physics investigatory project on ohm's law
Post on 16-Aug-2015
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Part of Made in India,Design Innovation
Workshop,2015
A Fresh New Experience in
Project-‐Making and Learning
Do you know why a 100 W bulb glows brighter than a 40 W bulb? Ohm’s law will help you understand this, it states that the voltage drop across a component equals the product of thecurrent flowing through it and its resistance ( V= I R ). Hence, a 100 W bulb glows brighter as itoffers less resistance as compared to a 40 W bulb. Now, to verify this law one needs to make acircuit using a breadboard, an LED, a 100 Ω resistor, a 9V baQery and a few connecRng wires. A mulRmeter was connected in series to complete the circuit. The current across the resistor wascalculated using a mulRmeter and it was also calculated theoreRcally using Ohm’s law. Both thevalues were found to be approximately same.
Again, if a 100 Ω resistor was replaced by a 1 kΩ, and likewise its current value was calculated(as above), both the theoreRcal and the mulRmeter values were approximately the same.However, it was also observed that the current value and also the brightness of the LEDdecreased as compared to the former case. AlternaRvely, the value of resistance (R=V/I) wasalso found using the mulRmeter readings of voltage and current across the resistor, which wasnearly equal to the theoreRcal value of the resistance. It was inferred that the raRo of voltageto current remains the same for a fixed resistance. Hence, Ohm’s law was verified.
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