simulation of electronic circuits using pspice
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SIMULATION OF ELECTRONIC CIRCUITS
USING PSPICE
(LINEAR INTEGRATED CIRCUITS LAB)
SWAGAT KARNANY 109/EC/07
INDEX
S.No. Expt No.
AIM Page no.
Sign.
1. I Basic applications of op-amps: AC, DC, and transient response of non-inverting and inverting amplifiers.
3
2. II To plot transient response of op-amp integrator and differentiator giving input as square and triangle wave respectively.
10
3. III Create a macro-model of op-amp taking into account Ao, wp, Rin and Rout. Simulate a non-inverting amplifier , its compensated version and compensated inverting amplifier.Plot the magnitude response and phase response.
14
4. IV To simulate differential amplifier based with current mirror .Carry out the DC, AC and transient analysis.
22
5. V PSpice simulation of KHN Biquad filter. 27
2
EXPERIMENT NO. 1
AIM: Basic applications of op-amps: AC, DC and transient response of non-inverting and inverting amplifiers.
THEORY:An operational amplifier is a DC-coupled high-gain electronic voltage amplifier with differential inputs and, usually, a single output. In its ordinary usage, the output of the op-amp is controlled by negative feedback which, because of the amplifier's high gain, almost completely determines the output voltage for any given input. The usual circuit symbol for an op-amp is:
where:V+: non-inverting input V−: inverting inputVout: outputVS+: positive power supply (sometimes also VDD, VCC, or VCC + )VS−: negative power supply (sometimes also VSS, VEE, or VCC − )
Types of Analysis:Pspice allows various types of analysis. The types of analysis and their corresponding .(dot) commands are follows:DC analysisDC sweep of an input voltage/current source, a model parameter, or temperature (.DC)Linearized device model parameterization (.OP)DC operating point (.OP)Small signal transfer function (Thevenin’s equivalent) (.TF)Small signal sensitivities (.SENS)
Transient AnalysisTime domain response (.TRAN)Fourier analysis (.FOUR)
3
AC Analysis : Small signal frequency response (.AC)Noise analysis (.NOISE)
Non-inverting amplifier
*Non-Inverting Amplifier - AC Analysis
R1 0 2 1kR2 2 6 2kX 3 2 7 4 6 UA741.lib c:\msimev71\lib\eval.libVP 7 0 DC 12VVN 0 4 DC 12VVIN 3 0 AC 0.1V.AC DEC 50 1Hz 1MegHz.PROBE.END*Non-Inverting Amplifier - DC AnalysisR1 0 2 1kR2 2 6 2kX 3 2 7 4 6 UA741.lib c:\msimev71\lib\eval.libVP 7 0 DC 12VVN 0 4 DC 12VVIN 3 0 DC 0V.DC LIN VIN -10 10 0.1V
4
.PROBE
.END
* Non-Inverting Amplifier - Transient AnalysisR1 0 2 1kR2 2 6 2kX 3 2 7 4 6 UA741.lib c:\msimev71\lib\eval.libVP 7 0 DC 12VVN 0 4 DC 12VVIN 3 0 sin(0.005 0.01 1KHz).TRAN 0.01ms 5ms 0ms 0.01ms.PROBE.END
5
Inverting Amplifier
*Inverting Amplifier - AC AnalysisR1 1 2 1kR2 2 6 10kX 0 2 7 4 6 UA741.lib "nom.lib"VP 7 0 DC 12VVN 0 4 DC 12VVIN 1 0 AC 0.1V.AC DEC 50 1Hz 1MegHz.PROBE.END
6
*Inverting Amplifier - DC AnalysisR1 1 2 1kR2 2 6 2kX 0 2 7 4 6 UA741.lib "nom.lib"VP 7 0 DC 12VVN 0 4 DC 12VVIN 1 0 DC 0V.DC LIN VIN -10 10 0.1V .PROBE.END
7
*Inverting Amplifier - Transient AnalysisR1 1 2 1kR2 2 6 10kX 0 2 7 4 6 UA741.lib "nom.lib"VP 7 0 DC 12VVN 0 4 DC 12VVIN 1 0 sin(0 0.01 1KHz).tran 0.01ms 5ms 0ms 0.01ms.PROBE.END
8
9
EXPERIMENT NO. 2
AIM: To plot transient response of op-amp integrator and differentiator giving input as square and triangle wave respectively.
THEORY:
Op-amp integrator
A circuit in which output voltage is directly proportional to the integral of the input is known as an integrator or the integration amplifier. Such a circuit is obtained by using operational amplifier in the inverting configuration with the feedback resistor R replaced by a capacitor, C. The transfer function is derived as follows:Vin/R = -Vout x sC
Vout/Vin = -1/sCR
Op-amp differentiator
A circuit in which output waveform is the derivative of the input waveform is known as the differentiator or the differentiation amplifier. Such a circuit is obtained by using operational amplifier in the inverting configuration connecting a capacitor, C at the input. The transfer function is derived as follows:Vin x sC = -Vout/R
Vout/Vin = -Scr
10
INTEGRATOR PROGRAM
* OPAMP INTEGRATOR SURBHI.LIB "NOM.LIB"X 0 2 7 4 6 UA741R1 1 2 .5KC1 2 6 10UVdd 7 0 DC 12VVss 0 4 DC 12VVin 1 0 PULSE( -2V 2V 0S 1NS 1NS .05S .1S).TRAN 10MS 1S.PROBE.END
INTEGRATOR FREQUENCY RESPONSE
* OPAMP INTEGRATOR SURBHI.LIB "NOM.LIB"X 0 2 7 4 6 UA741Vdd 7 0 DC 12VVss 0 4 DC 12VVin 2 0 AC 1V.AC DEC 50 .5HZ 1MEGHZ.PROBE.END
11
INTEGRATION:
Time
0s 0.1s 0.2s 0.3s 0.4s 0.5s 0.6s 0.7s 0.8s 0.9s 1.0sV(6) V(1)
-10V
0V
10V
20V
FREQUENCY RESPONSE:
Frequency
100mHz 1.0Hz 10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHz 10MHzV(6)
0V
50KV
100KV
150KV
200KV
12
DIFFERENTIATOR PROGRAM
* OPAMP DIFFERENTIATOR BY SURBHI .LIB "NOM.LIB"
X 0 2 7 4 6 UA741R1 2 6 .5KC1 1 2 10UVdd 7 0 DC 12VVss 0 4 DC 12VVin 1 0 PWL(0 0 .5M 5 1M 0 1.5M 5 2M 0 2.5M 5 3M 0 3.5M 5 4M 0).TRAN 10NS 4MS.PROBE.END
Time
0s 0.5ms 1.0ms 1.5ms 2.0ms 2.5ms 3.0ms 3.5ms 4.0msV(1) V(6)
-20V
-10V
0V
10V
20V
13
EXPERIMENT NO. 3
AIM: Create a macro-model of op-amp taking into account Ao, wp, Rin and Rout. Simulate a non-inverting amplifier , its compensated version and compensated inverting amplifier . Plot the magnitude response and phase response.
THEORY:
The following circuit diagrams are attached:1. Macro-model of op-amp2. Non-inverting amplifier (without compensation)3. Compensated non-inverting amplifier 4. Compensated inverting amplifier
The parameters of the one-pole op-amp macro-model are:Ao = 2 x 105
wp = 10 Hz.Rin = 2 Mega ohmRout = 75 ohm
The transfer function for the non-inverting amplifier is:Vo/Vin = 1 + R2/R1
The compensated non-inverting amplifier behave like a low pass filter, the transfer function of which is given byT(s) = 1+R2/R1 ts(1+R2/R1)+1
where: t = 1/ wp Ao.
14
MACROMODEL OF OPAMP
*MACROMODEL OF OPAMP BY SURBHI X 3 2 6 OPAMP1.SUBCKT OPAMP1 3 2 6R1 3 0 10MEGR2 3 2 2MEGR3 0 2 10MEGE1 4 0 3 2 2E5RP 4 5 1KCP 5 0 32UE2 10 0 5 0 1R0 10 6 75.ENDS OPAMP1
15
UNCOMPENSATED NON-INVERTING AMPLIFIER
*NON INVERTING AMPLIFIER BY SURBHI .LIB "NOM.LIB"X 3 2 7 4 6 UA741R1 2 0 1KR2 2 6 1KVdd 7 0 DC 15VVcc 0 4 DC 15VVin 3 0 AC .1V.AC DEC 50 10HZ 1MEGHZ.PROBE.END
16
MAGNITUDE RESPONSE
Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHzV(6) V(3)
80mV
120mV
160mV
200mV
PHASE RESPONSE
Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHzP(V(6)) P(V(3))
-100d
-50d
0d
17
COMPENSATED NON-INVERTING AMPLIFIER
*COMPENSATED NON INVERTING AMPLIFIER GAIN VS FREQUENCY BY SURBHI.LIB C:\EC2\MACROOP1.LIBX1 3 2 6 OPAMP1X2 6 5 4 OPAMP1R1 2 0 1KR2 2 4 1KR3 6 5 1KR4 5 4 1KVin 3 0 AC .1V.AC DEC 50 10HZ 1MEGHZ.PROBE.END
18
MAGNITUDE RESPONSE
Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHzV(3) V(6)
100mV
200mV
300mV
400mV
PHASE RESPONSE
Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHzP(V(6)) P(V(3))
-100d
-50d
0d
50d
19
COMPENSATED INVERTING AMPLIFIER
*COMPENSATED INVERTING AMPLIFIER BY SURBHI.LIB C:\EC2\MACROOP1.LIBX1 1 2 4 OPAMP1X2 1 3 7 OPAMP1X3 1 9 6 OPAMP1R1 4 3 2KR2 3 0 2KR3 3 6 2KR4 7 9 .5KR5 9 6 .5KR6 2 0 2KR7 6 2 .5KVin 1 0 AC .1V.AC DEC 50 10HZ 1MEGHZ.PROBE.END
20
MAGNITUDE RESPONSE
Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHzV(6) V(1)
50mV
100mV
150mV
PHASE RESPONSE
Frequency
10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHzP(V(6)) P(V(1))
-60d
-40d
-20d
-0d
21
EXPERIMENT NO. 4
AIM-To simulate differential amplifier based with current mirror .Carry out the DC, AC and transient analysis.
22
DC ANALYSIS
Vcm=0,Rc1 & Rc2 are removed and Vd is varied from -5V to 5V.
* DC ANALYSIS OF DIFFERENTIAL AMPLIFIER BIASED WITH CURRENT MIRROR BY SURBHI.LIB "NOM.LIB"Q1 4 1 2 Q2N2222Q2 5 3 2 Q2N2222Q3 8 8 9 Q2N2222Q4 2 8 9 Q2N2222Vd 10 0 DC 1VRd 10 0 1Vcc 6 0 DC 5VVee 0 9 DC 5VVc1 6 4 DC 0VVc2 6 5 DC 0VE1 1 0 10 0 0.5E2 0 3 10 0 0.5Rb 8 0 4.3K.DC Vd -5V 5V .1V.PROBE.END
23
Vd
-5.0V -4.0V -3.0V -2.0V -1.0V 0.0V 1.0V 2.0V 3.0V 4.0V 5.0VI(Vc1) I(Vc2)
0A
0.4mA
0.8mA
1.2mA
AC ANALYSISVc1 and Vc2 are removed and Rc1=Rc2=1kohms
* AC ANALYSIS OF DIFFERENTIAL AMPLIFIER BIASED WITH CURRENT MIRROR BY SURBHI.LIB "NOM.LIB"Q1 4 1 2 Q2N2222Q2 5 3 2 Q2N2222Q3 8 8 9 Q2N2222Q4 2 8 9 Q2N2222Vd 10 0 AC 1VRd 10 0 1Vcc 6 0 DC 5VVee 0 9 DC 5VE1 1 7 10 0 0.5E2 7 3 10 0 0.5Rb 8 0 4.3KVcm 7 0 AC 1VRc1 6 4 1KRc2 6 5 1K.AC DEC 50 1HZ 10MEGHZ.PROBE.END
24
Frequency
1.0Hz 10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHz 10MHzIC(Q1)-IC(Q2)
19.0mA
19.5mA
20.0mA
TRANSIENT ANALYSIS
* TRANSIENT ANALYSIS OF DIFFERENTIAL AMPLIFIER BIASED WITH CURRENT MIRROR BY SURBHI.LIB "NOM.LIB"Q1 4 1 2 Q2N2222Q2 5 3 2 Q2N2222Q3 8 8 9 Q2N2222Q4 2 8 9 Q2N2222Vd 10 0 SIN(0 0.1V 1KHZ)Rd 10 0 1Vcc 6 0 DC 5VVee 0 9 DC 5VE1 1 7 10 0 0.5E2 7 3 10 0 0.5Rb 8 0 4.3KVcm 7 0 AC 0VRc1 6 4 1KRc2 6 5 1K.TRAN 1US 10MS .PROBE.END
25
Time
0s 1ms 2ms 3ms 4ms 5ms 6ms 7ms 8ms 9ms 10msV(4)-V(5) V(10)
-1.0V
-0.5V
0V
0.5V
1.0V
26
Time
0s 1ms 2ms 3ms 4ms 5ms 6ms 7ms 8ms 9ms 10msIC(Q1) IC(Q2)
0A
0.4mA
0.8mA
1.2mA
OUTPUT
Differential mode gain, Ad=19.949
Common mode gain, Ac=6.614 * 10^-3
Common mode rejection ratio, CMRR=2994.71(normal scale)
=69.52(DB)
27
EXPERIMENT NO. 5
AIM-PSpice simulation of KHN Biquad filter
X1: AdderX2: IntegratorX3: IntegratorR1 = R2 = 20kR3 = Rf = 10kRa = Rb = 707ohmC1 = C2 = 0.01 Uf
28
*KHN BIQUAD FILTER BY SURBHI.LIB "NOM.LIB"X1 3 2 7 4 6 UA741X2 0 5 7 4 8 UA741X3 0 9 7 4 10 UA741Vdd 7 0 DC 10VVss 0 4 DC 10VR1 2 10 20KR2 1 3 20KR3 3 8 10KRf 2 6 10KRa 6 5 707Rb 8 9 707C1 5 8 0.01UFC2 9 10 0.01UFVin 1 0 AC 10V.AC DEC 50 1HZ 10MEGHZ.PROBE.END
29
Frequency
1.0Hz 10Hz 100Hz 1.0KHz 10KHz 100KHz 1.0MHz 10MHzV(8) V(10) V(1) V(6)
0V
4V
8V
12V
30
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