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    Energy Bands in SolidsEnergy Bands in Solids

    Physics 355Physics 355

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    Consider the available energies for electrons in the materials.

    As two atoms are brought

    close together, electrons

    must occuy different

    energies due to Pauli

    E!clusion rincile.

    "nstead of having discrete

    energies as in the case of

    free atoms, the available

    energy states form bands.

    Conductors, "nsulators, and Semiconductors

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    #ree Electron #ermi $as#ree Electron #ermi $as

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    ==

    m

    kE

    2

    22

    #or free electrons, the

    wavefunctions are lane

    waves%

    )rk()r(

    ie

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    Band $a

    &one boundary

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    'doed('thermally

    e!cited(

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    )

    *rigin of the Band $a

    +o get a standing wave at the boundaries, you cantae a linear combination of two lane waves%

    axiikx

    axiikx

    ee

    ee

    /2

    /1

    =

    =

    =+=+= +a

    xee axiaxi

    cos2//21

    / /

    1 2 2 sini x a i x a x

    e e ia

    = = =

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    *rigin of the Band $a

    Electron -ensity

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    *rigin of the Band $a

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    Bloch #unctions

    #eli! Bloch showed that the actualsolutions to the Schrdinger e/uation for

    electrons in a eriodic otential must have

    the secial form%

    where uhas the eriod of the lattice, that

    is

    )rk(kk )r()r( = ieu

    )Tr()r( kk +=uu

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    0ronig1Penney 2odel

    a+b4 b a a+b

    U!4

    x

    U0

    +he wave e/uation can be solved when the otential is

    simle... such as a eriodic s/uare well.

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    0ronig1Penney 2odel

    =+ )(2 2

    22xU

    dx

    d

    m

    Region I - where 0 < x< aand U= 0

    The eigenfunction is a linear comination of !lane wa"estra"eling oth left and right#

    The energ$ eigne"alue is#

    iKxiKx BeAe +=

    m

    K

    2

    22

    =

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    Region II - where b< x< 0 and U= U0%ithin the arrier& the eigenfunction looks like this

    and

    QxQx DeCe +=

    m

    QU

    2

    22

    0

    =

    0ronig1Penney 2odel

    =+ )(2 2

    22xU

    dx

    d

    m

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    0ronig1Penney 2odel

    a+b4 b a a+b

    U!4

    x

    U0

    +o satisfy 2r. Bloch, the solution in region """

    must also be related to the solution in region "".

    III III

    )( baik

    IIIII e

    +

    =

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    0ronig1Penney 2odel

    A,B,C, and - are chosen so that both the wavefunctionand its derivative with resect toxare continuous at

    thex6 and a.

    Atx6 ...

    Atx = a...

    )()( DCQBAiKDCBA = +=+

    )( baikIIIII e

    +=

    )()( baikQbQbiKaiKa eDeCeBeAe + +=+

    ( ) ( ) )( baikQbQbiKaiKa eDeCeQBeAeiK + =

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    0ronig1Penney 2odel

    )(coscoscoshsinsinh2

    22

    bakKaQbKaQbQK

    KQ+=+

    +7esult for E8 U%

    +o obtain a more convenient form 0ronig and Penney considered the

    case where the otential barrier becomes a delta function, that is, the

    case where Uis infinitely large, over an infinitesimal distance b, but the

    roduct U0bremains finite and constant.

    02 UQ

    and also goes to infinity as U. +herefore%

    222

    0

    )('im QKQ

    U

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    0ronig1Penney 2odel9hat haens to the roduct Qbas Ugoes to infinity:

    ; bbecomes infinitesimal as Ubecomes infinite.

    ; >

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    0ronig1Penney 2odel

    =2

    2baQP kaKaKaKaP coscossin =+

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    0ronig1Penney 2odel

    = 3 ka ka

    Plot of energy versus

    wavenumber for the

    Kronig-Penney Potential,

    with P = !".

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    Crucial to the

    conduction rocess

    is whether or notthere are electrons

    available for

    conduction.

    Conductors, "nsulators, and Semiconductors

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    Conductors, "nsulators, and Semiconductors

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    Conductors, "nsulators, and Semiconductors

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    Conductors, "nsulators, and Semiconductors

    'doed('thermally

    e!cited(