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    Write the mean value formula of the signal ( )y t .1

    0

    1 N

    i

    i

    y yN

    =

    = (1)

    Here,Number of samples isN .

    Since, there are 11samples. The value of N is eual to 11.

    !o"if# euation (1) for the mean value of signal ( )1y t .

    [ ]

    1

    1

    0

    0 1 $ % & ' ( ) * + 10

    1

    1

    11

    N

    i

    i

    y yN

    y y y y y y y y y y y

    =

    =

    = + + + + + + + + + +

    Substitute 0 for 0y , 11. for 1y , 1+.0$ for $y , 1+.0$ for %y , 11. for &y , 0 for 'y ,

    11. for (y , 1+.0$ for )y , 1+.0$ for *y , 11. for +y an" 0 for 10y .

    [ ]1 0 11. 1+.0$ 1+.0$ 11. 0 11. 1+.0$1

    11

    0

    1+.0$ 11. 0y + + + + + +=

    =

    Substitute 0 for 0y , 1'.$+ for 1y , $&.% for $y , $&.%for %y , 1'.$+ for &y , 0 for 'y ,

    1'.$+ for (y , $&.% for )y , $&.% for *y , 1'.$+ for +y an" 0 for 10y .

    ( ) ( ) ( ) ( )

    ( ) ( ) ( ) ( )

    $ $ $ $

    $ rms$ $ $ $

    0 1'.$+ $&.% $&.% 1'.$+ 01

    11 1'.$+ $&.% $&.% 1'.$+ 0

    %%*1.&$*

    11

    1.'%

    y + + + + + = + + + + +

    =

    =

    Hence, the rms value for the signal ( )$y t $ rmsy is 1.'% .

    Thus, the rms value of a signal having ero mean is a statistical measure of the

    fluctuations in the signal.