balanced path decompositions of crowns and directed crowns hung-chih lee and shun-li hsu department...
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Balanced Path Decompositions of Crowns and Directed Crowns
Hung-Chih Lee and Shun-Li Hsu
Department of Information Technology
Ling Tung University
Taichung, Taiwan 40852, R.O.C.
Introduction H-decomposition of G
Balanced H-decomposition of G
kk PP
path directed and Path
kP
*,, crown directed and Crown lnln CC
H-decomposition of G
Let G and H be graphs (digraphs) . An H-decomposition of G is a partition of the edge (arc) set of G into subsets each of which induces a graph (digraph) isomorphic to H.
If G has an H-decomposition, then we say H decomposes G, denoted by H|G.
kP
Balanced H-decomposition of G
An H-decomposition of G is balanced if each vertex of G belongs to the same number of members in the decomposition.
We write H||G If G admits a balanced H-decomposition.
kP
Crown :lnC , },,,,,,,{)( 110110, nnln bbbaaaCV
)}(mod1,,1,,1,,1,0:{)( , nliiijnibaCE jiln
)3,5(3,5 lnC
0a 4a2a 3a1a
0b 1b 2b 3b 4b
Directed crown
e
eCC lnln
of sendvertice theconnecting arcs opposite by two
edgeeach replacingby from obtainedgraph the: ,*,
1a 2a0a
0b 1b 2b*
2,3C
0a 2a1a
0b 1b 2b
2,3C
Notations
Eaxmple
)}(:{)(
,)}(:{)}(:{)(
with ofsubgraph thedenotes Then
.Let
,
,
GEbabatGE
GVbbGVaatGV
CtG
CG
jititi
itiiti
ln
ln
Notations
Example
)}(:{
)}(:{)(
,)}(:{)}(:{)(
with ofsubgraph thedenotes Then
.Let *,
*,
GAabab
GAbabatGA
GVbbGVaatGV
CtG
CG
srtstr
jititi
itiiti
ln
ln
Notations
))()((
.)()( and )()(with
(digraph)sgraph thedenotes , ,
Then .(digraphs) graphs be ,,,Let
1
11
121
21
m
ii
m
ii
m
ii
m
iim
m
FAFA
FEFEFVFV
FFFFF
FFF
Proof of Theorem A
(Necessity) Cn,l is l-regular and by Lemma 2.5
(Sufficiency) 2(k - 1)|lk ⇒ k - 1|l Case 1. k is even
By Lemma 2.2, it suffices to show 1
21
222
2
3120:Let
kkkkkk babababaW
|)1(2|| , lkkCP lnk
1,|| knk CP
ion.decomposit required theis }1,,1,0:{ nttW
0,1,2,,4,3,2 :label kkk
)4,3,5( ofion decomposit- Balanced 3,54 klnCP
0a 4a2a 3a1a
0b 1b 2b 3b 4b
)even ( ofion decomposit- Balanced , kCP lnk
Base graph
0a 1a
1b 2b
0 12
Proof of Theorem A Case 2. k is odd
2(k - 1)|lk ⇒ 2(k - 1)|l. By Lemma 2.2,
it suffices to show
2
1
2
1
2
3
2
13120:Let kkkkkk ababbabaP
|)1(2|| , lkkCP lnk
)1(2,|| knk CP
0,1,2,,4,3,2 :label kkk
Proof of Theorem A
2
53
2
3
2
33
2
5142032:Let kkkkkk babaababQ
|)1(2|| , lkkCP lnk
ion.decomposit required theis
}1,,1,0:,{ nttQtP
1,,1,,52,42,32 :label kkkkkk
)3,4,5( ofion decomposit- Balanced 4,53 klnCP
0a 4a2a 3a1a
0b 1b 2b 3b 4b
) odd( ofion decomposit- Balanced , kCP lnk
0a 1a
1b 2b 3b
0 21
3
Baes graph
Proof of Theorem B
(Necessity) C*n,l is 2l-regular and by Lemma 2.5
(Sufficiency) Case 1. 2(k - 1)|lk
By Theorem A, there exists a balanced Pk-decomposition of C*
n,l
Replace each edge in Cn,l by two arcs with opposite directions⇒ each Pk in becomes two with opposite directions ⇒ Done.
lkCP lnk |)1(|| *,
sPk '
ofion decomposit- Balanced *3,54 CP
0a 4a2a 3a1a
0b 1b 2b 3b 4b
) |)1(2( ofion decomposit- Balanced *, lkkCP lnk
Base graph
0a 1a
1b 2b
02 1
0a 1a
1b 2b
102
Replace each edge in the crown by two arcs with opposite directions
Proof of Theorem B Case 2.
lkCP lnk |)1(|| *,
odd is |)1(2 and |1 klkklk
lkk |)1(2
2
1
2
1
2
3
2
13120:Let kkkkkk ababbabaP
0,1,2,,4,3,2 :label kkk
Proof of Theorem B
lkCP lnk |)1(|| *,
2
3
2
3
2
1
2
51302:Let kkkkkk babaababQ
0,1,2,,4,3,2 :label kkk
ion.decomposit required theis
}1,,1,0:,{ nttQtP
ofion decomposit- Balanced *
2,33 CP
) |)1(2(
ofion decomposit- Balanced *,
lkk
CP lnk
3a
1b 2b 3b
2a1aBase graph
2a1a
Previous results Path decomposition
Tarsi( 1983 ) Truszczyński ( 1985 ) Shyu and Lin( 2003 ) Meszka and Skupień ( 2006 )
Balanced path decomposition Bermond ( 1975 ) Hung and Mendelsohn( 1977 )
Our object
Find the necessary and sufficient conditions for
kP
lnk CP , ofion decomposit- Balanced
*, ofion decomposit- Balanced lnk CP
Main results Main results
Necessary condition - Counting Method
Sufficient condition - Construction Method
lnk CP , ofion decomposit- Balanced
*, ofion decomposit- Balanced lnk CP
Procedure of the proof Labeling the edges of the crown Find a base graph (path)
k is even k is odd
2(k-1) does not divide lk
Shifting the base graph
lnk CP , ofion decomposit- Balanced
*, ofion decomposit- Balanced lnk CP
lkk |)1(2
Future works Find the necessary and sufficient conditions for
lnk CP , ofion decomposit- Balanced *, ofion decomposit- Balanced lnk CP
),( ofion decomposit- Balanced * rnKPk
),( ofion decomposit- Balanced rnKPk