building energy efficiency in the baltics ( benefit-2006 ) , riga, 25 october, 2006
DESCRIPTION
Calculation of Energy Performance of Buildings - Lithuanian Case Dr. Jurate Karbauskaite, dr. Edmundas Monstvilas, prof. V.Stankevicius, Institute of Architecture and Construction, Kaunas Technology University, Lithuania. Building Energy Efficiency in the Baltics - PowerPoint PPT PresentationTRANSCRIPT
Calculation of Energy Performance of Buildings - Lithuanian Case
Dr. Jurate Karbauskaite, dr. Edmundas Monstvilas, prof. V.Stankevicius, Institute of Architecture and Construction,
Kaunas Technology University, Lithuania
Building Energy Efficiency in the Baltics
(BENEFIT-2006), Riga, 25 October, 2006
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
The biggest part in environment pollution is formed by heating of buildings
(IEA data)
At the point of view of long-term energy policy, the buildings At the point of view of long-term energy policy, the buildings ought to conform to the minimal requirements of energy ought to conform to the minimal requirements of energy performance in them in respect to the local climate. performance in them in respect to the local climate. The factors which serve to the growth of energy efficiency, The factors which serve to the growth of energy efficiency, must be taken into advantage must be taken into advantage
41
545
18
27
Heating Ventilation Light Cooling Equipment Computers
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
420
220
150
70
170 180
250
220
150
70
120 130
0
50
100
150
200
250
300
350
400
450
tll 1992 West Europe Skandinavia Economicalhouse
STR2.05.01:1999
RSN 143:91
En
erg
y c
on
su
mp
tio
n f
or h
eati
ng
, k
Wh
/m2 p
er y
ear
Small houses
Big houses
Comparison of energy consumption in Lithuania building stock with the European trends
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
0,0
5,0
10,0
15,0
20,0
25,0
30,0
35,0
0 - 5 5 -10 10 - 15 15 - 20 20 - 25 25 - 30 30 - 35 35 - 40 40 - 45 45 - 50 50 - 55 55 - 60
Bins, kWh/m2 per month
Am
ou
nt o
f b
uild
ing
s, %
Energy consumption for heating during the recent 1997-2001 has been decreased by 15 - 20 %. In big apartment buildings mean energy consumption value can be assumed as 145 -240 kWh/m2 at 3790 degree days at indoor air temperature of 18 °C.
Energy consumption in a big part, about 30 % of them, is significantly lower, mainly due to lowered indoor temperature, as well as other 30 % are consuming more than mean value. .
BENEFIT-2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings - Lithuanian Case
The National Building Code STR 2.01.09.2005 (BUILDING TECHNICAL REGULATION) BUILDING ENERGY PERFORMANCE CERTIFICATION states, that building energy efficiency is assessed only by calculation of the building energy consumption according to the method presented in the obligatory Annex.
Development in this direction shall be provided in the future stage
Character of the tenants behavior andstate of the building envelope are not taken into consideration in recent normative document
BENEFIT-2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings - Lithuanian Case
1..
sumN
sumQ
Q
..sumN
sum
Q
QC
1..
sumR
sum
Q
Q
..1
sumR
sum
Q
QC
....
..1sumNsumR
sumNsum
QQC
The energy performance is evaluated by classification indicator value, which shall be determinated for a considered building due to the total building normative QN.sum, reference QR.sum and calculated Qsumvalues
of building energy consumption for 1 m2 of building heated area. classification indicator value is expressed by equation:
,
in the other cases
if
if
BENEFIT-2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings - Lithuanian Case
The performance class, depending on the value of the classification indicator C : - Class A, if C 0,5;- Class B, if 0,5 C 1;- Class C, if 1 C 1,5;- Class D, if 1,5 C 2;- Class E, if 2 C 2,5;- Class F, if 2,5 C 3;- Class G, if C 3.
THE BUILDINGS COULD BE ATTRIBUTED TO ONE OF THE 7CLASSES:
A.B, C, D, E, F, G.
CLASS A IS AT THE TOP AND SUCH A BUILDING IS VERY ENERGY EFFICIENT WITH LOW ENERGY CONSUMPTION IN IT.
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Transmission heat losses
Heat losses through the external walls;Heat losses through roof;Heat losses through building ceilings, which are in contact with external air;Heat losses through building ceilings over unheated basement and crawls;Heat losses through building elements on ground;Heat losses through the windows;Heat losses through external doors, excluding the heat losses due the door opening;Heat losses through thermal bridges in building;Heat losses due to opening of external door
Ventilation heat losses
Heat losses due to door opening
Heat losses due over-infiltration of external air through windows
Solar heat gains
Internal heat gains
Domestic hot water supply (annual value)
Electricity (annual value)
-
Building energy performance components
Heating season values
BENEFIT-2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings - Lithuanian Case
Lay-out of basic heat losses in the residential buildings according to the construction year
0,0
5,0
10,0
15,0
20,0
25,0
30,0
35,0
40,0
till 95 95 96 97 98 99 2000 2001 2002 2003 2004 2005 2006
Bu
ild
ing
heat
losses, %
Roofs CeilingsWalls WindowsDoors Thermal bridgesVentilation
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Calculation of the energy used for the ventilation of the building
Ventilation systems could be attributed to one of the three types:-natural ventilation;-mechanical ventilation without heat recovery;-mechanical ventilation with heat recovery.
Description of the heat recovery system r
Mechanical ventilation without heat recovery 0
The efficiency factor of mechanical ventilation with heat recovery is unknown
0,5
The calculated efficiency factor of the mechanical ventilation system with heat recovery r
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Calculation of the heat losses because of extra normative infiltration of external air through windows and external doors
Normative heat losses QN.inf. (kWh/(m2per year)) during the heating season because of extra normative infiltration of external air through windows and external doors, is set, that there should be no higher infiltration of external air than it’s needed for the ventilation of the building, so QN.inf.=0.
Reference QR.inf. (kWh/(m2per year)) heat losses during the heating season because of extra normative infiltration of external air through windows and external doors shall be calculated with respect to new and old window and door amount according to the equations in the Annex 2 of the Regulation.Calculated Qinf (kWh/(m2per year)) heat losses during the heating season because of extra normative infiltration of external air through windows and external doors shall be calculated with respect to new and old window and door amount according to the equations in the Annex 2 of the Regulation.
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Calculation of the heat losses through the external door due to doors opening
The heat losses Qd1 (kWh/(m2 per year)) during the heating season through the external door due to door opening shall be calculated according to the equation:
where: Ao – the area for one occupant (m2). Selected from table 2.4;
kd1 – the correction coefficient, evaluating the frequency of opening of external doors of different types of the
buildings, selected from table 2.11 of the Regulation.kd2 – the correction coefficient, evaluating the type of external doors. The value of the coefficient shall be selected
from table 2.12 of the Regulation with respect to the type of the external doors: according to the door, that is most frequently used or according to the door, that generalized corresponds to all types of external doors of the building;h – the height of the building (m). That is the distance from the ground level to the highest point of the heated room, located at the upper part of the building.
)2,01(1
15,2 21.1 hkkA
Q ddo
d
Type of building kd1
One and two storey residential buildings 7
Apartment buildings 7
Administrative 10
Educational 5
Health care 14
Restaurants 14
Trade 2
Sport, except swimming pools 9
Swimming pools 7
Cultural 3
Garage, manufacturing and industry 5
Storage 5
Hotels 7
Service 18
Transport 50
Recreation 10
Special 5
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Description of the type of external doors
kd2
One door without tambour 1
Two doors without tambour between 1,1
Two doors with tambour between 0,6
Three doors with tambour between 0,4
Swinging-doors 0,75
Doors with air curtain 0,1
One automatic door without tambour 0,9
One automatic doors with tambour 0,5
Correction coefficient for the doors kd2
Correction coefficient for the doors kd1
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Calculation of energy use for domestic hot water Annual energy use for hot water Qh.w. (kWh/(m2per year)):
..
....
wh
whwhQ
where:
ψh.w. – the annual energy demand for hot water
per unit of the building area (kWh/(m2per year)). Selected from table 2.4;h.w. – the efficiency factor of the hot water
supply system. Selected from table 2.4.
Description of the hot water preparation and regulation system
h.w.
Central heat substation 0,6
Building heat substation + manual temperature control 0,8
Building heat substation + automatic temperature control 0,95
Building boiler-house + manual temperature control 0,7
Building boiler-house + automatic temperature control 0,8
Gas heater in the apartment 0,75
Electric heater in the apartment 0,3
The efficiency factor of the hot water supply system h.w.
Calculation of Energy Performance of Buildings - Lithuanian Case
.....
1......
)(whE
shN
iedventNenvNsumN QQ
QQQQQQ
.....
inf.1......
)(whE
shR
ieRdventRenvRsumR QQ
QQQQQQQ
....
inf1 )(whE
sh
iedventenvsum QQ
QQQQQQQ
21.. sh
Calculation of sum energy consumption of the building
Normative sum QN.sum. (kWh/(m2per year)), reference sum QR.sum. (kWh/(m2
per year)) and calculated sum Qsum (kWh/(m2per year)) :; ( )
BENEFIT-2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings - Lithuanian Casec
BENEFIT-2006, Riga, 25 October, 2006
Description of the heat source 2
District heating, manual temperature control 0,9
District heating, automatic temperature control 1
Gas boiler, manual temperature control 0,8
Gas boiler, automatic temperature control 0,94
Gas radiant heating device 1
Liquid fuel boiler, manual temperature control 0,75
Liquid fuel boiler, automatic temperature control 0,87
Solid fuel boiler, manual temperature control 0,7
Solid fuel boiler, automatic temperature control 0,85
Heating by electricity, manual temperature control 0,9
Heating by electricity, automatic temperature control 1
Heat pump 1,1
Stoves 0,5
Fireplaces 0,4
Calculated efficiency factor of the temperature control devices of the heating system 1
Description of the regulation devices 1
No temperature control devices in the building heating system 0,88
Temperature control in the premises of the building, but only thermostatic valves on the heating devices or only internal or external thermostats are installed.
0,93
Temperature control devices in all the premises of building. Thermostatic valves on the heating devices and internal or external thermostats are installed.
0,98
Temperature control is settled in part of the building.
0,90
The calculated efficiency factor of the heat source 2
No. Type of building [3.2] N.h.s Rh.s.
1One and two storey residential buildings
0,70,83
2 Apartment buildings 0,7 0,90
3 Administrative 0,7 0,83
4 Educational 0,7 0,83
5 Health care 0,7 0,84
6 Restaurants 0,7 0,86
7 Trade 0,7 0,86
8 Sport, except swimming pools 0,7 0,81
9 Swimming pools 0,7 0,83
10 Cultural 0,7 0,82
11Garage, manufacturing and industry
0,70,83
12 Storage 0,7 0,84
13 Hotels 0,7 0,9
14 Service 0,7 0,88
15 Transport 0,7 0,84
16 Recreation 0,7 0,82
17 Special 0,7 0,85
BENEFIT-2006, Riga, 25 October, 2006
Calculation of Energy Performance of Buildings - Lithuanian Casec
No. Type of building [3.2] N.h.s. Rh.s.
Normative N.h.s. and reference Rh.s. heating system efficiency factors, different types of buildings
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Translation of the indices•Building addressBuilding destinationHeated area of buildingBuilding energy performance classification indicatorCalculated summed energy consumption related to 1 m2 heated area of the building (building part)Main heat supply sourceCertificate issue dateBuilding (building part) certificate expiry date Name and surname of expert Expert certificate registration number Expert signature
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
Calculation example:
Apartment building, 3 staircases, 5 stories
Input data: -Heated area 2700 m2;-Window area – 15 % from building heated area;-Ventilation natural;-Domestic hot water supply with manual control;-Temperature control in building heating system is absent;-Energy source - district heating, manual temperature control.
Description of energy consumption typekWh/(m2.per
year)
Transmission heat losses through the external wall 63,67
Transmission heat losses through the roof 21,77
Transmission heat losses through the ceilings over unheated basements and crawls 9,14
Transmission heat losses through the windows 36,28
Transmission heat losses through the doors, except opening losses 0,59
Transmission heat losses through the thermal bridges 13,94
Transmission heat losses due to external door opening 0,90
Energy losses doe to ventilation 24,04
Heat losses due to over-infiltration of external air 29,19
Solar heat gains 19,31
Internal heat gains 14,12
Electricity consumption in building 21,00
Energy consumption for domestic hot water supply 25,00
Building sum energy consumption without heating system efficiency assessment 212,09
Building sum energy consumption with of heating system efficiency assessment 255,71
Calculation of Energy Performance of Buildings - Lithuanian Case
BENEFIT-2006, Riga, 25 October, 2006
0
50
100
150
200
250
300
Wal
ls
Roo
f
Cei
lings
inco
ntac
tC
eilin
gsov
er c
raw
ls
Win
dow
s
Doo
rs
The
rmal
brid
ges
Doo
rop
enin
g
Ven
tilat
ion
Air
ove
r-in
filtr
atio
nSo
lar
heat
gain
sIn
tern
alhe
at g
ains
Ele
ctri
city
Dom
estic
hot w
ater
Sum
with
out
Sum
with
heat
ing
Ene
rgy
cons
umpt
ion,
kW
h/(m
2 p
er y
ear)
Normative
Reference
Calculated
Energy consumption lay-out for 5-story apartment building
Calculation of Energy Performance of Buildings - Lithuanian Case
Calculation program window with the part of input data and calculation results.
Building data:Destination – residentialHeated area- 175,22 m2Height – 4,2 mWalls, windows, doors by facades:External door descriptionDHW supply system- gas heaterEnergy consumption – 213,76Classification indicator value – 0,80Energy performance class - B
BENEFIT-2006, Riga, 25 October, 2006