anchor bolt design as per bs
DESCRIPTION
Anchor bolt design of steel poles as per BS code, example sheetTRANSCRIPT
![Page 1: Anchor Bolt design as Per BS](https://reader036.vdocuments.us/reader036/viewer/2022081802/5695d01f1a28ab9b02910d13/html5/thumbnails/1.jpg)
DESIGN OF ANCHOR BOLT FOR POLE:
No.of bolt = 4
From staad analysis page no: 9 (FACTORED LOAD 13), JOINT: 03
Moment acting of base = 5.894 KNM
Tensile force acting on base = 8.444 KN
Based on moment,
Tensile force acting on base = 5.894/0.2= 29.47/2 = 14.74 KN
Tensile force acting/Bolt = 8.444/4 KN
= 2.11 KN
Total Tensile force acting /bolt = 14.74 + 2.11 = 16.85 KN
Shear force acting/Bolt = (0.0² + 4.603²)½ =4.603/4
= 1.15 KN
For M20, 8.8 Grade anchor,
Tensile Capacity of M20, 8.8 grade bolt = 109.80 KN
109.8 KN > 16.85 KN Hence Safe
![Page 2: Anchor Bolt design as Per BS](https://reader036.vdocuments.us/reader036/viewer/2022081802/5695d01f1a28ab9b02910d13/html5/thumbnails/2.jpg)
Shear Capacity of M20, 8.8 grade bolt = 91.90 KN
91.90 KN > 1.15 KN Hence Safe
Combined Tension & Shear Check,
16.85/109.80 + 1.15/91.90 <1.4
0.165 <1.4 Hence Safe
DESIGN OF BOND LENGTH:
Bond length Ld = F/π x dx x Tbd
Where, Tbd =1.534 N/mm² (for plain bar)
Tensile load = 16.85 KN
Ld = 16.85 x1000/πx20x1.534 = 175 mm