b_lecture14 stability in the frequency domain and relative stability automatic control system

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Stability in the Frequency Domain

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Automatic control System

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  • Stability in the Frequency Domain

  • In previous chapters, we discussed stability and developed various tools to determine stability.

    For a control system, it is necessary to determine whether the system is stable.

    To determine the stability of a closed-loop system, we must investigate the characteristic equation of the system.

    Introduction

    0)()(1)( sHsGsF

    )(sG

    )(sH

    Characteristic Equation

  • To ensure stability we must ascertain that all the zeros of F(s) lie in the left hand of s-plane.

    A frequency domain stability criterion was developed by H.Nyquist in 1932.

    The Nyquist stability criterion is based on a theorem in the theory of the function of a complex variable due to CauchyThe argument principle (Cauchys theorem)

    Introduction

  • The Nyquist Criterion

    A closed loop system is stable if Z=0, where Z=P-2N P is the number of open-loop poles of G(s)H(s) in the right-hand of s-plane. N is the number of counterclockwise

    encirclements of the (-1, j0) point

    for the positive frequency

    value( ). Z is unstable poles of the system.

    G(s)H(s)

    0 -1

    Re

    Im

    0

    A method to investigate the stability of a system in terms of the open-loop frequency response.

    It is sufficient and necessary condition of the stability of the linear systems.

  • Consider a unity-gain feedback system whose open-loop transfer function is as follows

    1

    2)(

    ssG

    Stable

    1P2

    1N

    02 NPZ

    2 1

    G(s)

    0

    Example 1

    A system is stable if Z=0, where Z=P-2N P is the number of open-loop poles of G(s)H(s) in the right-hand of s-plane. N is the number of counterclockwise encirclements of the (-1, j0) point

    for the positive frequency value. Z is unstable poles of the system.

  • Consider a unity-gain feedback system whose open-loop transfer function is as follows

    1

    5.0)(

    ssG

    Unstable

    1P 0N

    12 NPZ

    1

    5.0

    G(s)

    0

    Example 2

    There is one unstable pole of the system is in the right-hand of s-plane.

  • Consider a single-loop control system, where open-loop transfer function is

    )11.0)(1(

    100)()(

    sssHsG

    0 ,0 NP

    02 NPZ

    Stable

    G(s)H(s)

    1

    0

    Example 3

  • Consider a single-loop control system, where open-loop transfer function is

    )42()(

    2

    sss

    KsG )(sG

    Determine the limiting value of K in order to maintain a stable system.

    Example 4

    2n000 1809090)( njG

    142

    )2(

    K

    jG

    In order to maintain a stable system

    8K

    The changes of the open-loop gain only alter the magnitude of G(j)H(j).

    1

  • G(j)H(j) locus traverses the left real axis of the point (-1, j0) in G(j)H(j)-plane L()0dB and () =180o in Bode diagram

    )()(

    GHL lg20

    1 2 3

    GH

    )0( LNNN

    1

    2 3 0

    1

    )( )(

    NNN

    Application of the Nyquist criterion in the Bode diagram

  • Application of the Nyquist criterion in the Bode diagram

    We have the Nyquist criterion in the Bode diagram : The sufficient and necessary condition of the stability of the linear closed loop systems is : When vary from 0+ , the number of the net positive traversing is P/2.

    Here: the net positive traversing Nthe difference between the number of the positive traversing and the number of the negative traversing in all L()0dB ranges of the open-loop systems Bode diagram. N=N+-N-

    positive traversingN+ () traverses the -180o line from below to above in the open-loop systems Bode diagram; negative traversing N- () traverses the -180o line from above to below.

    )()(

    GHL lg20

    1 2 3

    GH

    )0( LNNN

    1

    2 3 0

    1

    )( )(

    NNN

  • The Bode diagram of a open-loop stable system is shown in Fig., determine whether the closed loop system is stable.

    In terms of the Nyquist criterion in the Bode diagram:

    Because the open-loop system is stable, P = 0 .

    The number of the net positive traversingis 0 ( P/2 = 0 ).

    The closed loop system is stable .

    Solution

    0dB, 0o

    )(L20

    40

    60

    40

    20

    40

    60

    270o

    90o

    L()

    ()

    180o )(

    )(

    Application of the Nyquist criterion in the Bode diagram

  • The Nyquist criterion provides us with suitable information concerning the absolute stability and, furthermore, can be utilized to define and ascertain the relative stability of a system.

    The Nyquist stability criterion is defined in terms of (-1,0) point on the polar plot or the (0dB, -1800) point on the Bode diagram. Clearly the proximity of the -locus to this stability point is a measure of the relative stability of a system.

    In frequency domain, the relative stability could be described by the gain margin and the phase margin.

    Relative Stability and the Nyquist Criterion

    )()( jHjG

  • The gain margin is defined as

    |)()(|

    1

    gg jHjGh

    The phase margin is

    Gain margin and phase margin

    (dB) )()(lg20lg20 ggn jHjGhL or

    )()(1800 cc jHjG

    GHg

    j

    0

    [GH]

    gGHlg 20

    L

    0

    GHGH

    L

    (a) (b)

    c

    c

    -1

    g

    uencysover freqPhase-crosjHjGg

    180)()( : 0g

    encyover frequGain-crossjHjGc

    c 1)()( :

    The geometrical meanings is shown in this Figure

  • Re 1

    Im

    1/h

    stable

    Critical stability

    unstable

    The physical signification : h amount of the open-loop gain that can be allowed to increase before the closed-loop system reaches to be unstable.

    For the minimum phase system: h>1 the closed loop system is stable .

    amount of the phase shift of G(j)H(j) to be allowed before the closed-loop system reaches to be unstable.

    For the minimum phase system: >0 the closed loop system is stable.

    Gain margin and phase margin

  • )12.0)(1(

    1)()(

    jjjjHjG

    Gain margin

    Phase margin

    Example

  • Example

    A unity-gain feedback system whose open-loop transfer function is :

    try to find gain margin and phase margin.

    )102.0)(15.0(

    10)(

    ssssG

    2

    50c

    [-20][-40]

    [-60]

    180

    270

    90

    dbjG )(lg20 )( / jG

    )( jG

    )(lg20 jG

    )/1( s

    hLg

    (1) , 20lg ( ) 0 4.47c c cwhen G j

    180 ( )

    180 90 (0.5 ) (0.02 )

    19

    c

    c c

    G j

    arctg arctg

    (2) = , ( ) 180g gwhen G j

    90 (0.5 ) (0.02 ) 180g garctg arctg

    [ (0.5 ) (0.02 )] 90g gtg arctg arctg tg

    10g

    20lg ( ) 14h gL G j db

    gain margin is 190

    phase margin is 14 dB