c pointer declarations

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Average Rating: 4.4/5 | Rate this item | 111 users have rated this item.

Expertise: AdvancedLanguage: C++

March 8, 2000

Hide Function Pointer Declarations With a typedef

Can you tell what the following declaration means?

void (*p[10]) (void (*)() );

Only few programmers can tell that p is an "array of 10 pointers to a function returning void and taking apointer to another function that returns void and takes no arguments." The cumbersome syntax is nearlyindecipherable. However, you can simplify it considerably by using typedef declarations. First, declare atypedef for "pointer to a function returning void and taking no arguments" as follows:

typedef void (*pfv)();

Next, declare another typedef for "pointer to a function returning void and taking a pfv" based on thetypedef we previously declared:

typedef void (*pf_taking_pfv) (pfv);

Now that we have created the pf_taking_pfv typedef as a synonym for the unwieldy "pointer to a functionreturning void and taking a pfv", declaring an array of 10 such pointers is a breeze:

pf_taking_pfv p[10];

Danny Kalev

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By raviparu December 8 2009 2:17 AM PDT

This example really helps in simplifying any sort of complex function pointer declarations

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Hide Function Pointer Declarations With a typedef file:///Users/saumitre/other/read/tech/c-func-ptrs-typedef.htm

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By raviparu December 8 2009 2:17 AM PDT

This example really helps in simplifying any sort of complex function pointer declarations

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c pointer declarations

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