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[email protected] • ENGR-36_Lec-07_Moments_Intro.ppt1
Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Engineering 36
Chp 4: Intro to
Moments
[email protected] • ENGR-36_Lec-07_Moments_Intro.ppt2
Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment (Torque) Described
In Physics and Engineering a MOMENT is a measure of TWISTING Power
The MAGNITUDE of a Moment is the PRODUCT of a Lever Arm Distance and an Intensity• The “Intensity” can be a Force, an Electric
Charge, an Area, a Mass, or other• In Engineering Mechanics
the Intensity takes the form of a Force
[email protected] • ENGR-36_Lec-07_Moments_Intro.ppt3
Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment Described
In General, MOMENTS are VECTOR Quantities with Magnitude (see previous slide) and Direction
The Direction of the Moment Vector is determined by the Right Hand Rule• Wrap Fingers in the Direction of
ROTATION (or tendency to rotate), then THUMB points in the Direction of the Moment Vector
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment Center
The MOMENT CENTER is equivalent to the PIVOT POINT about which Rotation would occur upon application of a Force whose Line of Action is OFFSET from the Pivot Point
Moment Center (MC)or Pivot Point
distance from the Pivot to Force Loa
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Position Vector
The Position Vectorruns from theMoment Center toANY Point on theLoA of the Force• Often times the most Convenient Point on
the LoA is the Point of Application (PoA)– i.e., Pos. Vector runs from the Pivot to the PoA
The position Vector Contains within it the “LeverArm” part of the Moment Calc
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Picking the Position Vector, r
Often the Most Convenient Position Vector is that which runs From the Pivot to the Point of Application
r runs from the Pivot to the Point
OTHER Pts on the Force LoA may be more easily determined and are thus More Convenient
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Shortest Position Vector
The Shortest vector is that which is to the Force LoA
The Mag of the Shortest r is called the Perpendicular Distance, d:
distance yields Shortest r
minrd
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment Magnitude
As Noted Previously the Magnitude of a Moment is related to the product of• The Position Vector, r• The Force, F
r
Mathematically
FdM FsinrsinFrM
• Thus knowing F & d allows Calc of the Moment magnitude, but NOT its SENSE (direction)
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment Sense
TWO-DIMENSIONAL STRUCTURES Have Length And Breadth But Negligible Depth And Are Subjected To Forces Contained In The PLANE Of The Structure The Plane Of The Structure Contains The Point O And The Force F. MO, The Moment Of The Force About O Is Perpendicular To The Plane.
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment Sense/Direction
If The Force Tends To Rotate The Structure CLOCKWISE, The Sense Of The Moment Vector Is INTO The Structure Plane• SIGN{MO} → NEGATIVE
If The Force Tends To Rotate The Structure COUNTER-clockwise, The Sense Of The Moment Vector Is OUT Of The Structure Plane • SIGN{MO} → POSITIVE
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment Direction by Rt Hand Rule
1. Point Fingers in r Direction
2. Curl Fingers Toward +F Direction
3. THUMB Points in the Direction of M
k̂
k̂
HINT:Put r & FTail-to-Tail
rF
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moments Point in ALL Directions Since r and F
can be arbitrarily oriented relative to the CoOrd Axes, then M will also be arbitrarily Oriented
• Confirm These using your own Right Hand
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Moment Units Force • Dist
Discern the UNITS for Moments from
FdM FsinrsinFrM
ForceDistanceMUnits
Typical Units• Ft-lbs• In-lbs• N-m• N-mm
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Example: Moment Calculation A 100-lb Vertical Force Is Applied To
The End Of A Lever Which Is Attached To a Shaft At O. DETERMINE
a) Moment About O
b) Horizontal Force At Pt-A Which Creates The SAME Moment
c) Smallest Force At Pt-A Which Produces The SAME Moment
d) Location For a 240-lb Vertical Force To Produce The SAME Moment
e) Whether Any Of The Forces From b, c, and d is EQUIVALENT To The ORIGINAL Force
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Example M Calc – Soln (a) Moment About O Is Equal To The Product
Of The Force And The PERPENDICULAR DISTANCE Between The Line Of Action Of The Force And O
The Force Tends To Rotate The Lever CLOCKWISE, Thus The Moment Vector points INTO The Plane Of The Paper• The Moment Vector Qty is thus NEGATIVE
in. 12lb 100
in. 1260cosin.24
O
OO
M
d
FdMMin lb 1200 OM
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Example M Calc – Soln (b) Horizontal Force at A That Produces
The Same Moment
in. 8.20
in. lb 1200
in. 8.20in. lb 1200
in. 8.2060sinin. 24
F
F
FdM
d
O
lb 7.57F
60
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Example M Calc – Soln (c) The Smallest Force at A To Produce
The Same Moment Occurs When The Perpendicular Distance is a Maximum • i.e., When F Is Perpendicular To OA
in. 42
in. lb 1200
in. 42in. lb 1200
F
F
FdMO
lb 50F
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Example M Calc – Soln (d) To Determine The Point Of Application
Of A 240 lb Vertical Force To Produce The Same Moment
in. 5cos60
in. 5lb 402
in. lb 1200
lb 240in. lb 1200
dOB
d
d
FdMO
in. 10OB
cos60in. 5or OB
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Example M Calc – Soln (e) Although Each Of The Forces In Parts b),
c), and d) Produces The Same Moment As The 100 lb Force, NONE Are of The Same MAGNITUDE And SENSE (Line of Action) as the original pull
\ NONE Of The Forces Is Equivalent To The 100 lb force
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
WhiteBoard Work
Let’s WorkProblem
4.21
In order to pull out the nail at B, the force F exerted on the handle of the hammer must produce a clockwise moment of 500 in∙lb. about point A. Determine the required magnitude of force F.
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
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Bruce Mayer, PE Engineering-36: Engineering Mechanics - Statics
Bruce Mayer, PELicensed Electrical & Mechanical Engineer
Engineering 36
Appendix