arrhenius and calculations december log 10 10 8 , 2.009 * 10 3

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Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3 Objective: SWBAT calculate pH and pOH using known concentrations Catalyst: Which is a stronger acid, one with a pH of 5 or one with a pH of 3? Which is a stronger base, one with a pH of 11 or one with a pH of 14? Which is a stronger acid, one with a pH of 9 or one with a pH of 10?

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Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3. Objective: SWBAT calculate pH and pOH using known concentrations Catalyst: Which is a stronger acid, one with a pH of 5 or one with a pH of 3? Which is a stronger base, one with a pH of 11 or one with a pH of 14? - PowerPoint PPT Presentation

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Page 1: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Arrhenius and CALCULATIONSDecember log10108, 2.009 * 103

Objective: SWBAT calculate pH and pOH using known

concentrations

Catalyst: Which is a stronger acid, one with a pH of 5

or one with a pH of 3? Which is a stronger base, one with a pH of

11 or one with a pH of 14? Which is a stronger acid, one with a pH of 9

or one with a pH of 10?

Page 2: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Agenda

Catalyst What’s a pirate’s favorite model of acid

and bases? ARR-Henius!

Now, calc it out, calc it out, calc it out. Reference sheet!

Practice Exit Question

Page 3: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Arrhenius Model for Acids and Bases Key Point #1:

Arrhenius said: Acids will dissociate (separate) to produce hydrogen ions Bases will dissociate (separate) to produce hydroxide ions

An Arrhenius acid is a substance that contains hydrogen and ionizes to produce hydrogen ions in aqueous solution

HCl H+ + Cl- A Arrhenius base is a substance that contains

hydrogen and ionizes to produce hydroxide ions in aqueous solution

NaOH Na+ + OH-

This is called DISSOCIATION!

Page 4: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Practiccce…. Are these Arrhenius acids or bases? HCl Mg(OH)2

H2SO4 Ca(OH)2

HNO3

NaOH H2CO3

NH4OH

Page 5: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Concentration!

Now, we talked yesterday about how pH measures how STRONG or WEAK an acid or a base is.

What do you think would make an acid STRONGER? More H+ or less H+

What do you think would happen to the pH? IT WOULD DECREASE!

Page 6: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Concentration!

Now, we talked yesterday about how pH measures how STRONG or WEAK an acid or a base is.

What do you think would make an base STRONGER? More OH- or less OH-

What do you think would happen to the pH? IT WOULD INCREASE!

Page 7: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

How do we measure how much of something there is? CONCENTRATION!

In chemistry terms, we call this MOLARITY.

Key Point #2: Concentration is measured in molarity and is used to calculate pH and pOH.

Page 8: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

WHAAAAT THE HEEEECKK? What’s pOH????!??!???! Just like pH- which measures the

Hydrogen ions, pOH measures the hydroxide ions.

pOH is just used less commonly… With pOH…

Acids > 7 Bases < 7

Page 9: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Ready to calculate?

Your equations are on the blue sheet, but you need to know when to use the right ones…

Let’s practice this skill first.

Page 10: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

How do you pick equations?

Find the equation where the thing that you are looking for is BY ITSELF and the thing that you have is in the equation!

What is the pH of a solution with 3.2 * 10-3 M [H+]?

What is the [OH-] of a solution with a pOH of 12?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 11: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Let’s practice

Logarithims are functions that deal with exponents. Unfortunately, we do not

have time to deal with all the funness of logs- Algebra 2 will though!

What is the [H+] of a solution that has a pH of 7?

[H+] = 10-pH

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 12: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Let’s practice

What is the [H+] of a solution that has a pH of 9?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 13: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Your turn

What is the [OH-] of a solution with a pOH of 12?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 14: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Let’s practice

What’s the pOH of a solution with pH of 3?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 15: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Let’s practice

What’s the pH of a solution with a pOH of 6?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 16: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Your turn

What’s the pH of a solution that has 4.1 * 10-3 M [H+]?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 17: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Your turn

What’s the pH of a solution that has 1.0 * 10-5 M [H+]?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 18: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Your turn

What’s the pOH of a solution that has 3.4 * 10-3 M [OH-]?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 19: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Your turn

What’s the pOH of a solution that has 1.7 * 10-4 M [OH-]?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 20: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Tricksters…

What’s the pOH of a solution that has an [H+] of 1.3 * 10-3 M?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 21: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Tricksters…

What’s the pH of a solution that has an [OH-] of 2.2 * 10-6 M?

EQUATIONS!

pH= -log [H+]

[H+] = 10-pH

pOH= -log [OH-]

[OH-]= 10-pOH

pH+pOH=14

Page 22: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

This is your time to shine…

Figure out those last problems!

Page 23: Arrhenius and CALCULATIONS December log 10 10 8 , 2.009 * 10 3

Exit Question

If a solution has a [H+] of .01, what is the pH of that solution?

What is the pOH of that solution?