carbonyl compounds carbonyl compounds have the functional group c=o and form an homologous series...
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Carbonyl compounds
Carbonyl compounds have the functional group C=O and form an homologous series with a general
formula CnH2nO
There are two types; 1) Aldehydes and 2) Ketones
Aldehydes vs Ketones
Aldehydes have a carbonyl group C=O, at one end.
Ketones also have a carbonyl group, but in the interior of the molecule.
Naming Carbonyl compounds
• Aldehydes and ketones are named using the usual IUPAC rules with the addition of an appropriate suffix to the number of carbons.
For aldehydes -al For ketones -one
Eg; CH3(CH2)3CHO is pentanal
Eg; CH3(CH2)3COCH3 is hexanone
Eg; 3C molecule with the carbonyl group at one end. So
this is propanal.
3C molecule with the carbonyl group in the interior. So this is
propanone.
• Name the following compounds;
• CH3(CH2)8CHO
• Decanal
• C6H5CHO
• Benzaldehyde • (aka benzenecarbaldehyde)
• CH3CO(CH2)3CH3
• Hexan 2 one
Testing for carbonyl compounds.
Both aldehydes and ketones give an orange/red precipitate with 2,4 dinitro phenyl hydrazine.
Identifying organic compounds
2,4 DNPH precipitates have very sharp, easily distinguishable melting points.
So organic compounds were once identified by conversion to carbonyls and precipitation of the 2,4 dinitrophenylhydrazones.
These were filtered, recrystalised and their MPs determined and compared with text book values.
Eg; An unknown carbonyl compound has
a MP of 123OC.
• It must therefore have been Butanal.
MP (OC)
Methanal 167
Ethanal 164
Propanal 156
Butanal 123
Benzaldehyde 237
Distinguishing between aldehydes and ketones.
Aldehydes are oxidised as
orange chromium (vi) is
reduced togreen chromium (iii) when heated
with acid.
Only one organic product is possible; a Carboxylic Acids.
Dichromate redution Cr2O7 2- + 14H+ + 6e → 2Cr3+ + 7H20
Aldehyde oxidation; CH3CHO + H2O→ CH3CO(OH) + 2H++ 2e-
Ethanal Ethanoic acid
•NB Instead of H+ [H] or ‘H’ can be used in writing half equations.
Half equations
Distinguishing between aldehydes and Ketones
Ketones cannot be oxidised by acidified
potassium dichromate.
To oxidise them a much stronger oxidising agent is needed that can break C/C bonds.
Reaction with Fehling’s Solution
Aldehydes change the colour of
Fehling’s Reagent upon heating from
blue to red.
Blue copper (ii) ions are reduced to red
copper (i).
Cu 2+ + e- → Cu+
Ketones do not react with Fehling’s
Solution as they are not oxidised by mild
oxidising agents.
Reaction with Tollen’s Reagent
Aldehydes react with Tollen’s Reagent (ammonical silver solution [Ag(NH3)2]+
(aq), ), depositing a silver mirror on the side of the tube.
Silver ions are reduced to metallic silver.
Ag+(aq) + e- → Ag(s)
But Ketones do not react with Tollen’s reagent as they are not oxidised by mild oxidising agents.
Sugars and carbonyl groups.
Sugars form unbranched
chains in which each
carbon atom, bar one, has an hydroxyl
group.
The exception has a carbonyl group.
If this is an aldehyde the sugar is an
aldose.
If in the ketone form
the sugar is a ketose.
Eg; Glyceraldehyde is an aldose
Dihydroxyacetone is a ketose
Aldoses can be oxidised like any other aldehyde.
In the process another chemical is reduced.
So aldoses are referred to as reducing sugars.
Ketoses, like ketones,
cannot be easily
oxidised.
So they are known as
non-reducing sugars.
Reaction with Benedict’s Reagent
Benedict’s Reagent is similar to Fehlings. So Aldoses
change its colour of Fehling’s blue to red.
Blue copper (ii) ions are reduced by the reducing sugar to red copper (i).
Cu 2+ + e- → Cu+
Ketones do not react with Benedict’s
Reagent as they are not oxidised by mild
oxidising agents.