problems set 03 with solutions
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7/22/2019 Problems Set 03 With Solutions
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o sa s y es gn m a ons s necessary
to determine the effect of the 2-kNtension in the cable on the shear, tension,
- .
purpose replace this force by its
equivalent of two forces at A, Ft parallel
n .Determine Ft and Fn.
t=
1.28 kNt
F=2sin50
nF =
.n=
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Determ ne t e magn tu e Fs
o
e ens e spr ng orce n or er
s
ma nitude R of this verticalresultant force.
cos120
s=
60sF =
sin60120
=
103.92 lbR=
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7/22/2019 Problems Set 03 With Solutions
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In t e es gn o a contro
mec an sm, s e erm ne a
thex and scalar com onents of P.
5tan=
-1 5
12
260cos 22.62P = .=
240 Nx
P =
260sin 22.62yP =
y
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For t e mec an sm s own,
e erm ne e sca ar
t n
,
, .
5tan
12=
22.62=
30 30 22.62 = =
260cos 7.38P = 7.38=
n
257.84 Nn
P =
( )260sin 7.38tP=
.t
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I t e equa tens ons T n t e
pu ey ca e are , express
.ma nitude of R.
x xR F=
400 400cos60x
R = +
x =R F=
y y
400sin60y
R =
346.41 Ny
R = 600 346.41R i j= +
( ) ( )2 2
600 346.41R= +.=
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,exerts a 180 N force P as shown
Determine the components of P
which are parallel and
perpendicular to the incline.
180cos25t
P=
163.13 NtP=
180sin25P =
76.07 Nn
P =
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7/22/2019 Problems Set 03 With Solutions
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The normal reaction forceNand the
tangential friction force Fact on the tireof a front wheel drive car as shown.
forces in terms of the unit vectors a i
and j along thex-y axes and (b)etand e
nalong the n-t axes shown.
( ) 400cos15 900cos105 lbx
a R i= +
400sin15 900 105 lbR sin j= +
.x
972.86 lbR j=
153.43 972.86 lbR i j= +
( ) 400 900 lb t nb R e e= +
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e erm ne e resu an
o e wo orces app e
to t e rac et. r te n
terms of unit vectors
along thex-andy-axes.
x xR F=
200cos35 150cos120x
R = +
.x=R F=
y y
200sin35 150sin120y
R = +
244.61 Ny
R =
88.83 244.61 NR i j= +
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drag forceD for the simple airfoil isL/D=10. If the lift force on a short
sect on o t e a r o s 50 ,
resultant forceR and the an le which it makes with the horizontal.
10, L=50 lbL
=
50
102 2
2 250 5 50.25 lbR= + =
1 1 50tan tanL
= =
5D= .
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