beam lecture
TRANSCRIPT
![Page 1: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/1.jpg)
1
Introduction to Beams
• A beam is a horizontal structural member used to support loads
• Beams are used to support the roof and floors in buildings
![Page 2: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/2.jpg)
2
Introduction to Beams
• Common shapes are
I Angle Channel
• Common materials are steel and wood
Source: Load & Resistance Factor Design (First Edition), AISC
![Page 3: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/3.jpg)
3
Introduction to Beams• The parallel portions on an I-beam or H-beam are
referred to as the flanges. The portion that connects the flanges is referred to as the web.
FlangesWeb
Flanges
Web
![Page 4: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/4.jpg)
4
Introduction to Beams
• Beams are supported in structures via different configurations
Source: Statics (Fifth Edition), Meriam and Kraige, Wiley
![Page 5: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/5.jpg)
5
Introduction to Beams
• Beams are designed to support various types of loads and forces
Concentrated Load Distributed Load
Source: Statics (Fifth Edition), Meriam and Kraige, Wiley
![Page 6: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/6.jpg)
6
Beam Theory• Consider a simply supported beam of
length, L. The cross section is rectangular, with width, b, and depth, h.
L
b
h
![Page 7: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/7.jpg)
7
Beam Theory• An area has a centroid, which is similar to a center of
gravity of a solid body.• The centroid of a symmetric cross section can be easily
found by inspection. X and Y axes intersect at the centroid of a symmetric cross section, as shown on the rectangular cross section.
h/2
h/2
b/2 b/2
X - Axis
Y - Axis
![Page 8: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/8.jpg)
8
Beam Theory• An important variable in beam design is the moment of
inertia of the cross section, denoted by I.• Inertia is a measure of a body’s ability to resist rotation.• Moment of inertia is a measure of the stiffness of the
beam with respect to the cross section and the ability of the beam to resist bending.
• As I increases, bending and deflection will decrease.• Units are (LENGTH)4, e.g. in4, ft4, cm4
![Page 9: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/9.jpg)
9
Beam Theory• I can be derived for any common area using calculus.
However, moment of inertia equations for common cross sections (e.g., rectangular, circular, triangular) are readily available in math and engineering textbooks.
• For a rectangular cross section,
• b is the dimension parallel to the bending axis. h is the dimension perpendicular to the bending axis.
12bh3
x I
b
h
X-axis (passingthrough centroid)
![Page 10: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/10.jpg)
10
Beam Theory• Example: Calculate the moment of inertia about the X-
axis for a yardstick that is 1” high and ¼” thick.
12bh3
x I
b = 0.25”
h = 1.00” 12
in1.00in 0.25 3
x I
4x in0.02083I
X-Axis
Y-Axis
![Page 11: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/11.jpg)
11
Beam Theory• Example: Calculate the moment of inertia about the Y-
axis for a yardstick that is 1” high and ¼” thick.
h = 0.25”
b = 1.00”
X-Axis
Y-Axis
12bh3
y I
12
in0.25in 1.00 3
y I
4y in0.00130I
![Page 12: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/12.jpg)
12
Beam Theory• Suppose a concentrated load, P, is
applied to the center of the simply supported beam.
P
L
![Page 13: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/13.jpg)
13
Beam Theory• The beam will bend downward as a result
of the load P.
P
![Page 14: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/14.jpg)
14
Beam Theory• The deflection (Δ) is the vertical
displacement of the of the beam as a result of the load P.
Deflection, Δ
L
![Page 15: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/15.jpg)
15
Beam Theory• The deflection (Δ) of a simply supported, center loaded
beam can be calculated from the following formula:
I48EPL
Δ3
where,
P = concentrated load (lbs.)
L = span length of beam (in.)
E = modulus of elasticity (lbs./in.2)
I = moment of inertia of axis perpendicular to load P (in.4)
L
P
![Page 16: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/16.jpg)
16
Beam Theory• Modulus of elasticity, E, is a property that indicates the
stiffness and rigidity of the beam material. For example, steel has a much larger modulus of elasticity than wood. Values of E for many materials are readily available in tables in textbooks. Some common values are
Material Modulus of Elasticity (psi)
Steel 30 x 106
Aluminum 10 x 106
Wood ~ 2 x 106
![Page 17: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/17.jpg)
17
Beam Theory• Example: Calculate the deflection in the steel beam
supporting a 500 lb load shown below.
P = 500 lb
L = 36”
b = 3”
h = 2”
12bh3
II48E
PLΔ
3
![Page 18: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/18.jpg)
18
Beam Theory• Step 1: Calculate the moment of inertia, I.
12bh3
I
12
in2in 3 3
I
4in2I
![Page 19: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/19.jpg)
19
Beam Theory• Step 2: Calculate the deflection, Δ.
I48EPL
Δ3
4
26
3
in 2inlb
10 x 3048
in36lb 500Δ
4
26
3
in 2inlb
10 x 3048
in46656lb 500Δ
in0.0081Δ
![Page 20: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/20.jpg)
20
Beam Theory• These calculations are very simple for a solid, symmetric
cross section.• Now consider slightly more complex symmetric cross
sections, e.g. hollow box beams. Calculating the moment of inertia takes a little more effort.
• Consider a hollow box beam as shown below:
4 in.
6 in.
0.25 in.
![Page 21: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/21.jpg)
21
Beam Theory• The same equation for moment of inertia, I = bh3/12, can
be used.• Treat the outer dimensions as a positive area and the
inner dimensions as a negative area, as the centroids of both are about the same X-axis.
Positive Area Negative Area
X-axisX-axis
![Page 22: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/22.jpg)
22
Beam Theory• Calculate the moment of inertia about the X-axis for the
positive area and the negative area using I = bh3/12. The outer dimensions will be denoted with subscript “o” and the inner dimensions will be denoted with subscript “i”.
bi = 3.5 in.
ho = 6 in.
hi = 5.5 in.
bo = 4 in.
X-axis
![Page 23: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/23.jpg)
23
Beam Theory
bi = 3.5 in.
ho = 6 in.
hi = 5.5 in.
bo = 4 in.
X-axis
12hb 3
oopos I
12hb 3
iineg I
12
in6in 4 3
pos I
12in5.5in 3.5 3
neg I
![Page 24: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/24.jpg)
24
Beam Theory• Simply subtract Ineg from Ipos to calculate the moment of
inertia of the box beam, Ibox
4 in.
6 in.
0.25 in.
negposbox - III
12
in5.5in 3.512
in6in 4 33
box I
4box in23.5I
12hb
12hb 3
ii3
oobox I
12
in166.4in 3.512
in216in 4 33
box I
![Page 25: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/25.jpg)
25
Beam Theory• The moment of inertia of an I-beam can be calculated in
a similar manner.
![Page 26: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/26.jpg)
26
Beam Theory• Identify the positive and negative areas…
Positive Area Negative Area
![Page 27: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/27.jpg)
27
Beam Theory• …and calculate the moment of inertia similar to the box
beam (note the negative area dimensions and that it is multiplied by 2).
bo
hi
bi bi
ho
12hb2
12hb 3
ii3
oo beamII
![Page 28: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/28.jpg)
28
Beam Theory• The moment of inertia of an H-beam can be calculated in
a similar manner…
![Page 29: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/29.jpg)
29
Beam Theory• The moment of inertia of an H-beam can be calculated in
a similar manner…
![Page 30: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/30.jpg)
30
Beam Theory• …however, the H-beam is divided into three positive
areas.
b2
b1
h2 h1
b1
h1
12hb
12hb
12hb 3
113
223
11beam-H I
12hb
12hb2 3
223
11beam-H I
![Page 31: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/31.jpg)
31
Beam Theory• Example: Calculate the deflection in the I-beam shown
below. The I-beam is composed of three ½” x 4” steel plates welded together.
L = 8 ft
P = 5000 lbf
½” x 4” steel plate (typ.)
![Page 32: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/32.jpg)
32
Beam Theory• First, calculate the moment of inertia for an I-beam as
previously shown, i.e. divide the cross section of the beam into positive and negative areas.
bo = 4 in.bi = bi
12hb2
12hb 3
ii3
oo beamII
ho = 5 in. hi = 4 in.
![Page 33: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/33.jpg)
33
Beam Theory• First, calculate the moment of inertia for an I-beam as
previously shown, i.e. divide the cross section of the beam into positive and negative areas.
bo = 4 in.bi =1.75in bi
12
4in1.75in212
5in4in 33
beamII
ho = 5 in. hi = 4 in.
4in 23.0 beamII
![Page 34: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/34.jpg)
34
Beam Theory• Next, calculate the deflection (Esteel = 30 x 106 psi).
I48EPL
Δ3
L = 8 ft
P = 5000 lbf
![Page 35: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/35.jpg)
35
Beam Theory• Calculate the deflection, Δ.
I48EPL
Δ3
4
2f6
3
in 23inlb
10 x 3048
in96lb 5000Δ
4
26
3
in 23inlb
10 x 3048
in884736lb 5000Δ
in0.134Δ
![Page 36: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/36.jpg)
36
Beam Theory• Example: Calculate the volume and mass of the beam if
the density of steel is 490 lbm/ft3.
L = 8 ft ½” x 4” steel plate (typ.)
![Page 37: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/37.jpg)
37
Beam Theory• Volume = (Area) x (Length)
8ft4in0.5in3V ALV
in 962.0in3V 23in 576V
![Page 38: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/38.jpg)
38
Beam Theory• Convert to cubic feet…
33
12in1ft
in 576V
3
33
1728in1ft
576inV
3ft 0.333V
![Page 39: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/39.jpg)
39
Beam Theory• Calculate mass of the beam• Mass = Density x Volume
ρVm
33m 0.333ft
ftlb
490m
mlb 163.3m
![Page 40: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/40.jpg)
40
Materials
• Basswood can be purchased from hobby or craft stores. Hobby Lobby carries many common sizes of basswood. DO NOT purchase balsa wood.
• 1201 teams must submit a receipt for the basswood.
• The piece of basswood in the Discovery Box WILL NOT be used for Project 2.
• Clamps and glue are provided in the Discovery Box. Use only the glue provided.
![Page 41: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/41.jpg)
41
Assembly
• I-beams and H-beams: Begin by marking the flanges along the center where the web will be glued.
• Box beams: No marking is necessary.
• I-beams and H-beams: Apply a small amount of glue along the length of the web and also to the flange.
• Box beams: Apply a small amount of glue two one side and the bottom to form an “L” shaped section.
![Page 42: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/42.jpg)
42
Assembly• I-beams and H-beams: Press
the two pieces together and hold for a couple of minutes.
• Box beams: Press the two pieces together into an “L” shape and hold for a couple of minutes.
• I-beams and H-beams: Clamp the pieces and allow the glue to cure as instructed on the bottle.
• Box beams: Clamp the pieces and allow the glue to cure as instructed on the bottle.
• YOU MUST ALLOW EACH GLUE JOINT TO CURE COMPLETELY BEFORE CONTINUING ON TO ADDITIONAL GLUE JOINTS!
![Page 43: Beam Lecture](https://reader034.vdocuments.us/reader034/viewer/2022051014/55285c7c49795912048b47b2/html5/thumbnails/43.jpg)
43
Assembly• Stiffeners may be applied to the
web of an I or H beam or between sides of a box beam.
• Stiffeners are small pieces of wood that aid in gluing and clamping the beam together.
• Stiffeners may be necessary if the pieces of wood that the team has chosen are thin (less than ~3/16”). Thin pieces of wood may collapse when clamped together.
• Stiffeners keep the flanges stable during clamping and glue curing.