mrs. rivas (5-1) algebra find the value of x. 1

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Mrs. Rivas

Homework

(5-1) Algebra Find the value of x.

𝟐(𝟐 𝒙+𝟏)=πŸπŸ–πŸ’ 𝒙+𝟐=πŸπŸ–

πŸ’ 𝒙=πŸπŸ”π’™=πŸ’

1.

Mrs. Rivas

Homework

(5-1) Algebra Find the value of x.

𝟐(πŸ‘ 𝒙 )=πŸ‘πŸŽπŸ” 𝒙=πŸ‘πŸŽπ’™=πŸ“

2.

Mrs. Rivas

Homework

(5-1) Algebra Find the value of x.

3.

𝟐(πŸ‘ 𝒙 )=πŸπŸπŸ” 𝒙=πŸπŸπ’™=πŸ‘ .πŸ“

Mrs. Rivas

Homework

X is the midpoint of . Y is the midpoint of .

4. Find XZ.

πŸ—

Mrs. Rivas

Homework

X is the midpoint of . Y is the midpoint of .

5. If XY = 10, find MO.

𝟐𝟎

Mrs. Rivas

Homework

X is the midpoint of . Y is the midpoint of .

6. If is , find .

πŸ”πŸ’

πŸ”πŸ’

Mrs. Rivas

Homework

Use the diagram at the right for Exercises 7 and 8.

7. What is the distance across the lake?

πŸ“ .πŸ“

Mrs. Rivas

Homework

Use the diagram at the right for Exercises 7 and 8.

8. Is it a shorter distance from A to B or from B to C? Explain.

πŸ“ .πŸ“πŸ’

BC is shorter. BC is half od 8 and AB is half od 11.

Mrs. Rivas

Homework

(5-2) Algebra Find the indicated variables and measures.

10. x, EH, EF

πŸ“ 𝒙+πŸ‘=πŸ• π’™βˆ’πŸπŸ“ 𝒙 πŸ“ 𝒙

πŸ‘=𝟐 π’™βˆ’πŸ+𝟏+𝟏

πŸ’=𝟐 π’™πŸ=𝒙

𝑬𝑯=πŸ“π’™+πŸ‘=πŸ“ (𝟐 )+πŸ‘=πŸπŸ‘

𝑬𝑭=πŸ• π’™βˆ’πŸ=πŸ• (𝟐 )βˆ’πŸ=πŸπŸ‘

Mrs. Rivas

Homework

(5-2) Algebra Find the indicated variables and measures.

11. x, mTPS, mRPS

𝟐 𝒙 β€“πŸ”=πŸ‘ 𝒙 β€“πŸπŸ“πŸ 𝒙 𝟐 π’™β€“πŸ”=𝒙 β€“πŸπŸ“

+πŸπŸ“+πŸπŸ“πŸπŸ—=𝒙

π’Žβˆ π‘»π‘·π‘Ί=𝟐 π’™βˆ’πŸ”=𝟐 (πŸπŸ—)βˆ’πŸ”=πŸ‘πŸ

π’Žβˆ π‘Ήπ‘·π‘Ί=πŸ‘π’™ βˆ’πŸπŸ“=πŸ‘ (πŸπŸ—)βˆ’πŸπŸ“=πŸ‘πŸ

Mrs. Rivas

Homework

(5-2) Algebra Find the indicated variables and measures.

12. a, b

πŸ‘π’‚ β€“πŸ=𝒂+𝟏𝟎

πŸ‘π’ƒ β€“πŸπŸ“=πŸπ’ƒ+πŸ“

πŸπ’‚ β€“πŸ=πŸπŸŽπŸπ’‚=πŸπŸπ’‚=πŸ”

𝒃 β€“πŸπŸ“=πŸ“π’ƒ=𝟐𝟎

1.

Mrs. Rivas

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Mrs. Rivas

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2.

3.

Mrs. Rivas

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Mrs. Rivas

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4.

Mrs. Rivas

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5.

Mrs. Rivas

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6.

Mrs. Rivas

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7.

Mrs. Rivas

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𝒙+πŸ“=πŸ‘π’™+πŸ•8.

βˆ’πŸ 𝒙+πŸ“=πŸ•βˆ’πŸ 𝒙=𝟐

𝒙=βˆ’πŸ

Mrs. Rivas

Homework

𝒙+𝟐=πŸπ’™ β€“πŸ‘9.

βˆ’π’™+𝟐=β€“πŸ‘βˆ’π’™=β€“πŸ“π’™=πŸ“

Mrs. Rivas

Homework

πŸ“ 𝒙+πŸ•=𝒙+πŸ–10.

πŸ’ 𝒙+πŸ•=πŸ–πŸ’ 𝒙=𝟏

𝒙=πŸπŸ’

Mrs. Rivas

Homework

(5-4) In βˆ†ABC, X is the centroid.

11. If CW = 15, find CX and XW.

πŸπŸ“π‘ͺ𝑿=πŸπŸ‘π‘ͺ𝑾

π‘ͺ𝑿=πŸπŸ‘

(πŸπŸ“)

π‘ͺ𝑿=πŸ‘πŸŽπŸ‘

π‘ͺ𝑿=𝟏𝟎

𝑿𝑾=π‘ͺ𝑾 βˆ’π‘ͺ𝑿

𝑿𝑾=πŸπŸ“βˆ’πŸπŸŽπ‘Ώπ‘Ύ=πŸ“

Mrs. Rivas

Homework

(5-4) In βˆ†ABC, X is the centroid.

12. If BX = 8, find BY and XY.

πŸ–π‘©π‘Ώ=πŸπŸ‘π‘©π’€

πŸ–=πŸπŸ‘π‘©π’€

(πŸ‘πŸ )πŸ–=πŸπŸ‘π‘©π’€ (πŸ‘πŸ )

πŸπŸ’πŸ

=𝑩𝒀

𝟏𝟐=𝑩𝒀

𝟏𝟐

𝑿𝒀=𝑩𝒀 βˆ’π‘©π‘Ώπ‘Ώπ’€=πŸπŸβˆ’πŸ–π‘Ώπ‘Ύ=πŸ’

Mrs. Rivas

Homework

(5-4) In βˆ†ABC, X is the centroid.

13. If XZ = 3, find AX and AZ.

𝑿𝒁=πŸπŸ‘π‘¨π’

πŸ‘πŸ‘=

πŸπŸ‘π‘¨π’

(πŸ‘πŸ )πŸ‘=πŸπŸ‘π‘¨π’ (πŸ‘πŸ )

πŸ—=𝑨𝒁

πŸ—

𝑨𝑿=π‘¨π’βˆ’π‘Ώπ’π‘¨π‘Ώ=πŸ—βˆ’πŸ‘π‘¨π‘Ώ=πŸ”

Mrs. Rivas

Homework

Is a median, an altitude, or neither? Explain.

14. 15.

Median; bisects the opposite side.

Altitude; is perpendicular to the opposite side.

Mrs. Rivas

Homework

Is a median, an altitude, or neither? Explain.

16. 17.

Altitude; is perpendicular to the opposite side.

Neither; is not perpendicular to nor does it bisect the opposite side.

Mrs. Rivas

Homework

In Exercises 18–22, name each segment.

18. a median in βˆ†ABC

π‘ͺ𝑱

Mrs. Rivas

Homework

In Exercises 18–22, name each segment.

19. an altitude for βˆ†ABC

𝑨𝑯

Mrs. Rivas

Homework

In Exercises 18–22, name each segment.

20. a median in βˆ†AHC

𝑰𝑯

Mrs. Rivas

Homework

In Exercises 18–22, name each segment.

21. an altitude for βˆ†AHB

𝑨𝑯

Mrs. Rivas

Homework

In Exercises 18–22, name each segment.

22. an altitude for βˆ†AHG.

𝑨𝑯

Mrs. Rivas

Homework

23. A(0, 0), B(0, 2), C(3, 0). Find the orthocenter of ABC.

Mrs. Rivas

Homework

24. In which kind of triangle is the centroid at the same point as the orthocenter?

equilateral

Mrs. Rivas

Homework

π‘΄π’†π’…π’Šπ’‚π’ π‘ͺπ’†π’π’•π’“π’π’Šπ’…

𝑰𝒏𝒄𝒆𝒏𝒕𝒆𝒓 π‘ͺ𝒐𝒏𝒄𝒖𝒓𝒓𝒆𝒏𝒕 π’π’Šπ’π’†π’” π‘ͺπ’Šπ’“π’„π’–π’Žπ’„π’†π’π’•π’†π’“

π‘¨π’π’•π’Šπ’•π’–π’•π’† 𝑢𝒓𝒕𝒉𝒐𝒄𝒆𝒏𝒕𝒆𝒓 𝑽𝒆𝒓𝒕𝒆𝒙

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