bellwork 9-14-15. unit 1 quiz sept 2015 simplify each expression #1-5. write the problem and answer....
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Bellwork 9-14-15
Unit 1 Quiz Sept 2015Simplify each expression #1-5. Write the problem and answer.
1: -½ ( ¼ x + 10)2: 8y – 2x + y + 5y3: 9ab + 3a2 + 5ab + 4a2
4: (2x2y + 4xy – 7) – (3x2y – 7xy + 10)5.
6: (Do not have to copy problem.) If a rectangle has length x2+4, and the width is shorter by 3, what is the perimeter?
Bellwork Solutions 9-14-15
Definition: Linear Equation
Let a and b be real numbers such that a ≠ 0. A linear equation in one variable is an equation that can be written in the form
ax + b = 0
Linear Equations in One Variable
• An equation is a statement that indicates that two quantities are equal. It must have an equal sign separating two parts.
• A solution to an equation is a value of the variable that makes the equation a true statement.
• Substituting a solution to an equation for the variable makes the right-hand side equal to the left-hand side.
Linear Equations in One Variable
Equation Solution Check
x = -4 -4 (-4) = -4
p + 3 = 11 8 (8) + 3 = 11
-2b = -20 10 -2(10) = -20
Addition & Subtraction Properties of Equality
Let a, b, and c represent real numbers.
Addition property of equality: If a = b, then a + c = b + c.
Subtraction property of equality: If a = b, then a - c = b - c.
Multiplication & Division Properties of Equality
Let a, b, and c represent real numbers.
Multiplication property of equality:If a = b, then a • c = b • c.
Division property of equality:If a = b, then a/c = b/c (provided c ≠ 0).
Procedure for Solving a Linear Equation in One Variable
Step 1: Simplify both sides of the equation.a) Clear parentheses.b) Consider clearing fractions or decimals (if any are
present) by multiplying both sides of the equation by a common denominator of all terms.
c) Combine like terms.
Procedure for Solving a Linear Equation in One Variable
Step 2: Use the addition or subtraction property of equality to collect the variable terms on one side of the equation.
Step 3: Use the addition or subtraction property of equality to collect the constant terms on one side of the equation.
Procedure for Solving a Linear Equation in One Variable
Step 4: Use the multiplication or division property of equality to make the coefficient of the variable term equal to 1.
Step 5: Check your answer!
9-14-15 HW – Lesson 1.41 step equations. Solve for the
variable. Show work!1. 12 + x =402. -3/5 p = 4/153. 4 = w/2.24. -x = 65. -6/5 y = -3/56. 5 = t/167. -a = -2
Mon. 9-14-15 HW Problems Solutions 1step equations
• 1. x=28• 2. p= -4/9• 3. 8.8=w• 4. x= -6• 5. y= ½• 6. 80=t• 7. a=2
Wedn. 9-17-14 Homework
Intermediate Algebra textbook pp. 46-47 #15-25 odds
Complete before leaving or can be found on website: uhstitans.com/carruthers-latrease
Bellwork 9/18
• Show the “check” work to see if the solution is correct.
3(y – 4) = 2y – 5 y = - 7
Warm Up 9/18
Solve the equation:
¼ w + 1/3 w – 1 = ½ (w – 4)
Remember: the fractions in this equation can be eliminated by multiplying both sides of the equation by any common multiple of the denominators.