medium at temperature TH
QL= magnitude of heat transfer between the cycle
device and the L-T medium at temperature TL
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thermal efficiency can not
reach 100%
Even the Most Efficient Heat
Engines Reject Most Heat as
Waste Heat
400.4
100th
Automobile Engine 20%
Diesel Engine 30%
Gas Turbine 30%
Steam Power Plant 40%
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Heat is transferred to a heat engine from
a furnace at a rate of 80 MW. If the rate
of waste heat rejection to a nearby river
is 50 MW, determine the net power
output and the thermal efficiency for
this heat engine.
<Answers: 30 MW, 0.375>
Example 6-1: Net Power Production of a Heat
Engine
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The Second Law of Thermodynamics:
Kelvin-Plank Statement (The first)
The Kelvin-Plank statement:
It is impossible for any device that
operates on a cycle to receive heat
from a single reservoir and produce
a net amount of work.
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It can also be expressed as:
No heat engine can have a thermal
efficiency of 100%, or as for a
power plant to operate, the working
fluid must exchange heat with the
environment as well as the furnace. Note that the impossibility of having a 100%
efficient heat engine is not due to friction or
other dissipative effects.
It is a limitation that applies to both idealized
and the actual heat engines.
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Example 1 at the beginning of
the notes leads to the concept of
Refrigerator and Heat Pump.. Heat can not be transferred from low
temperature body to high temperature one
except with special devices.
These devices are called Refrigerators and
Heat Pumps
Heat pumps and refrigerators differ in
their intended use. They work the same.
They are characterized by the following:
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High-temperature Reservoir at TH
Low-temperature Reservoir at TL
QH
QL
W
RefQL = QH - W
Objective
Refrigerators
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Coefficient of Performance of a
RefrigeratorThe efficiency of a refrigerator is expressed in term of
the coefficient of performance (COPR).
Desired output
Required inputRCOP
,
1
1
L L
Hnet in H L
L
Q Q
QW Q Q
Q
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Heat Pumps
High-temperature Reservoir at TH
Low-temperature Reservoir at TL
QH
QL
W
HP
QH = W + QL
Objective
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Coefficient of Performance of a
Heat PumpThe efficiency of a heat pump is expressed in term of the
coefficient of performance (COPHP).
Desired output
Required inputHPCOP
,
1
1
H H
Lnet in H L
H
Q Q
QW Q Q
Q
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Relationship between Coefficient of
Performance of a Refrigerator (COPR)
and a Heat Pump (COPHP).
,
,
net in LH HHP
net in H L H L
W QQ QCOP
W Q Q Q Q
,1
net in LHP R
H L H L
W QCOP COP
Q Q Q Q
1HP RCOP COP
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The second Law of Thermodynamics:
Clausius Statement
The Clausius statement is
expressed as follows:
It is impossible to construct a
device that operates in a cycle
and produces no effect other
than the transfer of heat from
a lower-temperature body to a
higher-temperature body.
Both statements are negative
statements!
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High-temperature Reservoir at TH
Low-temperature Reservoir at TL
QH + QL
QL
W = QH
RefHE
QH
Net QIN = QL
Net QOUT = QL
HE + Ref
Equivalence of the Two
Statements
Consider the HE-RF combination shown below
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Example (6-2): Heating a House by a Heat Pump
A heat pump is used to meet the heating requirements of
a house and maintain it at 20oC. On a day when the
outdoor air temperature drops to -2oC, the house is
estimated to lose heat at rate of 80,000 kJ/h. If the heat
pump under these conditions has a COP of 2.5,
determine (a) the power consumed by the heat pump and
(b) the rate at which heat is absorbed from the cold
outdoor air.
Sol:
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6.3. Perpetual Motion Machines
Any device that violates the first or second law is called a perpetual motion machine
If it violates the first law, it is a perpetual motion machine of the first type (PMM1)
If it violates the second law, it is a perpetual motion machine of the second type (PMM2)
Perpetual Motion Machines are not possible