paper 4 (calculator) trigonometry - glyn maths gcse -...
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Surname Initial(s) Centre Paper Reference No.
Candidate 1 3 8 0 I 4 H Signature
No.
Peper Referenc:e(s)
1380/4H Examiner's use only
Edexcel GCSE Mathematics (Linear)- 1380 Paper 4 (Calculator)
Team Leader's use only
Trigonometry Past Paper Questions
Arranged by Topic Model Answers
Materials required for examination Ruler graduated in centimetres and millimetres, protractor, compasses, pen, HB pencil, eraser, calculator. Tracing paper may be used.
Instructions to Candidates
Items included with question papers Nil
In the boxes above, write your centre number, candidate number, your surname, initials and signature. Check that you have the correct question paper. Answer ALL the questions. Write your answers in the spaces provided in this question paper. You must NOT write on the formulae page. Anything you write on the formulae page will gain NO credit. If you need more space to complete your answer to any question, use additional answer sheets.
Information for Candidates The marks for individual questions and the parts of questions are shown in round brackets: e.g. (2). There are 26 questiorn in this question paper. The total mark for this paper is 100. There are 24 pages in this question paper. Any blank pages are indicated. Calculators may be used. If your calculator does not have an button, take the value ofn to be 3.142 unless the question instructs otherwise.
Advice to Candidates Show all stages in any calculations. Work steadily through the paper. Do not spend too long on one question. If you cannot answer a question, leave it and attempt the next one. Return at the end to those you have left out.
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GCSE Mathematics (Linear) 1380
Fonnul ae: Higher Tier
You must not write on this for·mulae page. Anything you write on this formulae page will gain NO credit.
Volume of a prism = area of cross section x length
Volume of sphere = 4nr3
.)
Surface area of sphere = 4nr2
In any triangJe ABC
S. R I a b c me u e --= --= --sin A sin B sin C
Area of triangle =!ab sin C
Volume of cone =+nr2h .)
Curved sur·face area of cone = nrl
T he Quadratic Equation
The solutions of ax2 + bx + c = 0
where a:~- 0, are given by
- b ±~(b2 - 4ac) X = -----''-'----'-
2a
_ I
AdjacentcosHypotenuse
8.2cos10.6
39.323
x
x
=
=
=
39.3
51.3
AdjacentcosHypotenuse
5cos8
51.3178
x
x
=
=
=
OppositetanAdjacent
=
tan 4012.5
12.5 tan4010.488
y
yy
=
==
o
o
10.5
OppositetanAdjacent
=
tan4012.5
4tan10
21.8014
y
RPQ
RPQ
=
=
∠ =
o
21.8
121 8 7228
A bh
A
A
=
= × ×
=
2 2 2
2 2 2
2
2
7 849 64113
11310.6301
AC AB BCACACAC
ACAC
= += += +=
==
10.63
28
OppositetanAdjacent
=
32tan46
34.8244
y
y
=
=
34.8
121 14 6242
A bh
A
A
=
= × ×
=
42
2 2 2
2
2
14 6196 36232
23215.2315
ABABAB
ABAB
= += +=
==
15.23
AdjacentcosHypotenuse
=
cos5816
16cos588.4787
AB
ABAB
=
==
o
o
8.48
1 sin21 9 15sin110264.4292
A ac B
A
A
=
= × ×
=
o
64.4
OppositetanAdjacent
=
2.4tan4.5
28.072
x
x
=
=
28.1
180 90 28.07261.928
AA
∠ = − −∠ =
Bearing of C from A180 61.928
118.072−
= 118
2 2 2
2 2 2
cos2
10 12 15cos2 10 12
19cos240
85.459
b c aAbc
A
A
A
+ −=
+ −=× ×
=
= (use or INV cos key)1cos−
85.5
2 2 2
2 2 2
2
2
8 364 955
7.42
CB CA ABCBCBCBCB
= −= −= −=
=Oppositesin
Hypotenuse=
(Pythagoras)
7.42sin50
sin50 7.427.42 9.686
sin50
CDCD
CD
=
=
= =
o
o
o
9.69
( )( )
2 2 2
2 2 2
2
2 cos
9.69 19 2 9.69 19cos 40
172.823
172.82313.1462
d e c ec D
d
d
dd
= + −
= + − × ×
=
==
o
13.2
- 1
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