calculation of water current forces :-
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CALCULATION OF WATER CURRENT FORCES :-TRANSCRIPT
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CALCULATION OF WATER CURRENT FORCES :-
Mean velocity of water current at HFL ,V = 7.0 m/s
= 9.90 m/s
= 98.0 m/s
Case 1:
Value of "K" = 0.66 Water current force diagram
3.363t/m2Pier shaft width at top (m) = 2.68
HFLPier shaft width at base (m) = 2.0 94.875
FIntensity of pressure due to water
= 3.363
Intensity of pressure due to water
= 1.853 1.853t/m2 80.200
Water current force on pier uptoend of varying portion, F (t) = 47.5
Level at which force F acts = 89.876
62.200
Case 2:
Value of "K" along transverse direction = 0.66
= 41.95 t
Value of "K" along longitudinal direction = 1.50
Water current force on pier uptoend of varying portion, F (t) = 56.2
Level at which force F acts = 94.162
Max. velocity at surface , V = (2)0.5*V
V2 at HFL
Water current force for normal case, water flowing at 0o
current at HFL, 52KV2 (t/m2)
at well cap top level (t/m2)
Top of well cap
Normal scour level
Water current force for normal case, water flowing at 20o
Force at base of pier along transverse direction ( taking cosine component of the value as calculated above & multiplying with the appropriate obstruction width)
Force at base of pier along transverse direction ( taking sine component of the value as calculated above & multiplying with the appropriate obstruction width)
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3.90mPier cap top Level
RL 95.950
3.46m HFLRL 94.875
1.00m
pier centre line
H= 14.67m
2.00m RL 80.200Top of well cap
OBSTRUCTION DIAGRAM IN TRANSVERSE DIRECTION
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11.00mPier cap top Level
RL 95.95HFL
RL 94.875 10.10m
5.00m
pier centre line
14.67m
RL 80.200 6.00mTop of foundation / well cap
OBSTRUCTION DIAGRAM IN LONGITUDINAL DIRECTION
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= 98.0 m/s
Case 3:
Value of "K" = 0.66 Water current force diagram
3.363t/m2Pier shaft width at top (m) = 2.14
HFLPier shaft width at base (m) = 2.00 94.875
FIntensity of pressure due to water
= 3.363
Intensity of pressure due to water
= 1.685 1.685t/m2 80.200
Water current force on pier uptoend of varying portion, F (t) = 45.7
Level at which force F acts = 88.886
65.460
Case 4:
Value of "K" along transverse direction = 1.50
= 40.34 t
Value of "K" along longitudinal direction = 1.50
Water current force on pier uptoend of varying portion, F1 (t) = 54.7
Level at which force F1 acts = 94.303
V2 at HFL
Water current force for seismic case, water flowing at 0o
current at HFL, 52KV2 (t/m2)
at well cap top level (t/m2)
Top of well cap
Seismic scour level
Water current force for seismic case, water flowing at 20o
Force at base of pier along transverse direction ( taking cosine component of the value as calculated above & multiplying with the appropriate obstruction width)
Force at base of pier along transverse direction ( taking sine component of the value as calculated above & multiplying with the appropriate obstruction width)