answer - university of utahkrueger/6220/mo-add.pdf3. find u∗ and z0 from the following wind...

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Find u and z 0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯ u (m/s) 1 4.6 3 6.0 10 7.6 30 9.0 Answer: u =0.52 m/s, z 0 =0.028 m. To calculate u , apply the log wind profile u = u /k log(z/z 0 ), at any two heights z 1 and z 2 to obtain u(z 2 ) u(z 1 )= u /k log(z 2 /z 1 ), then solve for u : u = k u(z 2 ) u(z 1 ) log(z 2 /z 1 ) . To calculate z 0 , solve the log wind profile at any height z for z 0 : z 0 = z exp(ku(z )/u ).

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Page 1: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)

3. Find u∗ and z0 from the following wind profile measurements made during statically neutralconditions at sunset:

z (m) u (m/s)1 4.63 6.010 7.630 9.0

Answer:u∗ = 0.52 m/s, z0 = 0.028 m. To calculate u∗, apply the log wind profile

u = u∗/k log(z/z0),

at any two heights z1 and z2 to obtain

u(z2)− u(z1) = u∗/k log(z2/z1),

then solve for u∗:

u∗ = ku(z2)− u(z1)

log(z2/z1).

To calculate z0, solve the log wind profile at any height z for z0:

z0 = z exp(−ku(z)/u∗).

The graphical solution method is to plot the wind profile u versus log z, then extrapolate theprofile to u = 0. The height at which u = is z0.

! " # $ % & ' ( ) * "!"! #

"! "

"!!

"!"

"!#

+,-./01

2,-.1

34,%,56789:.,$

Difficulties: Some used the wrong equations.

2

3. Find u∗ and z0 from the following wind profile measurements made during statically neutralconditions at sunset:

z (m) u (m/s)1 4.63 6.010 7.630 9.0

Answer:u∗ = 0.52 m/s, z0 = 0.028 m. To calculate u∗, apply the log wind profile

u = u∗/k log(z/z0),

at any two heights z1 and z2 to obtain

u(z2)− u(z1) = u∗/k log(z2/z1),

then solve for u∗:

u∗ = ku(z2)− u(z1)

log(z2/z1).

To calculate z0, solve the log wind profile at any height z for z0:

z0 = z exp(−ku(z)/u∗).

The graphical solution method is to plot the wind profile u versus log z, then extrapolate theprofile to u = 0. The height at which u = is z0.

! " # $ % & ' ( ) * "!"! #

"! "

"!!

"!"

"!#

+,-./01

2,-.1

34,%,56789:.,$

Difficulties: Some used the wrong equations.

2

Page 2: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)

3. Find u∗ and z0 from the following wind profile measurements made during statically neutralconditions at sunset:

z (m) u (m/s)1 4.63 6.010 7.630 9.0

Answer:u∗ = 0.52 m/s, z0 = 0.028 m. To calculate u∗, apply the log wind profile

u = u∗/k log(z/z0),

at any two heights z1 and z2 to obtain

u(z2)− u(z1) = u∗/k log(z2/z1),

then solve for u∗:

u∗ = ku(z2)− u(z1)

log(z2/z1).

To calculate z0, solve the log wind profile at any height z for z0:

z0 = z exp(−ku(z)/u∗).

The graphical solution method is to plot the wind profile u versus log z, then extrapolate theprofile to u = 0. The height at which u = is z0.

! " # $ % & ' ( ) * "!"! #

"! "

"!!

"!"

"!#

+,-./01

2,-.1

34,%,56789:.,$

Difficulties: Some used the wrong equations.

2

Page 3: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)

Monin-Obukhov length as a function of friction velocity and surface heat flux

Page 4: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)

Wind and thermodynamic profiles

- 6.4 -

Atm S 547 Boundary Layer Meteorology Bretherton

(iii) Unstable limit. Convection replaces shear as the main source of eddy energy, so we expectthe eddy velocity to scale with the buoyancy flux B0 and not the friction velocity. We stillassume that the eddy size is limited by the distance z to the boundary. In this ‘free convectivescaling’, the eddy velocity scale is uf = (B0z)1/3 and the eddy viscosity should go as

Km = ku*z/!m " uf z # !m " u* / uf " (-z/L)-1/3 = (-$)-1/3

A similar argument applies to eddy diffusivity for scalars Kh. The empirical relations go as(-$)-1/2 for scalars and (-$)-1/4 for momenta, but reliable measurements only extend out to $= -2. Free convective scaling may be physically realized, but only at higher $.

Wind and thermodynamic profilesThe similarity relations can be integrated with respect to height to get:

u/u* = k-1 [ln(z/z0) - %m(z/L)]

(&0 ' & )/&* = k-1 [ln(z/zT0) - %h(z/L)] (and similarly for other scalars)

where if x = (1 - (1$)1/4,

%m($) =

=

%m($) =

=

Wind profiles in stable, neutral, and unstable conditions are shown in the figure below. Low-levelwind and shear are reduced compared to the log profile in unstable conditions, when Km is larger.From these,we derive bulk aerodynamic coefficients which apply in non-neutral conditions:

CD = , CH = (3)

These decrease considerably in stable conditions (see figure on next page). In observational anal-yses and numerical models, (3) and the formula for L are solved simultaneously to find surface heatand momentum fluxes from the values of u and &0 - & at the measurement or lowest grid-level z

1 !– m $'( )[ ] $'d $'⁄0

$)

1 x2+2

--------------* +, - 1 x+

2------------* +, - 2

* +. /, -

ln 2tan 1– x– 02---+ for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,3445446

1 !– h $'( )[ ] $'d $'⁄0

$)

2 1 x2+2

--------------* +, -ln for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,34546

k2

z z0⁄( )ln %m z L⁄( )–[ ]2---------------------------------------------------------- k2

z zT 0⁄( )ln %m z L⁄( )–[ ] z zT 0⁄( )ln %h z L⁄( )–[ ]---------------------------------------------------------------------------------------------------------------------

- 6.4 -

Atm S 547 Boundary Layer Meteorology Bretherton

(iii) Unstable limit. Convection replaces shear as the main source of eddy energy, so we expectthe eddy velocity to scale with the buoyancy flux B0 and not the friction velocity. We stillassume that the eddy size is limited by the distance z to the boundary. In this ‘free convectivescaling’, the eddy velocity scale is uf = (B0z)1/3 and the eddy viscosity should go as

Km = ku*z/!m " uf z # !m " u* / uf " (-z/L)-1/3 = (-$)-1/3

A similar argument applies to eddy diffusivity for scalars Kh. The empirical relations go as(-$)-1/2 for scalars and (-$)-1/4 for momenta, but reliable measurements only extend out to $= -2. Free convective scaling may be physically realized, but only at higher $.

Wind and thermodynamic profilesThe similarity relations can be integrated with respect to height to get:

u/u* = k-1 [ln(z/z0) - %m(z/L)]

(&0 ' & )/&* = k-1 [ln(z/zT0) - %h(z/L)] (and similarly for other scalars)

where if x = (1 - (1$)1/4,

%m($) =

=

%m($) =

=

Wind profiles in stable, neutral, and unstable conditions are shown in the figure below. Low-levelwind and shear are reduced compared to the log profile in unstable conditions, when Km is larger.From these,we derive bulk aerodynamic coefficients which apply in non-neutral conditions:

CD = , CH = (3)

These decrease considerably in stable conditions (see figure on next page). In observational anal-yses and numerical models, (3) and the formula for L are solved simultaneously to find surface heatand momentum fluxes from the values of u and &0 - & at the measurement or lowest grid-level z

1 !– m $'( )[ ] $'d $'⁄0

$)

1 x2+2

--------------* +, - 1 x+

2------------* +, - 2

* +. /, -

ln 2tan 1– x– 02---+ for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,3445446

1 !– h $'( )[ ] $'d $'⁄0

$)

2 1 x2+2

--------------* +, -ln for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,34546

k2

z z0⁄( )ln %m z L⁄( )–[ ]2---------------------------------------------------------- k2

z zT 0⁄( )ln %m z L⁄( )–[ ] z zT 0⁄( )ln %h z L⁄( )–[ ]---------------------------------------------------------------------------------------------------------------------

- 6.4 -

Atm S 547 Boundary Layer Meteorology Bretherton

(iii) Unstable limit. Convection replaces shear as the main source of eddy energy, so we expectthe eddy velocity to scale with the buoyancy flux B0 and not the friction velocity. We stillassume that the eddy size is limited by the distance z to the boundary. In this ‘free convectivescaling’, the eddy velocity scale is uf = (B0z)1/3 and the eddy viscosity should go as

Km = ku*z/!m " uf z # !m " u* / uf " (-z/L)-1/3 = (-$)-1/3

A similar argument applies to eddy diffusivity for scalars Kh. The empirical relations go as(-$)-1/2 for scalars and (-$)-1/4 for momenta, but reliable measurements only extend out to $= -2. Free convective scaling may be physically realized, but only at higher $.

Wind and thermodynamic profilesThe similarity relations can be integrated with respect to height to get:

u/u* = k-1 [ln(z/z0) - %m(z/L)]

(&0 ' & )/&* = k-1 [ln(z/zT0) - %h(z/L)] (and similarly for other scalars)

where if x = (1 - (1$)1/4,

%m($) =

=

%m($) =

=

Wind profiles in stable, neutral, and unstable conditions are shown in the figure below. Low-levelwind and shear are reduced compared to the log profile in unstable conditions, when Km is larger.From these,we derive bulk aerodynamic coefficients which apply in non-neutral conditions:

CD = , CH = (3)

These decrease considerably in stable conditions (see figure on next page). In observational anal-yses and numerical models, (3) and the formula for L are solved simultaneously to find surface heatand momentum fluxes from the values of u and &0 - & at the measurement or lowest grid-level z

1 !– m $'( )[ ] $'d $'⁄0

$)

1 x2+2

--------------* +, - 1 x+

2------------* +, - 2

* +. /, -

ln 2tan 1– x– 02---+ for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,3445446

1 !– h $'( )[ ] $'d $'⁄0

$)

2 1 x2+2

--------------* +, -ln for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,34546

k2

z z0⁄( )ln %m z L⁄( )–[ ]2---------------------------------------------------------- k2

z zT 0⁄( )ln %m z L⁄( )–[ ] z zT 0⁄( )ln %h z L⁄( )–[ ]---------------------------------------------------------------------------------------------------------------------

Page 5: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)

- 6.1 -

Atm S 547 Boundary Layer Meteorology Bretherton

Lecture 6. Monin-Obuhkov similarity theory (Garratt 3.3)

Because so many BL measurements are made within the surface layer (i. e. where wind veeringwith height is insignificant) but stratification effects can be important at standard measurementheights of 2 m (for temperature and moisture) and 10 m (for winds), it is desirable to correct thelog-layer profiles for stratification effects.

Based on the scaling arguments of last lecture, Monin and Obuhkov (1954) suggested that thevertical variation of mean flow and turbulence characteristics in the surface layer should dependonly on the surface momentum flux as measured by friction velocity u*, the buoyancy flux B0, andthe height z. One can form a single nondimensional combination of these, which is traditionallychosen as the stability parameter

! = z/LThe logarithmic scaling regime of last time corresponds to !<< 1.

Thus, within the surface layer, we must have(kz/u*)("u/"z) = #m(!) (1)

(kz/$*)("$/"z) = #h(!) (2)

where #m(!) and #h(!) are universal similarity functions which relate the fluxes of momentumand $ (i. e. sensible heat) to their mean gradients. Other adiabatically conserved scalars should be-have similarly to $ since the transport is associated with eddies which are too large to be affectedby molecular diffusion or viscosity. To agree with the log layer scaling, #m(!) and #h(!) shouldapproach 1 for small !.

We can express (1) and (2) in other equivalent forms. First, we can regard them as defining sur-face layer eddy viscosities:

Km = -u´w´ / ("u/"z) = u*2/(#m(!) u*/kz) = ku*z / #m(!)

Kh = -w´$´ / ("$/"z) = u*$*/(#h(!) $*/kz) = ku*z / #h(!)

By analogy to the molecular Prandtl number, the turbulent Prandtl number is their ratio:Prt = Km / Kh = #h(!) / #m(!)

Another commonly used form of the similarity functions is to measure stability with gradient Ri-chardson number Ri instead of !. Recalling that N2 = -db/dz, and again noting that the surface layeris thin, so vertical fluxes do not vary significantly with height within it, Ri is related to ! as follows:

Ri = (-db/dz) / (du/dz)2

= (w´b´0 /Kh)/ ( u´w´0/Km)2

= (B0#h(!) /ku*z) / (u*2#m(!)/ku*z))2

= !#h/#m2

Given expressions for #m(!) and #h(!), we can write ! and hence the similarity functions and eddydiffusivities in terms of Ri. The corresponding formulas for dependence of eddy diffusivity on Ri(stability) are often used by modellers even outside the surface layer, with the neutral Km and Km

- 6.1 -

Atm S 547 Boundary Layer Meteorology Bretherton

Lecture 6. Monin-Obuhkov similarity theory (Garratt 3.3)

Because so many BL measurements are made within the surface layer (i. e. where wind veeringwith height is insignificant) but stratification effects can be important at standard measurementheights of 2 m (for temperature and moisture) and 10 m (for winds), it is desirable to correct thelog-layer profiles for stratification effects.

Based on the scaling arguments of last lecture, Monin and Obuhkov (1954) suggested that thevertical variation of mean flow and turbulence characteristics in the surface layer should dependonly on the surface momentum flux as measured by friction velocity u*, the buoyancy flux B0, andthe height z. One can form a single nondimensional combination of these, which is traditionallychosen as the stability parameter

! = z/LThe logarithmic scaling regime of last time corresponds to !<< 1.

Thus, within the surface layer, we must have(kz/u*)("u/"z) = #m(!) (1)

(kz/$*)("$/"z) = #h(!) (2)

where #m(!) and #h(!) are universal similarity functions which relate the fluxes of momentumand $ (i. e. sensible heat) to their mean gradients. Other adiabatically conserved scalars should be-have similarly to $ since the transport is associated with eddies which are too large to be affectedby molecular diffusion or viscosity. To agree with the log layer scaling, #m(!) and #h(!) shouldapproach 1 for small !.

We can express (1) and (2) in other equivalent forms. First, we can regard them as defining sur-face layer eddy viscosities:

Km = -u´w´ / ("u/"z) = u*2/(#m(!) u*/kz) = ku*z / #m(!)

Kh = -w´$´ / ("$/"z) = u*$*/(#h(!) $*/kz) = ku*z / #h(!)

By analogy to the molecular Prandtl number, the turbulent Prandtl number is their ratio:Prt = Km / Kh = #h(!) / #m(!)

Another commonly used form of the similarity functions is to measure stability with gradient Ri-chardson number Ri instead of !. Recalling that N2 = -db/dz, and again noting that the surface layeris thin, so vertical fluxes do not vary significantly with height within it, Ri is related to ! as follows:

Ri = (-db/dz) / (du/dz)2

= (w´b´0 /Kh)/ ( u´w´0/Km)2

= (B0#h(!) /ku*z) / (u*2#m(!)/ku*z))2

= !#h/#m2

Given expressions for #m(!) and #h(!), we can write ! and hence the similarity functions and eddydiffusivities in terms of Ri. The corresponding formulas for dependence of eddy diffusivity on Ri(stability) are often used by modellers even outside the surface layer, with the neutral Km and Km

- 6.1 -

Atm S 547 Boundary Layer Meteorology Bretherton

Lecture 6. Monin-Obuhkov similarity theory (Garratt 3.3)

Because so many BL measurements are made within the surface layer (i. e. where wind veeringwith height is insignificant) but stratification effects can be important at standard measurementheights of 2 m (for temperature and moisture) and 10 m (for winds), it is desirable to correct thelog-layer profiles for stratification effects.

Based on the scaling arguments of last lecture, Monin and Obuhkov (1954) suggested that thevertical variation of mean flow and turbulence characteristics in the surface layer should dependonly on the surface momentum flux as measured by friction velocity u*, the buoyancy flux B0, andthe height z. One can form a single nondimensional combination of these, which is traditionallychosen as the stability parameter

! = z/LThe logarithmic scaling regime of last time corresponds to !<< 1.

Thus, within the surface layer, we must have(kz/u*)("u/"z) = #m(!) (1)

(kz/$*)("$/"z) = #h(!) (2)

where #m(!) and #h(!) are universal similarity functions which relate the fluxes of momentumand $ (i. e. sensible heat) to their mean gradients. Other adiabatically conserved scalars should be-have similarly to $ since the transport is associated with eddies which are too large to be affectedby molecular diffusion or viscosity. To agree with the log layer scaling, #m(!) and #h(!) shouldapproach 1 for small !.

We can express (1) and (2) in other equivalent forms. First, we can regard them as defining sur-face layer eddy viscosities:

Km = -u´w´ / ("u/"z) = u*2/(#m(!) u*/kz) = ku*z / #m(!)

Kh = -w´$´ / ("$/"z) = u*$*/(#h(!) $*/kz) = ku*z / #h(!)

By analogy to the molecular Prandtl number, the turbulent Prandtl number is their ratio:Prt = Km / Kh = #h(!) / #m(!)

Another commonly used form of the similarity functions is to measure stability with gradient Ri-chardson number Ri instead of !. Recalling that N2 = -db/dz, and again noting that the surface layeris thin, so vertical fluxes do not vary significantly with height within it, Ri is related to ! as follows:

Ri = (-db/dz) / (du/dz)2

= (w´b´0 /Kh)/ ( u´w´0/Km)2

= (B0#h(!) /ku*z) / (u*2#m(!)/ku*z))2

= !#h/#m2

Given expressions for #m(!) and #h(!), we can write ! and hence the similarity functions and eddydiffusivities in terms of Ri. The corresponding formulas for dependence of eddy diffusivity on Ri(stability) are often used by modellers even outside the surface layer, with the neutral Km and Km

Similarity Functions

Page 6: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)
Page 7: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)

Bulk aerodynamic coefficients for non-neutral conditions

- 6.4 -

Atm S 547 Boundary Layer Meteorology Bretherton

(iii) Unstable limit. Convection replaces shear as the main source of eddy energy, so we expectthe eddy velocity to scale with the buoyancy flux B0 and not the friction velocity. We stillassume that the eddy size is limited by the distance z to the boundary. In this ‘free convectivescaling’, the eddy velocity scale is uf = (B0z)1/3 and the eddy viscosity should go as

Km = ku*z/!m " uf z # !m " u* / uf " (-z/L)-1/3 = (-$)-1/3

A similar argument applies to eddy diffusivity for scalars Kh. The empirical relations go as(-$)-1/2 for scalars and (-$)-1/4 for momenta, but reliable measurements only extend out to $= -2. Free convective scaling may be physically realized, but only at higher $.

Wind and thermodynamic profilesThe similarity relations can be integrated with respect to height to get:

u/u* = k-1 [ln(z/z0) - %m(z/L)]

(&0 ' & )/&* = k-1 [ln(z/zT0) - %h(z/L)] (and similarly for other scalars)

where if x = (1 - (1$)1/4,

%m($) =

=

%m($) =

=

Wind profiles in stable, neutral, and unstable conditions are shown in the figure below. Low-levelwind and shear are reduced compared to the log profile in unstable conditions, when Km is larger.From these,we derive bulk aerodynamic coefficients which apply in non-neutral conditions:

CD = , CH = (3)

These decrease considerably in stable conditions (see figure on next page). In observational anal-yses and numerical models, (3) and the formula for L are solved simultaneously to find surface heatand momentum fluxes from the values of u and &0 - & at the measurement or lowest grid-level z

1 !– m $'( )[ ] $'d $'⁄0

$)

1 x2+2

--------------* +, - 1 x+

2------------* +, - 2

* +. /, -

ln 2tan 1– x– 02---+ for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,3445446

1 !– h $'( )[ ] $'d $'⁄0

$)

2 1 x2+2

--------------* +, -ln for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,34546

k2

z z0⁄( )ln %m z L⁄( )–[ ]2---------------------------------------------------------- k2

z zT 0⁄( )ln %m z L⁄( )–[ ] z zT 0⁄( )ln %h z L⁄( )–[ ]---------------------------------------------------------------------------------------------------------------------

- 6.4 -

Atm S 547 Boundary Layer Meteorology Bretherton

(iii) Unstable limit. Convection replaces shear as the main source of eddy energy, so we expectthe eddy velocity to scale with the buoyancy flux B0 and not the friction velocity. We stillassume that the eddy size is limited by the distance z to the boundary. In this ‘free convectivescaling’, the eddy velocity scale is uf = (B0z)1/3 and the eddy viscosity should go as

Km = ku*z/!m " uf z # !m " u* / uf " (-z/L)-1/3 = (-$)-1/3

A similar argument applies to eddy diffusivity for scalars Kh. The empirical relations go as(-$)-1/2 for scalars and (-$)-1/4 for momenta, but reliable measurements only extend out to $= -2. Free convective scaling may be physically realized, but only at higher $.

Wind and thermodynamic profilesThe similarity relations can be integrated with respect to height to get:

u/u* = k-1 [ln(z/z0) - %m(z/L)]

(&0 ' & )/&* = k-1 [ln(z/zT0) - %h(z/L)] (and similarly for other scalars)

where if x = (1 - (1$)1/4,

%m($) =

=

%m($) =

=

Wind profiles in stable, neutral, and unstable conditions are shown in the figure below. Low-levelwind and shear are reduced compared to the log profile in unstable conditions, when Km is larger.From these,we derive bulk aerodynamic coefficients which apply in non-neutral conditions:

CD = , CH = (3)

These decrease considerably in stable conditions (see figure on next page). In observational anal-yses and numerical models, (3) and the formula for L are solved simultaneously to find surface heatand momentum fluxes from the values of u and &0 - & at the measurement or lowest grid-level z

1 !– m $'( )[ ] $'d $'⁄0

$)

1 x2+2

--------------* +, - 1 x+

2------------* +, - 2

* +. /, -

ln 2tan 1– x– 02---+ for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,3445446

1 !– h $'( )[ ] $'d $'⁄0

$)

2 1 x2+2

--------------* +, -ln for 2– $ 0 (unstable)< <,

1– $ for 0 $ (stable)2,34546

k2

z z0⁄( )ln %m z L⁄( )–[ ]2---------------------------------------------------------- k2

z zT 0⁄( )ln %m z L⁄( )–[ ] z zT 0⁄( )ln %h z L⁄( )–[ ]---------------------------------------------------------------------------------------------------------------------

Page 8: Answer - University of Utahkrueger/6220/MO-add.pdf3. Find u∗ and z0 from the following wind profile measurements made during statically neutral conditions at sunset: z (m) ¯u (m/s)