assigment cisco
TRANSCRIPT
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1. Determine network information for a given IP address and network mask.
Task 2: Challenge
Problem 1:
Host IP Address: 172.30.1.33Network Mask: 255.255.0.0
To change these decimal number to binary number is by following these step:-
1) Convert Host IP Address to Binary172.30.1.33
From these number, what can we added to get the total 172.30.1.33 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
172 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 0 1 1 0 1 0 0
27 +25 + 2 4+22=172
128+32+16+4=172
So the number will be 10110100 and this number is a binary number for 172 .
30=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 1 1 1 1 0
24+23+22+21=30
16+8+4+2=30
00011110 is a binary number for 30
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1=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 1
20=1
1=1
00000001 is a binary number for 1
33=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 1 0 0 0 0 1
25
+20
=3332+1=33
00100001 is a binary number for 33
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2) Convert Network Mask to binary255.255.0.0
From these number, what can we added to get the total 255.255.0.0 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
255 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
So the number will be 10110100 and this number is a binary number for 255 .
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
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0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
All of these step is a way to convert decimal to binary number. There is a few step to convert thisnumber by using divided, multiply, or minus. You do the same step to find binary number for thesedecimal.
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To find the Network Address.
*Perform a bit-wise AND (Multiply) operation on the IP address and the subnet mask*
172 30 1 33IP Address 10101100 00011110 00000001 00100001
AND AND AND ANDSubnet Mask 11111111 11111111 00000000 00000000
Network Address 10101100 00011110 00000000 00000000172 30 0 0
Network Address is 172.30.0.0
To find the Network Broadcast Address.
*Perform an invert (swap 0 to 1, 1 to 0) on the network address and the network mask*
172 30 0 0Network Address 10101100 00011110 00000000 00000000Mask Address 11111111 11111111 00000000 00000000
Broadcast 10101100 00011110 11111111 11111111172 30 255 255
Network Broadcast Address is 172.30.255.255
By counting the number of host bits, we can determine the total number of usable host for thisnetwork.
Host Bits: 16 (count the inverted number)
Total of number Host:
216=65,536
65,536 2 = 65,534 (addresses that cannot use the all 0s address,network address, or the all 1s address, broadcast address.)
Problem 1
Host IP Address 172.30.1.33Network Mask 255.255.0.0
Network Address 172.30.0.0Network Broadcast Address 172.30.255.255Total Number of Host Bits 65536
Number of Host 65534 (after minus 2)
use this formula to get the Number of Host
Formula
2x= y
y - 2= Answer
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Problem 2:
Host IP Address: 172.30.1.33
Network Mask: 255.255.255.0
To change these decimal number to binary number is by following these step:-
1) Convert Host IP Address to Binary172.30.1.33
From these number, what can we added to get the total 172.30.1.33 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
172 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 0 1 1 0 1 0 0
27 +25 + 2 4+22=172
128+32+16+4=172
So the number will be 10110100 and this number is a binary number for 172 .
30=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 1 1 1 1 0
24+23+22+21=30
16+8+4+2=30
00011110 is a binary number for 30
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1=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 1
20=1
1=1
00000001 is a binary number for 1
33=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 1 0 0 0 0 1
25
+20
=3332+1=33
00100001 is a binary number for 33
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2) Convert Network Mask to binary255.255.255.0
From these number, what can we added to get the total 255.255.255.0 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
255 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
So the number will be 10110100 and this number is a binary number for 255 .
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
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0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
All of these step is a way to convert decimal to binary number. There is a few step to convert thisnumber by using divided, multiply, or minus. You do the same step to find binary number for thesedecimal.
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To find the Network Address.
*Perform a bit-wise AND (multiply) operation on the IP address and the subnet mask*
172 30 1 33IP Address 10101100 00011110 00000001 00100001
AND AND AND ANDSubnet Mask 11111111 11111111 11111111 00000000
Network Address 10101100 00011110 00000001 00000000172 30 1 0
Network Address is 172.30.1.0
To find the Network Broadcast Address.
*Perform an invert (swap 0 to 1, 1 to 0) on the network address and the network mask*
172 30 1 0Network Address 10101100 00011110 00000001 00000000Mask Address 11111111 11111111 11111111 00000000
Broadcast 10101100 00011110 00000001 11111111 172 30 1 255
Network Broadcast Address is 172.30.1.255
By counting the number of host bits, we can determine the total number of usable host for thisnetwork.
Host Bits: 8 (count the inverted Number)
Total of number Host:
28=256
256 2 = 254 (addresses that cannot use the all 0s address,network address, or the all 1s address, broadcast address.)
Problem 2
Host IP Address 172.30.1.33Network Mask 255.255.255.0
Network Address 172.30.1.0Network Broadcast Address 172.30.1.255Total Number of Host Bits 256
Number of Host 254 (after minus 2)
Formula
2x= y
y - 2= Answeruse this formula to get the Number of Host
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Problem 3:
Host IP Address: 192.168.10.234
Network Mask: 255.255.255.0
To change these decimal number to binary number is by following these step:-
1) Convert Host IP Address to Binary192.168.10.234
From these number, what can we added to get the total 192.168.10.234 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
192 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 0 0 0 0 0 0
27 +26=192
128+64=192
So the number will be 11000000 and this number is a binary number for 192 .
168=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 0 1 0 1 0 0 0
24+25+23=168
16+32+8=168
10101000 is a binary number for 168
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10=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 1 0 1 0
23+21=10
8+2=10
00001010 is a binary number for 10
234=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 0 1 0 1 0
27+26+25+23+21=243
128+64+32+8+2=24311101010 is a binary number for 234
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2) Convert Network Mask to binary255.255.255.0
From these number, what can we added to get the total 255.255.255.0 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
255 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
So the number will be 10110100 and this number is a binary number for 255 .
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
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0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
All of these step is a way to convert decimal to binary number. There is a few step to convert thisnumber by using divided, multiply, or minus. You do the same step to find binary number for thesedecimal.
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To find the Network Address.
*Perform a bit-wise AND (multiply) operation on the IP address and the subnet mask*
192 168 10 234IP Address 110000000 10101000 00001010 11101010
AND AND AND ANDSubnet Mask 11111111 11111111 11111111 00000000
Network Address 11000000 10101000 00001010 00000000192 168 10 0
Network Address is 192.168.10.0
To find the Network Broadcast Address.
*Perform an invert (swap 0 to 1, 1 to 0) on the network address and the network mask*
192 168 10 234Network Address 11000000 10101000 00001010 11101010Mask Address 11111111 11111111 11111111 00000000
Broadcast 11000000 10101000 00001010 11111111 192 168 10 255
Network Broadcast Address is 192.168.10.255
By counting the number of host bits, we can determine the total number of usable host for thisnetwork.
Host Bits: 8 (count the inverted Number)
Total of number Host:
28=256
256 2 = 254 (addresses that cannot use the all 0s address,network address, or the all 1s address, broadcast address.)
Problem 3
Host IP Address 192.168.10.234Network Mask 255.255.255.0
Network Address 192.168.10.0Network Broadcast Address 192.168.10.255Total Number of Host Bits 256
Number of Host 254 (after minus 2)
Formula
2x= y
y - 2= Answeruse this formula to get the Number of Host
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Problem 4:
Host IP Address: 172.17.99.71
Network Mask: 255.255.0.0
To change these decimal number to binary number is by following these step:-
1) Convert Host IP Address to Binary172.17.99.71
From these number, what can we added to get the total 172.17.99.71 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
172 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 0 1 0 1 1 0 0
27 +25+23+22=172
128+32+8+4=172
So the number will be 10101100 and this number is a binary number for 172 .
17=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 1 0 0 0 1
24+20=17
16+1=17
00010001 is a binary number for 17
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99=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 1 1 0 0 0 1 1
26+25+21+20=99
64+32+2+1=99
01100011 is a binary number for 99
71=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 1 0 0 0 1 1 1
26
+22
+21
+20
=7164+4+2+1=71
01000111 is a binary number for 71
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2) Convert Network Mask to binary255.255.0.0
From these number, what can we added to get the total 255.255.0.0 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
255 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
So the number will be 10110100 and this number is a binary number for 255 .
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
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0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
All of these step is a way to convert decimal to binary number. There is a few step to convert thisnumber by using divided, multiply, or minus. You do the same step to find binary number for thesedecimal.
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To find the Network Address.
*Perform a bit-wise AND (multiply) operation on the IP address and the subnet mask*
172 17 99 71IP Address 110000000 10101000 00001010 11101010
AND AND AND ANDSubnet Mask 11111111 11111111 00000000 00000000
Network Address 11000000 10101000 00000000 00000000172 17 0 0
Network Address is 172.17.0.0
To find the Network Broadcast Address.
*Perform an invert (swap 0 to 1, 1 to 0) on the network address and the network mask*
172 17 0 0Network Address 11000000 10101000 00001010 11101010Mask Address 11111111 11111111 00000000 00000000
Broadcast 11000000 10101000 11111111 11111111 172 17 255 255
Network Broadcast Address is 172.17.255.255
By counting the number of host bits, we can determine the total number of usable host for thisnetwork.
Host Bits: 16 (count the inverted Number)
Total of number Host:
216=65536
65536 2 = 65534 (addresses that cannot use the all 0saddress, network address, or the all 1s address, broadcastaddress.)
Problem 4
Host IP Address 172.17.99.71Network Mask 255.255.0.0
Network Address 172.17.0.0Network Broadcast Address 172.17.255.255Total Number of Host Bits 65536
Number of Host 65534 (after minus 2)
Formula
2x= y
y - 2= Answeruse this formula to get the Number of Host
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Problem 5:
Host IP Address: 192.168.3.219
Network Mask: 255.255.0.0
To change these decimal number to binary number is by following these step:-
1) Convert Host IP Address to Binary192.168.3.219
From these number, what can we added to get the total 192.168.3.219 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
192 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 0 0 0 0 0 0
27 +26=192
128+64=192
So the number will be 11000000 and this number is a binary number for 192 .
168=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 0 1 0 1 0 0 0
27+25+23=168
128+32+8=168
10101000 is a binary number for 168
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3=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 1 1
21+20=3
2+1=3
00000011 is a binary number for 3
219=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 0 1 1 0 1 1
27+26+24+23+21+20=219
128+64+16+8+2+1=21911011011 is a binary number for 219
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2) Convert Network Mask to binary255.255.0.0
From these number, what can we added to get the total 255.255.0.0 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
255 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
So the number will be 10110100 and this number is a binary number for 255 .
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
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0=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 0 0
0=0
There is nothing you can added to get 0
00000000 is a binary number for 0
All of these step is a way to convert decimal to binary number. There is a few step to convert thisnumber by using divided, multiply, or minus. You do the same step to find binary number for thesedecimal.
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To find the Network Address.
*Perform a bit-wise AND (multiply) operation on the IP address and the subnet mask*
192 168 3 219IP Address 110000000 10101000 00000011 11011011
AND AND AND ANDSubnet Mask 11111111 11111111 00000000 00000000
Network Address 11000000 10101000 00000000 00000000192 168 0 0
Network Address is 192.168.0.0
To find the Network Broadcast Address.
*Perform an invert (swap 0 to 1, 1 to 0) on the network address and the network mask*
192 168 0 0Network Address 11000000 10101000 00001010 11101010Mask Address 11111111 11111111 00000000 00000000
Broadcast 11000000 10101000 11111111 11111111 192 168 255 255
Network Broadcast Address is 172.17.255.255
By counting the number of host bits, we can determine the total number of usable host for thisnetwork.
Host Bits: 16 (count the inverted Number)
Total of number Host:
216=65536
65536 2 = 65534 (addresses that cannot use the all 0saddress, network address, or the all 1s address, broadcastaddress.)
Problem 5
Host IP Address 192.168.3.219Network Mask 255.255.0.0
Network Address 192.168.0.0Network Broadcast Address 192.168.255.255Total Number of Host Bits 65536
Number of Host 65534 (after minus 2)
Formula
2x= y
y - 2= Answeruse this formula to get the Number of Host
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Problem 6:
Host IP Address: 192.168.3.219
Network Mask: 255.255.255.224
To change these decimal number to binary number is by following these step:-
1) Convert Host IP Address to Binary192.168.3.219
From these number, what can we added to get the total 192.168.3.219 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
192 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 0 0 0 0 0 0
27 +26=192
128+64=192
So the number will be 11000000 and this number is a binary number for 192 .
168=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 0 1 0 1 0 0 0
27+25+23=168
128+32+8=168
10101000 is a binary number for 168
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3=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 10 0 0 0 0 0 1 1
21+20=3
2+1=3
00000011 is a binary number for 3
219=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 0 1 1 0 1 1
27+26+24+23+21+20=219
128+64+16+8+2+1=21911011011 is a binary number for 219
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2) Convert Network Mask to binary255.255.0.0
From these number, what can we added to get the total 255.255.225.224 ?
20= 1
21= 2
22= 4
23= 8
24= 16
25= 32
26= 64
27= 128
From added number, which number do we have?
255 =?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
So the number will be 10110100 and this number is a binary number for 255 .
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
255=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 1 1 1 1 1
27+26+25+24+23+22+21+20=255
128+64+32+16+8+4+2+1=255
11111111 is a binary number for 255
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224=?
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 11 1 1 0 0 0 0 0
27+26+25=224
128+64+32=224
11100000 is a binary number for 224
All of these step is a way to convert decimal to binary number. There is a few step to convert thisnumber by using divided, multiply, or minus. You do the same step to find binary number for thesedecimal.
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To find the Network Address.
*Perform a bit-wise AND (multiply) operation on the IP address and the subnet mask*
192 168 3 219IP Address 110000000 10101000 00000011 11011011
AND AND AND ANDSubnet Mask 11111111 11111111 11111111 11100000
Network Address 11000000 10101000 00000011 11000000192 168 3 192
Network Address is 192.168.3.192
To find the Network Broadcast Address.
*Perform an invert (swap 0 to 1, 1 to 0) on the network address and the network mask*
192 168 3 0Network Address 11000000 10101000 00000011 111 01010Mask Address 11111111 11111111 11111111 11 1 00000
Broadcast 11000000 10101000 00000011 110 11111 192 168 3 223
Network Broadcast Address is 172.17.3.223
By counting the number of host bits, we can determine the total number of usable host for thisnetwork.
Host Bits: 5 (count the inverted Number)
Total of number Host:
25=32
32 2 = 30 (addresses that cannot use the all 0s address,network address, or the all 1s address, broadcast address.)
Problem 6
Host IP Address 192.168.3.219Network Mask 255.255.255.224
Network Address 192.168.3.192Network Broadcast Address 192.168.255.223Total Number of Host Bits 32
Number of Host 30 (after minus 2)
Formula
2x= y
y - 2= Answeruse this formula to get the Number of Host