trigonometry

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Trigonometric Functions

The unit circle.Radians vs. DegreesComputing Trig Ratios

Trig IdentitiesFunctions

DefinitionsEffectsApplications

Review

hypotenuse

oppositesin

hypotenuse

adjacentcos

cos

sintan

adjacent

opposite

opposite

adjacent

hypotenuse

Starting with a right triangle, like the one pictured on the right, three basic trig ratios are defined as follows:

Review

opposite

adjacent

hypotenuse

opposite

hypotenuse

sin

1csc

adjacent

hypotenuse

cos

1sec

opposite

adjacent

tan

1cot

Three additional trig ratios are defined from the basic ratios as follows:

Table of Contents

The Unit Circle

360

2

deg

rees

radians

Consider the unit circle: a circle with a radius equal to one unit, centered at the origin.

The unit circle has a circumference: 2C

30°

2

2

23

43

6

45°

Radians relate directly to degrees:The distance around the unit

circle, starting at the point (1, 0)

equals the angle formed between

the x-axis and the radius drawn

from the origin to a point along

the unit circle.

60°

Distance around the unit circle is measured in radians.

The Unit CircleRadians vs. Degrees

180deg

rees

radiansThe conversion from radians to degrees or

the other way around uses the equation:

180120

x

Convert 120° to radians by solving the equation:

120180 x

180

120

180

180x

3

2x

Cross multiply to solve for x:

The Unit CircleRadians vs. Degrees

180deg

rees

radiansThe conversion from radians to degrees or

the other way around uses the equation:

Convert radians to degrees by solving the equation:4

5

1804

5

x

Cross multiply to solve for x:

x41805

x41805

x41805

x

4

4

4

1805

x455

225x

The Unit CircleComputing Trig Ratios

1

x

y

hypotenuse = 1x = cos y = sin tan = y/x

The trigonometric ratios can be computed using the unit circle.

To form the trig ratios, we need a right triangle inscribed in the unit circle, with one vertex placed at the origin so that the perpendicular sides are parallel to the x-axis & y-axis.

This triangle has the following relationships:

Notice that tan is the same as the slope of the line radiating out of the origin!

1

1

0

1/2

1/2

23

22

23

22

The Unit CircleComputing Trig RatiosUsing the newly defined relationship, the trig

ratios are determined by reading the x & y values off the graph.

x = cos y = sin tan = y/x

Note the pattern:Values increase

from 0 to 1 according to integral square roots.

angle sine

0 2

0

2

1 2

1

2

2 2

2

2

3 2

3

1 2

4

sin x cos x tan x

0 0 1 0

/6 2

1 2

3 3

1

/4 2

2 2

2 1

/3 2

3 2

1 3

/2 1 0

The Unit CircleComputing Trig Ratios

These trig ratios are summarized in the following table:

Table of Contents

Trig identities

In the first and forth quadrants x is positive while y changes sign.

As is swept up and down away from the positive x-axis, only its sign changes.

These characteristics lead to the following relationships:

x

cos (-) = cos ()sin (-) = -sin () tan (-) = -tan ()

Trig identities

cos (-) = -cos ()sin (-) = sin () tan (-) = -tan ()

y From the first to the second quadrants x changes sign while y remains positive.

As is swept up away from the positive and negative x-axis, equal angle sweeps are related as: : -.

These characteristics lead to the following relationships:

Trig identities - Examples:

6cos

6

7cos

6sin

6

5sin

4tan

4

7tan

a.) second quadrant:

b.) fourth quadrant:

c.) third quadrant:

6sin

2

3

4tan

1

6cos

6cos

6cos

2

3

Trig identities

sin2 + cos2 = 1

(1,0)x

y (cos ,sin )

1

Combining the Pythagorean Theorem with the properties of the right triangle inscribe in the unit circle we get the following trig identity, relating sine to cosine:

Note that when x = sin, 21cos x

(1,0)

(1 ,tan )

sec

1

Trig identities

sec2 = 1 + tan2Cosecant and Cotangent

are similarly related:

csc2 = 1 + cot2

A similar triangle combined with the Pythagorean Theorem produces the trig identity relating tangents to secants:

Trig identities

These other trig identities can also be derived from the unit circle:

cos(-) = coscos + sinsincos(+) = coscos - sinsincos(2) = cos2 - sin2sin(+) = sincos + cossinsin(-) = sincos - cossin

These trig identities are useful to solve problems such as:

43cos

12cos

4sin

3sin

4cos

3cos

Proof

Table of Contents

Functions

Consider the ratio expressed as a function:

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1 -0.5 0 0.5 1

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

xxfy sin:sin We can graph the function on the Cartesian

coordinates:

Functions - Definition

The function:

x

y

-1

-0.5

0

0.5

1

xxf sinhas the domain: ,

and range: 1,1

Functions - Definition

The function: xxf coshas the domain: ,

and range: 1,1

x

y

-1

-0.8

-0.6

-0.4

-0.2

0

0.2

0.4

0.6

0.8

1

Functions - Definition

The function: xxf tanhas the domain: ,...

2

3,

2,0

x

and range: ,

x

y

-4

-3

-2

-1

0

1

2

3

4

y = Asin (Bx-C)+DAmplitude (A):

Distance between minimum and maximum values.

Frequency (B): Number of intervals required for one complete cycle

Period (2/B): Length of interval containing one complete cycle

Phase Shift (C): Shift along horizontal axis.

Vertical Shift (D): Shift along vertical axis.

Functions - Effects

y = A(sin (Bx-C)

Examples:

Functions - Amplitude (A)

x

y

-3

-2

-1

0

1

2

3xy sin3

xy sin3

1

x

y

-3

-2

-1

0

1

2

3

x

y

-3

-2

-1

0

1

2

3

x

y

-3

-2

-1

0

1

2

3

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

y = A(sin (Bx-C)

Examples:

Functions – Frequency/Period (B)

xy 3sin

xy

3

1sin

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

Period = 2/3

Period = 6

x

y

-1

-0.5

0

0.5

1

y = A(sin (Bx-C)

Examples:

Functions – Phase (C)

3sin

xy

2sin

xy x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

x

y

-1

-0.5

0

0.5

1

xcos

What does the sine curve represent?Periodic Behavior:

SoundWaves, TidesSpringsCyclic growth and decay

Consider the waves in the ocean,The amplitude effect their heightChoppy water is caused a high frequencyFlat seas indicate that there is a low frequency

and amplitude

Functions - Applications

Low tide occurs in some port at 10:00 am on Monday and again at 10:24 pm that same night. At low tide the water level is 1 foot and at high tide it measures 7 feet. What is the sine function that represents the water level?

Functions - Applications

Amplitude:The difference between low and high tide is 7-1=6 feet.

The amplitude is half that difference: 6/2=3 feet

Vertical Shift:The average water level: .4

2

71ft

Frequency:Time between high tides: 12 hrs. 24 min. = 12.4 hrs.

Period : 507.04.12

2

ttf 507.0sin34

Practice:1. Express 135 in radians:

360

2

135

135180

180

135

4

3

2. Convert 4/3 radians to degrees:

1803

4

60

14

240

1803

4

Express the following trig ratios as multiples of a simple radical expression:

Practice:

3cos

2

3sin

4

3tan

12

sin2

sin

14

tan4

tan

2

1

3cos

Express the following trig ratios as multiples of a simple radical expression:

Practice:

3

2sin

3

2tan

4

3cos

2

3

3sin

3sin

2

2

4cos

4cos

33

tan3

tan3

2tan

4sin1

xy

42sin21

xy

xy 2sin32

Match the curve to the equation:

Practice:

x

y

-0.5 0 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 6.5

-1

0

1

2

3

4

A.

B.

C.

B

A

C

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