practice quiz 3

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Practice Quiz 3. Hurley 4.3 - 4.7. For the quiz …. I will provide you with a categorical proposition, like… No apples sold in Minnesota are mushy weapons I’ll ask you for its quality qualifier quantity quantifier copula distribution letter name terms. 1. Consider: - PowerPoint PPT Presentation

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Practice Quiz 3Hurley 4.3 - 4.7

For the quiz …I will provide you with a categorical proposition,

like…No apples sold in Minnesota are mushy weapons

I’ll ask you for its quality qualifier quantity quantifier copula distribution letter name terms

1Consider:No non-A are B (T) Obversiona.Some non-A are B. (F)b.All A are non-B. (Und.)c.All non-A are non-B. (T)d.Some non-A are not B. (T)e.No B are non-A. (T)

2Consider:All A are non-B. (F) Contrapositiona.All A are non-B. (F)b.All non-B are A. (Und.)c.No non-A are B. (Und.)d.All B are non-A. (F)e.Some non-A are not B. (T)

3Consider:Some A are not non-B. (T) Some A are B.a.Contraposition (T)b.Contrary (F)c.Conversion (T)d.Obversion (T)e.Subcontrary (Und.)

4Consider:Some non-A are B. (F) Some B are non-A.a.Subcontrary (T)b.Conversion (Und.)c.Contraposition (Und.)d.Conversion (F)e.Contraposition (F)

5Assume Aristotle (Traditional standpoint).Consider:Some A are non-B. (F) Some A are not non-B.

(F)a. Illicit, contraryb. Illicit, subalternationc. Subcontraryd. Illicit, subcontrarye.Contraposition

6No S are P. (Aristotelian standpoint)

After filling in the diagram …a.Area 2 is shaded, and there is a circled X in area 1.b.Areas 1 and 3 are shaded.c.Area 1 is shaded, and there is a circled X in area 2.d.There is an X in area 2.e.Area 1 is shaded, and there are no other marks.

7All S are P. (Boolean standpoint)

After filling in the diagram …a.Areas 1 and 3 are shaded.b.Area 2 is shaded, and there are no other marks.c.Area 1 is shaded, and there is a circled X in area 2.d.There is an X in area 2.e.Area 1 is shaded, and there are no other marks.

8Shade area 2 and place an X in area 1.

Which of the following would be valid inferences:a.shaded area 2.b.an X in area 3.c.an X in area 1.d.shaded 1.e.no X’s or shadings.

9Shade area 1 and place an X in area 2.

Which of the following would be valid inferences:a.shaded area 2.b.an X in area 3.c.shaded area 1, and X in area 2.d.shaded 1.e.no X’s or shadings.

10Assume Aristotle (Traditional standpoint).Consider:No non-A are B. (T) Some non-A are not B. (F)a. Illicit, subalternationb. Illicit, contradictoryc. Contradictoryd. Illicit, subcontrarye.Conversion

11Assume Bool (Modern standpoint).Consider:No A are B. (T) Some A are B. (F)a.Existential fallacyb. Illicit, contradictoryc. Contradictoryd. Illicit, subcontrarye.Conversion

12Assume Bool (Modern standpoint).Consider:No A are B. (T) All A are B. (F)a.Existential fallacyb. Illicit, contraryc. Contradictoryd. Illicit, subcontrarye.Conversion

13Assume Aristotle (Traditional standpoint)All square circles are happy shapes.

Some square circles are happy shapes.a.Existential fallacyb.Valid, contradictoryc. Valid, subcontraryd. Invalid, subalternatione. Invalid, contrary

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