Bingo Review Game

This review game allows the students an opportunity to review the material and still have

fun while learning. I used this during Student Teaching 1 in Algebra AB at Seward High School.

The students enjoyed being able to review the material in a more fun way than just going over

problems that would not give them any reward while reviewing.

To begin, each student is given a blank “bingo board,” such as the one on the next page.

They were then able to randomly put the numbers from 1 through 25. This gives them the

opportunity to make their board unique from all the others. I split them in to groups of 2 or 3.

This gave them the opportunity to help each other out if they did not understand how to solve the

problem. The students had to write down their own work and solutions on a separate sheet of

paper in order to get credit if they got a bingo. I had a PowerPoint presentation that had all the

problems and answers on it. To choose the next problem I used a random number generator to

choose the next problem. They were giving 2 minutes to solve the problem given. After the 2

minutes I showed the answer and if they got it right they would mark off the problem on their

sheet.

Contained in this document is a pdf of a blank bingo sheet and a pdf of the PowerPoint

that I used while at Seward High School.

Chapter 4 Review

BINGO

1 2 3 4 56 7 8 9 10

11 12 13 14 1516 17 18 19 2021 22 23 24 25

Question 1Plot these points and describe the location.

A(-2, 0) B(0 ,0) C(-1 ,-1) D(2 ,-3)

A Negative x-axis B Origin C Quadrant 3 D Quadrant 4

Question 2Graph the equation using an

x-y chart

-2x + y = 3

x -2 -1 0 1 2

2x - 3 2(-2) - 3 2(-1) - 3 2(0) - 3 2(1) - 3 2(2) - 3

y -7 -5 -3 -1 1

Question 3Write in slope-intercept form, name the slope and y-

intercept

y - x = 0

y = x Slope: 1

y-intercept: 0

Question 4Graph using slope-intercept form

y = 5x - 3

Question 5Evaluate the Function when x = -2, 0, 3

p(x) = -8x - 2

p(-2) = 14 p(0) = -2

p(3) = -26

Question 6Evaluate the Function when x = -2, 0, 3

h(x) = 3/4x - 6

h(-2) = -7.5 h(0) = -6

h(3) = -3.75

Question 7Find the value of x so that the function has the given

value.

m(x) = 9x - 5; -2

x = 1/3

Question 8Graph with the given intercepts

x: 3

y: 5

Question 9Find the slope between the two given points

(6, -1) (-2, 2)

-3/8

Question 10Plot these points and describe the location.

A(3, 2) B(2, 5) C(0, 4) D(-2 , 2)

A Quadrant 1 B Quadrant 1 C Positive y-axis D Quadrant 2

Question 11Find the x and y intercepts using the zeros method

3x + 2y = 6

2(0) + 7y = 28 2x + 7(0) = 28 y = 4 x = 14

Question 12Which of these points would be on the line

y = 4/3x + 2

(-1, -2) (-3, -2) (3, 6) (1, 1)

(-3,-2) (3, 6)

Question 13Graph using slope-intercept form

3x - 3y = 12

Question 14Write in slope-intercept form, name the slope and y-

intercept

-12x -4y = 2

y = -3x -1/2 Slope: -3

y-intercept: -1/2

Question 15Find the value of x so that the function has the given

value.

g(x) = -x + 5; 2

x = 3

Question 16Evaluate the Function when x = -2, 0, 3

d(x) = -3/2x + 5

d(-2) = 8 d(0) = 5

d(3) = .5 or 1/2

Question 17Find the value of x so that the function has the given

value.

p(x) = -12x -36; -3

x = -2.75 or -11/4

Question 18Graph with the given intercepts

x: 9 y: -1

Question 19Find the x and y intercepts using the zeros method

-3x + 5y = -15

-3(0) + 5y = -15 -3x + 5(0) = -15 y = -3 x = 5

Question 20Find the slope between the two given points

(-1, 1) (4, 1)

0/5 = 0

Question 21Find the slope between the two given points

(5, 3) (2, -1)

4/3

Question 22Write in slope-intercept form, name the slope and y-

intercept

2x + 5y = -10

y = -2/5x - 2 Slope: -2/5

y-intercept: -2

Question 23Plot these points and describe the location.

A(-3, -2) B(4, -2) C(3, 0) D(1, -2)

A Quadrant 3 B Quadrant 4 C Positive x-axis D Quadrant 4

Question 24Find the slope between the two given points

(1, 5) (1, -2)

7/0 undefined

Question 25Graph with the given intercepts

x: -2 y: -6