zkambing
Post on 20-Oct-2015
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Disscussion
1. UV rays found in sunlight . These UV rays work to break the covalent bonds between atoms of bromine. This fragmentation is also known as "homolytic cleavage". As a result of this created a homolytic cleavage of the unstable species is very reactive and we know as free radicals.
2. Solubility
Alkane : C6H14 + H2O C6H10 + H2O
Alkene : C6H10 + H2O C6H10+ H2O
Combustion
Alkane : 2C6H14 + 19O2 12CO2 + 14H2O
Alkene : 2C6H10+ 17O2 12CO2 + 10H2O
Bromine water
Alkane :Hexane C6H14 + bromine Br2 1,1-dibromohexane + hygrogen gas H2.
# cyclohexane, only the Br2 will react, but even it will require the addition ultraviolet light.
Alkene : cyclohexene C6H10 + bromine Br2 1,2-dibromocyclohexane
Iodine
Alkane : C6H14 +I2 C6H12 + I2
Alkene : cyclohexene C6H10 + Iodine I2 1,2-diiodocyclohexane
Baeyer test
Alkane : C6H14+ KMnO4 C6H12 + KMnO4
Alkene : cyclohexene C6H10 + KMnO4 1,2-cyclohexadiol
3. Cyclohexene, C6H10 is the most reactive hydrocarbon with bromine water and the easiest hydrocarbon oxidized by potassium permanganate solution in this experiment.
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