calculation note for tank foundation (recovered).docx
TRANSCRIPT
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8/14/2019 Calculation note for tank foundation (Recovered).docx
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Sheet: Page 1 of 8Document Number :
Document Title:
I.P.D.C.
15000 m 3 GASOIL TANK
RING WALL FOUNDATION
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8/14/2019 Calculation note for tank foundation (Recovered).docx
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Document Title:
I.P.D.C.
UNITS: ton & m (unless noted otherwise)
Input Data
Concrete
f'c (kg/cm2) 250
c (ton/m3) 2.4
Soil Parameter
(degree) 30C (kg/cm 2) 0.04
Ks (kg/cm 3) 1.35
s (ton/m3) 1.8
qnet (kg/cm2) 1.5
S settlement (m) 0.025
Equipment Data
B.C.D 38.2 Anchor bolts NoneShell thickness 0.012
Bottom Plate Thickness 0.008D, Tank outside diameter 38.212 H 13.2
Foundation Assumption
B 1.1H1 0.5H2 1.5D1, Ring Diameter 39.312
Loading (ton & m)
W operate 13189Earthquake Shear 2068Earthquake Coefficient 0.16
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I.P.D.C.
Stability Check
Bearing Capacity Check
Description(Elastic Condition) P1 P2 max AllowFactor BearingCapa.
Conclusion
EmptyDL+EMPTY+WL 5.26 1.05 4.75 1.33 15.00 OKDL+EMPTY+EL 5.26 0.22 4.13 1.33 15.00 OK
TestDL+ET+0.2WL 12.07 0.21 9.24 1.33 15.00 OKDL+ET+0.2*EL 12.07 2.63 11.06 1.33 15.00 OK
OperateDL+EO+WL 11.25 1.05 9.25 1.33 15.00 OKDL+EO+EL 11.25 11.57 17.16 1.33 15.00 OK
DL+EO 11.25 0.00 8.46 1.00 15.00 OK
A1 132.05 m 2 Area of footing
A2 65.08 m 2 Area of tank bott. that settled on the footing
F1(Test) 13.09 ton/m 2 Stress on tank bott. due to Test load
F2(Op.) 11.50 ton/m 2 Stress on tank bott. due to Operate load
Atank bott.
1146.80 m 2
W steel bott. 72.02 ton Steel bott. Weight
Av 0.140 Vertical earthquake acceleration coefficent %g according to API-650
P1 = {(Empty wt. - W steel bott. ) + (Ring Wall wt.) + (F1 or F2)*A2} / A1
P2 = (1.273*M) / (D 2 * B) M : Wind or Seismic Moment
Ultimate ConditionFor Reinforcement Design
Description(Ultimate Condition) P1 P2 max
Empty0.9(DL+EMPTY)+1.3WL 4.74 1.37 6.110.9(DL+EMPTY)+EL 4.74 0.22 4.96
Test1.2(DL+ET)+1.3*(0.2*WL) 14.49 0.31 14.801.2(DL+ET)+1.6*(0.2*EL) 14.49 4.21 18.70
Operate
1.2(DL+EO)+1.3WL 13.50 1.37 14.871.2(DL+EO)+EL 13.50 11.57 25.07
1.4(DL+EO) 15.75 0.00 15.75
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I.P.D.C.
Settlement
s = (qB / Es) * f 1.42 cm OK
Es 1800 ton / m 2 f 1.35
max 17.16 from table 4
Design
Hoop TensionWall Height (H2) 1.50Wall Width (B) 1.10Tank Shell dia. (D) 38.21K0 = 1 - Sin ( ) 0.50
Horizontal Compact Load :
Phc =( 2 * P * s / )0.5 3.04 ton/m 2
Phc : max horizontal pressure on the ring wall from the soil and compaction combinedlP : line load from the compaction equal to sum of static and dynamic pressureP = 451 lbs/inch=8.06 t/m (Assume, vibratory roller)
s 1.8 ton/m3
Radial Force,Fr1 = Phc * H2 4.56 ton/m
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Sheet: Page 7 of 8Document Number :
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Horizontal Load :
Pw : Max ( F1 & F2 ) 13.09 ton/m 2 Radial Force,Fr2 = (K 0 * Pw * H2) + (0.5 * K 0 * s * H2
2)
Radial Force,Fr2 10.83ton
T ( Axial Tansion in Ring ) = 0.5 * MAX (Fr1&Fr2) * DMAX (Fr1&Fr2) 10.83 ton
T ( Axial Tansion in Ring ) 206.85 ton
Tu (Ultimate Axial Tension in Ring) = (Soil Pressure Load Factor Acc.to ACI 2005) * T
Tu (Ultimate Axial Tension in Ring) 330.96ton
Reinforcing
Vertical Bar
As the shell will be placed at the center of the ring wall, the torsional moment due to shell eccentricity can be negligible.
So, MIN re-bar is provided.
bw 100 cm B 110 cm
min 0.002 (for temperature and shrinkage for wall in ACI 318-7.12)
Asmin = 0.0020 * bw * B 22.00 cm 2
Horizontal Bar
B 110 cmH2 150 cm
min 0.0035 (for structural walls of uniform thickness as stated in ACI 318, chapter 14)
fy 4000 kg/cm 2
Asreq = Tu / (0.9 * fy) 91.93cm 2
Asmin = min * B * H2 57.75cm 2
Asreq = Max ( Asreq & Asmin ) 91.93cm 2
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Sheet: Page 8 of 8Document Number :
Document Title:
I.P.D.C.
Checking of Min. wallthk.
As the differential settlement is disadvantageous for the tank, minimum thickness of concrete wallrequired to equalize soil pressures between under tank and ring wall.
test 1 ton/m3
operate 1.4 ton/m3
f = Max ( test & operate ) 1.4 ton/m 3
Soil presure
P1 = f * H + s * H2 21.18 ton/m 3
P2 = W / t' + 0.5 * f * H + c * H2
W = ( Empty wght. - W steel bott. ) / ( * D ) 1.52ton
t' 18.28 cm OK
Concrete Stress
C (shrinkage coeff.) 0.003
Es 2.10E+06 kg / cm 2 n = Es / Ec 9
fct = 0.7 * ( fc ) 0.5 23.69kg / cm 2
t" 93.15 cm OK