application of linear algebric equation in chemical engineering
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APPLICATION OF LINEAR ALGEBRIC EQUATION IN CHEMICAL ENGINEERING
Prepared By: Lakhlani Nishith
Linear Algebraic EquationThe definition of a linear equation is an
algebraic equation in which each term has an exponent of one.
The graphing of the equation results in a straight line.
One or more variables in the equation.
Application In Chemical EngineeringOne of the most important organizing
principles in chemical engineering is the Conservation of Mass.
The principle of mass conservation, states that for any closed system the mass of the system must remain constant over time.
Cont.. independent of any chemical and physical
changes taking place within the system.
For stable condition(i.e., steady-state) it can be represented as:
Input = output
Example-1Suppose we are performing a mass balance
for a conservative substance (i.e., one that doesn’t increase or decrease due to chemical transformation) in a reactor, we would have to quantify the rate mass flows into the reactor through the two inflow pipes and out of the reactor through outflow pipe.
Cont..For pipe 1,product flow rate Q1=2 m3/min ,
Q2= 1.5 m3/min and concentrate C1=25 mg/m3 C2= 10 mg/m3 ; therefore, the rate at which mass flows into reactor through pipe 1 and pipe 2 accordingly.
Cont..Because of Steady state of Reactor
Input = Output ,according to that
Q1C1 + Q2C2 = Q3C3
50 + 15 = 3.5 C3
C3 =18.6 mg/m3
Example-2Problem
By examination we can see that the following equation is not balanced.
CH4 + O2 CO2+H2O
Cont..Solution
First assign variables to each of the unknown coefficients in the equation which gives us:
wCH4 + xO2 yCO2 + zH2O
Cont..CARBON w = y There is 1 carbon
atom in the w term and 1 in the y term.
HYDROGEN 4w = 2zThere are 4 Hydrogen
atoms in the w term and 2 in the z term.
OXYGEN 2x = 2y + z
There are 2 oxygen atoms in the x term, 2 in the y
term, and 1 in the z term.
Cont..Rewrite the linear equations in standard form
to get a homogeneous system of equations with 4 variables:
w-y = 0 4w-2z = 0 2x-2y-z = 0
Create a matrix for the above systems of equations augmented with zero’s (left) and perform the Gauss-Jordan elimination method to reduce the matrix(right).
Cont..This gives us the following values for our
variables.
w = 1/2zx = 1zy = 1/2z
above equations we calculate the values of our 4 variables to be:
w x y z1 2 1 3
Cont..Replace these values as the coefficients to
our original equation.
CH4 + 2O2 CO2 + 2H2O