atomic theory of matter we now take for granted the idea that all matter is comprised of atoms. but...
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Atomic Theory of Matter
We now take for granted the idea that all matter is comprised of atoms.
But how did the Atomic Theory of Matter develop, and how was it proved?
The notion that matter was made up of atoms had to be postulated and proved.
Experimental Evidence
Experimental evidence for the atomic nature of matter was realized in the 18th century.
Since then scientists have proved conclusively the atomic nature of matter
In the mid ‘80’s a tool was developed which for the first time allowed scientists to actually “see” individual atoms and molecules.
Surface of graphite as imaged by a scanning tunneling microscope
http://www.columbia.edu/cu/chemistry/groups/flynn/
Law of Conservation of Mass
1775 - Lavoisier
“Father of Modern Chemistry”
In every chemical operation an equal amount of matter exists before and after the operation.
Mass is conserved, the total mass after the chemical operation must be the same as that before.
Problem
Potassium chlorate (KClO3) decomposes to potassium chloride (KCl) and oxygen (O2) when heated. In one experiment 100.0 g of KClO3 generated 36.9g of O2 and 57.3 g of KCl. What mass of KClO3 remained unreacted?
Mass of KClO3 before reaction = mass of KCl + mass of O2 + mass of unreacted KClO3
100.0 g of KClO3 = 57.3 g KCl + 36.9g O2 + g unreacted KClO3
g unreacted KClO3 = 100.0 g - 57.3 g - 36.9 g
= 5.8 g
Law of Definite Proportions
Joseph Proust
In a given chemical compound, the proportions by mass of the elements that compose it are fixed, regardless of the source of the compound.
The ratio of elements in a compound is fixed regardless of the source of the compound.
Water is made up of 11.1% by mass of hydrogen and 88.9% oxygen.
Problem
In a set of experiments very pure tin (Sn) was combined with bromine (Br) forming tin tetrabromide (SnBr4). Using the data below, confirm the law of definite proportions by calculating the % of tin in each sample of SnBr4.
Grams of Sn reacted Grams of SnBr4 formed
2.8445 10.4914
3.0125 11.1086
4.5236 16.6752
Need to determine (mass of Sn reacted)
(mass of Br reacted)
Mass of Br reacted = Mass of SnBr4 formed - mass of Sn reacted
Grams of Sn reacted Grams of Br reacted2.8445 10.4914 - 2.8445 = 7.64693.0125 11.1086 - 3.0125 = 8.09614.5236 16.6752 - 4.5236 = 12.1516
(mass of Sn reacted)
(mass of Br reacted)
0.3721
0.3721
0.3723
Dalton’s Atomic Theory
•All matter consists of indivisible atoms
• Atoms of one kind of element are identical in mass and properties; atoms of different kinds of elements are different•Compounds are made up of definite numbers of atoms of the component elements•The weight of a compound equals the sum of the weights of the component elements
Gay Lussacs - Law of Combining Volumes
For chemical reactions involving gases, combinations occur in simple proportions by volume. Moreover, the ratio of the volume of each product gas to the volume of either reacting gas is a ratio of small integers.
For example, if the pressure and temperature are kept constant, two volumes of H2 gas reacts with one volume of O2 gas, producing two volumes of water vapor. The two reactants and the product form a 2:1:2 ratio.
Based on experimental observation:
2 volumes of hydrogen + 1 volume of oxygen 2 volumes of water vapor
How do atoms combine to form compounds?
Avogadro’s HypothesisEqual volumes of different gases (at the same temperature and pressure) contain equal numbers of particles
2 volumes of hydrogen + 1 volume of oxygen 2 volumes of water vapor can be expressed as
2H2 + O2 2H2O
While at this time there was no direct evidence to show that hydrogen and oxygen gas were H2 and O2, 50 years later
this was proven to be the case.
Are Atoms really indivisible?
Dalton reached his conclusions about atoms on the basis of evidence gained on a macroscopic level.
As scientists developed more instrumentation capable of probing phenomena at a microscopic level, more about atoms was understood.
Example: The color of the emitted light characterizes the
element.
Electrons
J.J. Thompson showed that the cathode rays were in fact particles of NEGATIVE charge, the rays could be deflected by a magnetic field.
The term ELECTRON was coined for the negative particles. Thompson also calculated the charge of each particle
Millikan’s Oil Drop Experiment
Robert Millikan’s oil drop experiment calculated the charge/mass ratio of the electron, and combining Thompson’s results the mass of the electron was calculated to be 9.10 x 10-28 g.
(actual mass of the electron 9.10939 x 10 -28 g)
There must be a positive species which counters the electron charge.
Radioactivity
Henri Becquerel in 1896 discovered high-energy radiation was spontaneously emitted from uranium.
Later Marie Curie and her husband Pierre further investigated this spontaneous emission of radiation which was termed radioactivity.
Further studies of radioactivity by Rutherford showed that the radiation consisted of three types of radiation , , radiation.
and radiation are bent by an electric field, but in opposite directions, and radiation is unaffected.
Rutherford was able to show that particles have charge of +2 and that –1 and that particles combine with electrons to form Helium atoms.
rays are high energy electromagnetic radiation
The Structure of the Atom
J.J. Thompson, realized that electrons were sub-atomic particles, and presented his theory of the model of the atom.
The “PLUM-PUDDING” model
electronpositive sphereof charge
Rutherford’s conducted further experiments which contradicted Thompson’s model.
To explain his results Rutherford postulated
Most of the mass of the atom and all its positive charge was located in a concentrated core, called the nucleus. Most of the total volume of the atom is empty in which electrons move around the positive core.
Model of the Atom
Since the times of Rutherford, many more subatomic particles have been discovered.
However, for chemists three sub-atomic particles are all that we need to focus on – ELECTRON, PROTON, NEUTRON.
Electrons are –1, protons +1 and neutrons are neutral.
Atoms have an equal number of electrons and protons they are electrically neutral.
Protons and neutrons make up the heavy, positive core, the NUCLEUS which occupies a small volume of the atom.
Isotopes
Atoms of different elements are distinguished by the difference in the number of protons and the number of electrons.
Since atoms are electrically neutral, the number of protons = number of electrons
Since the number of protons (and electrons) differ, their MASS differ. Hence atoms of different elements have different masses.
So for example, hydrogen has ONE proton and ONE electron
Carbon has SIX protons and SIX electrons
Atoms of the SAME element can have different number of NEUTRONS.
These atoms of the SAME elements but with different number of neutrons are called ISOTOPES.
Hence isotopes of the same elements have the same number of protons and electrons, but different number of neutrons and hence different masses.
EXAMPLE – Carbon has three isotopes C12, C13, C14. Each of these isotopes differ by the number of neutrons – ALL have SIX protons. C12 has SIX neutron, C13 has SEVEN and C14 has EIGHT.
To denote the number of protons and neutrons in an atom the following symbol notation is used
126C where 12 denotes SUM OF PROTONS + NEUTRONS
6 denotes the number of PROTONS
So for the isotopes of carbon the complete chemical symbols are: 12
6C, 136C, 14
6C
The superscript, which is the sum of the number of protons and neutrons, is called the MASS NUMBER (A).
The subscript indicates the number of protons and is called the ATOMIC NUMBER (Z) .
How many protons, neutrons, and electrons are there in
79197Au
197 is the mass number and refers to the total number of protons and neutrons. 79 is the atomic number and refers to the number of protons. Hence this atom has 79 electrons and 197-79 = 118 neutrons
Atomic Units
Atoms are very, very light and very, very small
Since atomic dimensions are so small, it would be cumbersome to use units we typically use for length (cm, m) or mass (g).
Hence, on the atomic scale we define units appropriate for this scale
MASS – unit typically used is an ATOMIC MASS UNIT (amu)
1 amu = 1.66054 x 10–24 g
Particle Charge Mass (g) Mass (amu)
Proton +1 1.6727x10-24 1.0073
Neutron Neutral 1.6750x10-24 1.0087
Electron -1 9.109x10-28 5.486 x 10-4
LENGTH – ANGSTROM(Å) = 10-10m
Typical atomic dimensions are 1 to 5 x10-10 m which corresponds to 1 to 5 Å.
Relative Atomic Mass
A relative scale has been developed to compare the relative masses of atoms. The ATOMIC MASS of an atom is its relative mass on this scale.
Carbon- 12 (12C) has been set as the standard and assigned a RELATIVE MASS of exactly 12.
Relative atomic masses have no units since they are the ratio of two masses.
Average Relative Atomic Mass
Because the abundance of the isotopes of different elements are essentially constant, we can define an AVERAGE RELATIVE ATOMIC mass
Average Relative Atomic Mass = average mass of atoms of an element =
(Abundance)A(Mass)A + (Abundance)B(Mass)A + …
(Table at the back of the text lists relative atomic masses of elements)
Problem
Naturally occurring chlorine has two isotopes, 3517Cl, 37
17Cl. The 35-Cl isotope has a relative atomic mass of 34.9688 and an abundance of 75.77% and the 37-Cl isotope has a relative atomic mass of 36.9659 and an abundance of 24.23%. Calculate the average atomic mass of Cl.
Average Atomic Mass of Cl = (0.7577x34.9659) +
(.2423x36.9659)
= 35.4527
Average relative atomic mass of C is 12.0107 accounting for 12C (98.892%, relative atomic mass 12.000000) and 13C (1.108%, relative atomic mass 13.003354)
Relative Molecular Mass
The relative molecular mass is the sum of the relative atomic masses of the atoms that make up the molecule.
Example, the chemical formula for water is H2O
Its relative molecular mass
= 2 (1.00794) + 15.9994 = 18.0153
Avogadro’s Number
Avogadro’s number: the number of atoms in exactly 12 g of 12C.
No = 6.022137 x 1023
Sodium (Na) has a relative atomic mass of 22.98977
12
Hence a sodium atom is (22.98977) times as heavy as 12C
If No atoms of 12C have a mass of 12g then, the mass of No atoms of sodium must be
(22.98977) 12g = 22.98977 g
12
The mass, in grams, of No atoms of ANY element is numerically equal to the relative atomic mass of that element.
Same applies to molecules.
Since the relative molecular mass of water is 18.0152, the mass of No water molecules is 18.0152g
MOLE: A mole has been defined as a unit containing 6.022137 x 1023 , Avogadro’s number, atoms or molecules,
One mole of any atom or molecule contains the same number of atoms or molecules
The mass, in grams, of ONE MOLE of atoms or molecules is numerically equal to relative atomic or molecular mass.
Hence 1 mole of Na weighs 22.9898 g, 1 mole of H2O weighs 18.0153 g
The MASS of one mole of atoms or molecules is called its MOLAR MASS and has UNITS of g/mol
PROBLEMHow many moles of Fe are there in 8.232 g of Fe?How many atoms are there in 8.232 g of Fe?
1 mol H2O
0.2000 mol H2O x 18.015 g H2O = 3.603 g H2O
55.85 g Fe
Moles of Fe = 8.232 g Fe x 1 mole = 0.1474 mol Fe
How many grams of water are there in 0.2000 moles of water?