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Math 1000

Stuart Jones

Section2.6

Transformations of Functions

Math 1000

Stuart Jones

Parent Functions

Linear Function y = x

Quadratic Function y = x2

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Stuart Jones

Parent Functions

Cubic Function y = x3

Square Root Function y =√x

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Parent Functions

Absolute Value Function y = |x |

Constant Function y = b for some constant b

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Transformations

Theorem (Translations)

Given a function f (x), it can be shifted around the graph usingthe following modifications, called translations:

f (x) + a is a vertical shift of a units upwards

f (x)− b is a vertical shift of b units downwards

f (x + c) is a horizontal shift c units left

f (x − d) is a horizontal shift d units right

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) = x2, g(x) = (x − 7)2

Answer: Shift right 7 unitsf (x) =

√(x) g(x) =

√(x) + 6

Answer: Shift up 6 units

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) = x2, g(x) = (x − 7)2

Answer: Shift right 7 units

f (x) =√

(x) g(x) =√

(x) + 6Answer: Shift up 6 units

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) = x2, g(x) = (x − 7)2

Answer: Shift right 7 unitsf (x) =

√(x) g(x) =

√(x) + 6

Answer: Shift up 6 units

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) = x2, g(x) = (x − 7)2

Answer: Shift right 7 unitsf (x) =

√(x) g(x) =

√(x) + 6

Answer: Shift up 6 units

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Stuart Jones

Graph f (x) = |x | − 4

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Stuart Jones

Graph f (x) = |x | − 4

Math 1000

Stuart Jones

Theorem (Reflections over x and y axis)

Given a function h(x), a reflection is obtained by flipping thefunction over the x or y axis.

f (−x) reflects the function over the y-axis

−f (x) reflects the function over the x-axis.

Math 1000

Stuart Jones

Explain how the graph of j is obtained from the graph of h.h(x) = x2, j(x) = −x2

Answer: Reflection over the x-axis.h(x) = x3, j(x) = (−x)3 Answer: Reflection over y-axis.

Math 1000

Stuart Jones

Explain how the graph of j is obtained from the graph of h.h(x) = x2, j(x) = −x2Answer: Reflection over the x-axis.

h(x) = x3, j(x) = (−x)3 Answer: Reflection over y-axis.

Math 1000

Stuart Jones

Explain how the graph of j is obtained from the graph of h.h(x) = x2, j(x) = −x2Answer: Reflection over the x-axis.h(x) = x3, j(x) = (−x)3

Answer: Reflection over y-axis.

Math 1000

Stuart Jones

Explain how the graph of j is obtained from the graph of h.h(x) = x2, j(x) = −x2Answer: Reflection over the x-axis.h(x) = x3, j(x) = (−x)3 Answer: Reflection over y-axis.

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Graph −x2

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Graph −x2

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Stuart Jones

Theorem (Stretches and Compressions)

A function f (x) can be stretched or compressed vertically orhorizontally by the coefficient.

f (ax) is a horizontal compressions when a > 1 and astretch when a < 1

bf (x) is a vertical stretch when b > 1 and a compressionwhen b < 1

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) =

√x . g(x) = 3

√x

Answer: A vertical stretchf (x) = x2, g(x) = 1

4x2

Answer: A vertical compression

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) =

√x . g(x) = 3

√x

Answer: A vertical stretch

f (x) = x2, g(x) = 14x

2

Answer: A vertical compression

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) =

√x . g(x) = 3

√x

Answer: A vertical stretchf (x) = x2, g(x) = 1

4x2

Answer: A vertical compression

Math 1000

Stuart Jones

Explain how the graph of g is obtained from the graph of f.f (x) =

√x . g(x) = 3

√x

Answer: A vertical stretchf (x) = x2, g(x) = 1

4x2

Answer: A vertical compression

Math 1000

Stuart Jones

Given the parent graph, f (x) = x2 below, graph h(x) = 3x2

and g(x) = 13x

2

The cyan graph is h(x) and the gray graph is g(x)

Math 1000

Stuart Jones

Given the parent graph, f (x) = x2 below, graph h(x) = 3x2

and g(x) = 13x

2

The cyan graph is h(x) and the gray graph is g(x)

Math 1000

Stuart Jones

Given the parent graph, f (x) = x2 below, graph h(x) = 3x2

and g(x) = 13x

2

The cyan graph is h(x) and the gray graph is g(x)

Math 1000

Stuart Jones

Given the parent graph, f (x) = x2 below, graph h(x) = 3x2

and g(x) = 13x

2

The cyan graph is h(x) and the gray graph is g(x)

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = x , g(x) = 2x − 4

Answer: Stretched vertically (orcompressed horizontally) by a factor of 2, then shifted down 4unitsf (x) = x3, g(x) = −(x − 4)3 + 1 Answer: Reflected over they-axis downward, and shifted 4 units right and 1 unit up

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = x , g(x) = 2x − 4 Answer: Stretched vertically (orcompressed horizontally) by a factor of 2, then shifted down 4units

f (x) = x3, g(x) = −(x − 4)3 + 1 Answer: Reflected over they-axis downward, and shifted 4 units right and 1 unit up

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = x , g(x) = 2x − 4 Answer: Stretched vertically (orcompressed horizontally) by a factor of 2, then shifted down 4unitsf (x) = x3, g(x) = −(x − 4)3 + 1

Answer: Reflected over they-axis downward, and shifted 4 units right and 1 unit up

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = x , g(x) = 2x − 4 Answer: Stretched vertically (orcompressed horizontally) by a factor of 2, then shifted down 4unitsf (x) = x3, g(x) = −(x − 4)3 + 1 Answer: Reflected over they-axis downward, and shifted 4 units right and 1 unit up

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = |x |, g(x) = −|12x + 1| − 2

Answer: Reflected (flipped)over the y-axis, stretched horizontally by a factor of 1/2, andshifted left 1 and down 2.f (x) =

√x , g(x) = −

√2x − 4 + 1 Answer: Reflected over

y-axis, compressed horizontally by a factor of 2, and shiftedright 4 and up 1.

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = |x |, g(x) = −|12x + 1| − 2 Answer: Reflected (flipped)over the y-axis, stretched horizontally by a factor of 1/2, andshifted left 1 and down 2.

f (x) =√x , g(x) = −

√2x − 4 + 1 Answer: Reflected over

y-axis, compressed horizontally by a factor of 2, and shiftedright 4 and up 1.

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = |x |, g(x) = −|12x + 1| − 2 Answer: Reflected (flipped)over the y-axis, stretched horizontally by a factor of 1/2, andshifted left 1 and down 2.f (x) =

√x , g(x) = −

√2x − 4 + 1

Answer: Reflected overy-axis, compressed horizontally by a factor of 2, and shiftedright 4 and up 1.

Math 1000

Stuart Jones

Combining TransformationsExplain how the graph of g(x) is obtained from f(x).f (x) = |x |, g(x) = −|12x + 1| − 2 Answer: Reflected (flipped)over the y-axis, stretched horizontally by a factor of 1/2, andshifted left 1 and down 2.f (x) =

√x , g(x) = −

√2x − 4 + 1 Answer: Reflected over

y-axis, compressed horizontally by a factor of 2, and shiftedright 4 and up 1.

Math 1000

Stuart Jones

Graph g(x) =√−x − 1

The red graph is the parent graph. G(x) is shown in blue.

Math 1000

Stuart Jones

Graph g(x) =√−x − 1

The red graph is the parent graph. G(x) is shown in blue.

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Graoh f (x) = −x3 − 1

The parent graph is shown in red. The graph of f(x) is shown

in magenta.

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Stuart Jones

Graoh f (x) = −x3 − 1The parent graph is shown in red. The graph of f(x) is shown

in magenta.

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Stuart Jones

Graph f (x) = 35 |x − 1|+ 2

The parent function is shown in red. The graph of f(x) isshown in purple.

Math 1000

Stuart Jones

Graph f (x) = 35 |x − 1|+ 2

The parent function is shown in red. The graph of f(x) isshown in purple.

Math 1000

Stuart Jones

Even and Odd Functions

Theorem (Even and Odd Functions)

An even function is a function f (x) such thatf (−x) = f (x) for all x.

An odd function is a function f (x) such thatf (−x) = −f (x) for all x.

Graphically, even functions are symmetric with respect tothe y-axis.

Graphically, odd functions are symmetric with respect tothe origin.

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Decide whether each function is even, odd, or neither.

y = x4

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Decide whether each function is even, odd, or neither.

y = 4x3 − 2x

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Decide whether the function is even, odd, or neither:

y = x3 − x2

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The Bottom Line

Numbers inside the function affect x; numbers outside thefunction affect y.

Translations shift a function around the coordinate plane.

Reflections flip a function over the x-axis or y-axis.

Coefficients stretch or compress functions in the x- ory-direction.

Even and odd functions can make it easier to graph themif you know the symmetry involved.

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