ap biology review – unit 1

32
AP Biology Review – Unit 1 Chapter 1-3

Upload: dori

Post on 07-Jan-2016

59 views

Category:

Documents


3 download

DESCRIPTION

AP Biology Review – Unit 1. Chapter 1-3. 1. Briefly summarize the characteristics of life shared by all living organisms. Common set of chemical components (cells) Contains genetic info (DNA) Convert molecules from environment into new molecules Extract energy from environment to do work - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: AP Biology Review – Unit 1

AP Biology Review – Unit 1

Chapter 1-3

Page 2: AP Biology Review – Unit 1

1. Briefly summarize the characteristics of life shared by all living organisms

a) Common set of chemical components (cells)b) Contains genetic info (DNA)c) Convert molecules from environment into new

moleculesd) Extract energy from environment to do worke) Metabolismf) Homeostasisg) Replicate genetic infoh) Share sequence similarities with othersi) evolve

Page 3: AP Biology Review – Unit 1

2. How do scientists define a theory?

• Biologists define “theory” as a body of scientific work which is rigorously tested

and well-established factsand principles are used to understand, explain,

and make predictions about the natural world.

Page 4: AP Biology Review – Unit 1

3. Design an experiment…

1. Testable hypothesis2. Independent variable – specific to it’s values and

range3. Dependent variable – specific on how and when

it is being measured.4. Large sample size or repeat experiment several

times5. State your control variables6. Statistical analysis of data7. State results expected as they relate to

hypothesis

Page 5: AP Biology Review – Unit 1

Actual key answer…• The independent variable is the type of goldfish food. For the sake of this experiment, we will

assume thatfeeding goldfish fish flakes is customary or the “control,” while feeding shrimp pellets is the independent variable.

• Hypothesis: Feeding goldfish shrimp pellets instead of fish flakes produce larger fish.• In the experiment, twenty 5-gallon tanks are filled with 5 gallons of water, kept at the same

temperature of 68 degree F. Twenty young goldfish of identical age, which have each been measured in length prior tocommencement of the experiment, are placed into the tanks, one fish per tank. The water in each tank isfiltered and aerated with the same type of aeration system, and the tanks are placed near each other withequal exposure to periods of light and darkness. In the first ten tanks, the goldfish are fed shrimp pellets,according to the directions on the package. In the second group of ten tanks, the control group, the goldfish are fed fish flakes, also in accordance with package directions.

• At the end of each week, the goldfish are carefully removed from their respective tanks and individuallymeasured before being returned to the tank. This process is continued for twelve weeks. The food should be weighed and its nutritional content should be matched between the two treatments.

• *** Many other examples are possible. ***

Page 6: AP Biology Review – Unit 1

4. electrons, protons, neutrons, atomic number

Electrons Protons Neutrons Atomic Number

Hydrogen 1 1 0 1

Carbon 6 6 6 6

Oxygen 8 8 8 8

Phosphorus 15 15 16 15

Remember protons = atomic number ALWAYS!!

Remember protons = electrons in a NEUTRAL atom.

Remember mass number on periodic table is rounded then subtract the atomic number to get # of neutrons

Page 7: AP Biology Review – Unit 1

5. Strongest Weakest

• Covalent (sharing of electrons)• Ionic (transfer of electrons)• Hydrogen (attraction between partial + and

partial – charges – like between water molecules)

• Van Der Waals – (weak electric forces)

Page 8: AP Biology Review – Unit 1

6. Cation vs. Anion

• Cations are positively charged ions– Examples are Mg2+, Na+1, Al+3

• Anions are negatively charged ions– Examples are F-1, O-2, P-3

Page 9: AP Biology Review – Unit 1

7. NaCl explanation of ionic bond• A sodium atom has only one electron

in its outermost shell, which is an unstable condition.

• A chlorine atom has seven electrons in its outermost shell, also unstable.

• They achieve stability by transferring an electron from sodium to chlorine, making sodium a cation and making chlorine an anion.

• The electrical attraction between the anion and the cation is an ionic bond, which holds these ions together as dry salts, but this weak bond gives way when the ions are dissolved in water.

Page 10: AP Biology Review – Unit 1

8. Name that molecule• Water or H20• The oxygen molecule in water,

however, has a higher electronegativity than the hydrogen molecules. When they combine to form water, the electrons involved are unequally shared, tending to be nearer to the oxygen nucleus because of its greater electronegativity, giving the oxygen end of the chemical bond a slightly negative charge (δ- added to picture) and the hydrogen end a slightly positive charge (two δ+ added to picture).

Page 11: AP Biology Review – Unit 1

9. Explain A and B/same vs. different number of atoms

A. This demonstrates the formation of a hydrogenbond between two water molecules

B. Thisis an example of how hydrogen bonds can form between different parts of the

same large molecule.More atoms are represented in drawing B because it is a protein and not all of the atoms are being shown in the picture.

Page 12: AP Biology Review – Unit 1

10. Explain prompts• Choice A is more water-

soluble because it contains more polar covalent bonds, causing it to be hydrophilic or more attracted to the hydrogen atoms in water.

• Choice B is less water-soluble because it is a nonpolar molecule, containing mostly carbon and hydrogenatoms, which tend to aggregate with one another rather than with the more polar water molecules. Thistype of molecule is hydrophobic.

Page 13: AP Biology Review – Unit 1

11. Number carbons and name

Page 14: AP Biology Review – Unit 1

12. Label molecule

The hydrophobic tail includesHydrocarbon chains.

The hydrophilic head includesCholine and phosphate.

Page 15: AP Biology Review – Unit 1

13. Steroids and other fatty substances pass readily through most

cell membranes because:• … they are fat soluble. The lipid molecules line

up in a way that the center of the lipid bilayer (the fatty acid tails) are nonpolar, so they do not readily interact with polar molecules such as water.

• Their nonpolar nature makes them hydrophobic, so they do not dissolve in water.

Page 16: AP Biology Review – Unit 1

14. Draw amino acid and label

Page 17: AP Biology Review – Unit 1

15. Explain how the diversity of different proteins is created.

• The primary structure of a protein/peptide/polypeptide is determined by its precise linear sequence of amino acids.

• Since there are 20 different amino acids, combinations of two amino acids could mathematically generate 400 distinct dipeptides; combinations of three amino acids could generate 8,000 tripeptides. Even a small polypeptide of 100 amino acids has 20100 possible sequences, making the potential diversity of proteins essentially immense.

Page 18: AP Biology Review – Unit 1

16. Explain levels of proteins• Primary The primary structure of a protein is established by covalent bonds

between adjacent amino acids. This type of structure is found where amino acid monomers are joined, forming polypeptide chains. The primary structure determines the protien’s secondary, tertiary, and quaternary structures.

• Secondary The secondary structure of a protein consists of regular, repeated spatial configurations in different regions of a polypeptide chain. The two basic types are the “alpha helix,” a right-handed coil similar to a wood screw, and “beta pleated sheet,” formed from two or more polypeptide chains that are extended and aligned. Many proteins contain both types of secondary structure.

• Tertiary Tertiary structure is formed when the polypeptide chain is bent at specific sites and then folded back and forth. This provides the molecule’s specific three-dimensional shape, including a buried interior as well as an exposed outer surface. These folds are stabilized by hydrogen bonds and disulfide bridges.

• Quaternary Quaternary structure refers to the distinct manner in which two or more polypeptide chains or subunits bind together and interact, forming even larger protein molecules.

Page 19: AP Biology Review – Unit 1

17. Draw amino acids

Page 20: AP Biology Review – Unit 1

17C. Draw dipeptide

Page 21: AP Biology Review – Unit 1

18. Leucine substituted for Cysteine• Leucine is nonpolar and

hydrophobic, often found clustering with other similar hydrophobic side chains in the interior of the protein. Cysteine, a special type of amino acid which is not hydrophobic , has a terminal SH group that can react with another cysteine side chain to form a covalent bond, called a disulfide bridge, which determines how a polypeptide chain folds.

• If leucine were to be substituted for cysteine, the spatial orientation of the molecule would be affected because of the loss of hydrophobic properties, and the folding of the polypeptide chain would be altered. Altered shape usually results in altered functions of proteins.

Page 22: AP Biology Review – Unit 1

18. Arginine substituted for Phenylalanine

• Arginine is positively charged, hydrophilic, and attracts negatively charged ions of all sorts. Phenylalanine isnonpolar and hydrophobic.

• This substitution would likely cause the molecule to alter its orientation toward, instead of away from, water, possibly reducing the protein’s solubility in water. The changed protein would

also tend to more readily interact with anions.

Page 23: AP Biology Review – Unit 1

18. Alanine substituted for Aspartic Acid

• Alanine has nonpolar, hydrophobic side chains, whereas aspartic acid is negatively charged and hydrophilic.

• Substitution of alanine for aspartic acid would likely cause the molecule to alter its orientation away fromwater. It would also reduce its tendency to interact with positively charged ions.

Page 24: AP Biology Review – Unit 1

29. Quaternary? Why?• “B” shows a quaternary

structure, because the diagram depicts four polypeptides (observe that “B” has 8terminal amino acids) associated with each other, forming a larger protein molecule. This example is a tetramer, made up of four polypeptide subunits.

Page 25: AP Biology Review – Unit 1

30. Explain with terms

• Strongacid is an environmental factor that can result in the breakdown of a functional protein’s secondaryand tertiary structures, a process also known as denaturation.

• The introduction of acid alters the concentration of protons (H+ ) which results in the ionization of exposed carboxyl and amino groups, thus altering polarity.

• Since the tertiary structure of a protein determines its three-dimensional shape, the protein loses its original structure and likely, its original function.

Page 26: AP Biology Review – Unit 1

31. How does an enzyme speed up a reaction between 2 substrate

molecules?• An enzyme speeds the reaction time between

two substrate molecules by lowering the activation energy required for a reaction to occur.

• Substrate molecules bind themselves to a particular site on the enzyme, called the active site, where catalysis takes place.

Page 27: AP Biology Review – Unit 1

32. Label diagram

Page 28: AP Biology Review – Unit 1

33. Cofactors vs. Coenzymes?

• Cofactors are inorganic ions such as copper, zinc, and iron that bind to certain enzymes.

• A coenzyme differs from a cofactor because it is an organic molecule that adds or removes chemical groups from the substrate, althoughit does not permanently bind to the active site.

Page 29: AP Biology Review – Unit 1

34. Allosteric Regulation? Why?• “B” is an example of allosteric

regulation. Allosteric regulationoccurs when a non-substrate molecule controls enzymaticactivity by binding to or modifying a site other than theactive site.

• This molecule does not attempt to replace the substrate on the active site, but instead binds to a site away from the active site, changing the enzyme’s shape so that the substrate no longer fits.

Page 30: AP Biology Review – Unit 1

Identifying Molecules

1. Carbohydrate Monosaccharide C6H12O62. Carbohydrate Monosaccharide C6H12O63. Carbohydrate Disaccharide4. Carbohydrate Monosaccharide, alpha

glucose5. Carbohydrate Monosaccharide, beta glucose6. Carbohydrate polysaccharide, cellulose7. Carbohydrate polysaccharide, glycogen or

starch

Page 31: AP Biology Review – Unit 1

Continued…

8. Lipid, Steroid9. Amino Acid10.Carbohydrate, monosaccharide, pentose –

deoxyribose11.Carbohydrate, monosaccharide, pentose –

ribose12.Carbohydrate, polysaccharide13.Lipid, Triglyceride, saturated

Page 32: AP Biology Review – Unit 1

Last page!

14.Lipid, triglyceride, unsaturated15.Lipid, phospholipid16.Lipid, steroid17.Protein, primary18.Protein, tertiary19.Protein, quaternary20.Protein, secondary, alpha helix