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4.35 Determine reaction at the walls Compatibility => + (1) => 2.33Fc + Fc=16 Fc= Fc= 4.8KN Fa=16-4.8=11.2KN 4.36 Determine the average normal stress Compatibility

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4.35 Determine reaction at the walls

Compatibility

=> +

(1) => 2.33Fc + Fc=16

Fc= Fc= 4.8KN Fa=16-4.8=11.2KN

4.36 Determine the average normal stress

Compatibility

a=b

(1) 0.728Pbr+Pbr=25

Pst=25-14.467=10.532kn

st=

br=

br = 2.78MPa 4.1 SA = P = 5KN, L = 8m, do = 400mm, t = 50mmd1 = do 2tSA = = -3.637x10-6 m= -3.637x10-3 mm 4.87 Determine Maximum normal stress

follet

follet = 112 MPA For the hole

Max =

= = 0.19 GPA

Max = 190 MPA

4.89 Determine maximum axial loading P. For fillet Part

allow

P=

= P = 2Pfillet = 64.28KN = 32.142KN For hole part.

allow

P=

= = 44.081 KN 4.90 Determine Maximum P fillet part

allow= max =

P=

=

6.43 Determine the maximum stress A. Z axist

max=

max= B.About Y axist

=> max= 6.44 Determine stress created at point a,b

max=

max= Point B

b=

I =

b=

6.45 Determine percentage of the moment

a=

Ca =

b=

Cb =

a=b

= Mb100 =87.5 Mb Ma= 0.87.5 Mb Ma > Mb

6.46 Determine the moment M that should be applied to D.

D= M=

D= 30 MPA =

I=

= 0.00009114

Y =

M = M = 36.456 KN.m

6.47 Determine the largest internal moment A. About Z axist

Iz =

=

Iz = 5410500mm= C= 64mm

M= M = 14150 N.m = 14.15 KN.m B. About Y axist

Iy =

=

Iy = C= 60mm=0.06

M= M = 1653NM M = 1.635 KN.m 6.50 Determine which one will support of M =150KN.m

a =

I=

=

=

I =

a =

a = 114.34 MPA

4.1Determine the stress in the concrete SA = P = 5KN, L = 8m, do = 400mm, t = 50mmd1 = do 2tSA = = -3.637x10-6 m= -3.637x10-3 mm

4.2Find the displacementSAD= = = 4.3 Determine the displacement of its end D S = =

6.47Determine the maximum stress in the member Iz= == 56.2510-16 m4IY= == 0.110-3 m4 For bending about z axis c For bending about y axis c

6.48Find the moment M

INA= == 3.34610 7 mm4

Maximum bending stress

6.49Find the maximum tensile and compressive bending stress

= 84.707mm INA= 3.46

6.50 Find the bending stress

INA= == 0.09588310-6m4 For bending stress formula

6.51Find the maximum bending moment

= 13.24mm INA= 0.09588310-6For bending stress formula

6.52Find the percentage of the moment

I= == 91.1458310-6 m4For bending stress formulaResultant force and Moment

6.53Find the moment M

I= == 91.1458310-6 m4For bending stress formula6.113Find the constant a,b,c

Equation :

6.116Find the force P

, PropertyIz= == 28.4410-6 m4IY= == 13.34510-6 m4

Allowable bending stressP = 14208N

6.117Find the maximum bending stress

,

Iz= == 28.4410-6 m4IY= == 13.34510-6 m4 Maximum bending stress formula

6.118Find the maximum bending stress

IY= == 1.307810-3 m4 Iz= == 5.2113210-3 m4

7.1 Determine the shear stress on the web at A

F7.2 Determine the shear stress at points A and Bon the beam if it is subjected to a shearforce of v=600KNProof

F7.3Determine the absolute maximum shear stress developed in the beam

F7.4 Determine the maximum shear stress in the beam

F7.5 Determine the vertical shear force resist by the flange

F7.6 Determine the web shear stress at A and B

F7.7 Determine the maximum shear stress

F7.8 Determine the shear force resisted by the web of the beam

F7.9 Determine the allowable maximum space of the bolts to the nearest mm

F7.10 Determine the allowable maximum spacing of the bolt s

7.3 Determine Shear force resisted by web on beam

I= ==4.5210-5 m4