mod 1 cat b1.1 & b2

EASA PART 66 CATEGORY B1.1/B2 MODULE 1 : MATHEMATICS

ARITHMETIC

1.1 ARITHMETIC

LEVEL 1

Question 1B1.1M01.1(1)L1

0.10102 + 3.1056 + 0.01013, give answer to three decimal places

A. 3.216B. 3.217C. 3.218Question 2B1.1M01.1(2)L1

Round off 53 857 to the nearest thousand.

A. 54 000B. 53 900C. 53 000 Question 3B1.1M01.1(3)L1

Given 12 : 7 = 60 : y. Find the value of y.

A. 35B. 103C. 1.5

Question 4B1.1M01.1(4)L1

An increase of 35% of 15 500 is

A. 5 425B. 11 625C. 20 925

Question 5BM01.1(5)L1Given the ratio of two lengths is 13:7; if the smaller length is 21 metres, the larger length is

A. 42 metresB. 36 metresC. 39 metres

LEVEL 2

Question 1B1.1M01.1(1)L2

A.

B.

C.

Question 2B1.1M01.1(2)L2

8((7(5 – 2) - 3) + 4 -5)

A. 143B. - 8C. 136 Question 3B1.1M01.1(3)L2

The temperature of an object is 200C. Convert this temperature to oF.

A. 2.22 degrees FB. 68 degrees FC. 93.6 degrees F

Question 4B1.1M01.1(4)L2

A road is 5.0 cm long in a map. Given that the road is drawn according to the scale of

1 : 50000. Find the actual length of the road, in m.

A. 25.0 mB. 250 mC. 2500 m

Question 5B1.1M01.1(5)L2

The average of 5, 10, 8, x, 14, 18, 25 is 13. Find the value of x.

A. 10B. 11C. 12

Question 6B1.1M01.1(6)L2

Figure 1

Figure 1 shows ABDE is a square and CGFD is a rectangle. Calculate the total area of the whole diagram.

A. 63 cm2

B. 81 cm2

C. 90 cm2

Question 7B1.1M01.1(7)L2

Figure 2

Figure 2 shows a solid cylinder with radius 3 m. If the volume of the cylinder is 72 cm3, calculate the value of y.

A. 20 cmB. 12 cmC. 8 cm

Question 8B1.1M01.1(8)L2

Given that y = . Find the value of y when r = 2, s = -6and t = 1/6.

A. 3B. 6C. 9

Question 9BM01.1(9)L2

The value of , expressed in scientific notation is

A.B.C.

Question 10BM01.1(10)L2

What is the total of a(b + c – d2) when a = 3, b = -4, c = 5 and d = -3?

A. -24B. -30C. 30

Question 11BM01.1(11)L2

If the pressure of one bar is approximately equal to 14.5psi(pounds per square inch), how many bars would be equivalent to 2175psi?

A. 125 barB. 250 barC. 150 bar

Question 12BM01.1(12)L2

=

A. 4031B. 4007C. 4001

ALGEBRA

1.2 (a) ALGEBRA

LEVEL 1

Question 1B1.1MO1.2(a)(1)L1

Express as a single fraction in its simplest form.

A.

B.

C.

Question 2B1.1MO1.2(a)(2)L1

Simplify in its simplest form.

A. 10 – 3a2b

B. 10 + 3a2b

C. 2 + 3a2b

Question 3B1.1MO1.2(a)(3)L1

Factorize the equation 2x2 + 16x + 24

A. (3x + 2)(x + 6)

B. 2(x + 2)(x + 6)

C. (2x + 3)(2x + 4)

LEVEL 2

Question 1B1.1MO1.2(a)(1)L2

Simplify the equation;

A.

B.

C.

Question 2BM01.2(a)(2)L2

The simplified expression of is

A. (ans)B.C.

Question 3BM01.2(a)(3)L2

Find R in the following expression

A. (ans)B.C.

Question 4BM01.2(a)(4)L2

What is the value of L in the formula , when R = 5, C = 0.0125 and Q = 2 ?

A. 2.25B. 1.25C. 0.15

Question 5BM01.2(a)(5)L2

is equal to

A. (ans)B.C.

Question 6

BM01.2(a)(6)L2

Simplify the following

A.

B.

C. (ans)

1.2 (b) ALGEBRALEVEL 1

Question 1B1.1MO1.2(b)(1)L1

Find the value of

A.

B.

C.

Question 2B1.1MO1.2(b)(2)L1Find the value of x for the equation ; 4 – 2(1 – x) = 3x + 2

A. 0

B. 2

C. 6

Question 3BM01.2(b)(3)L1

can be written as the binary number

A. 10110B. 101001C. 101010

Question 4BM01.2(b)(4)L1

The expression is equivalent to

A. 81B. 1

C.

Question 5BM01.2(b)(5)L1

The expression can be simplified to

A.

B.

C. 27

Question 6BM01.2(b)(6)L1

can be written as the binary number

A. 10110B. 101001C. 101010

Question 7BM01.2(b)(7)L1

Log 9 – log 3 + log 4 is equal to

A. log 12B. log 10C. log 16

Question 8BM01.2(b)(8)L1

If , then is

A. (ans)

B.

C. 3

LEVEL 2

Question 1B1.1MO1.2(b)(1)L2

Given that . Find u.

A.

B.

C.

Question 2B1.1MO1.2(b)(2)L2

Given that , find the value of x when y = 5.

A. 3B. 5C. 9

Question 3B1.1MO1.2(b)(3)L2Find the value of x for the given equation;

A. -3B. 3C. 9

Question 4B1.1MO1.2(b)(4)L2

Find the value of

A. 1B. 0C. 5

Question 5B1.1MO1.2(b)(5)L2

Solve the addition for 101012 + 110012 and give answer in decimal numbering system.

A. 46B. 48C. 62

Question 6B1.1MO1.2(b)(6)L2Express 2378 as a number in base two.

A. 10001101112

B. 111011012

C. 100111112

Question 7B1.1MO1.2(b)(7)L2Given that 5x + 2y = - 1 and 3x + 4y = 5. Find the value of x + y

A. 2B. -1C. 1

Question 8B1.1MO1.2(b)(8)L2Given log 4 = 0.6021, and log 6 = 0.7782. Evaluate log 144.

A. 1.3803B. 2.1585C. 1.9824

GEOMETRY

1.3 (a) GEOMETRYLEVEL 1

Question 1BM01.3(a)(1)L1

Each of the central angles of a regular pentagon is

A. 50 degreesB. 72 degreesC. 60 degrees

Question 2BM01.3(a)(2)L1

Which of the following information allows us to construct a triangle?

A. 2 sides givenB. 2 angles and an included sideC. 2 sides and an excluded angle

Question 3BM01.3(a)(3)L1

What does equilateral mean?

A. All of polygons sides are of equal lengthB. All of polygons angles are of equal sizeC. All of polygons sides and angles are equal

Question 4BM01.3(a)(4)L1

Each of the central angles of a regular octagon is

A. 45 degreesB. 72 degreesC. 60 degrees

Question 5BM01.3(a)(5)L1

What do we call a polygon with 6 equal sides?

A. PentagonB. HexagonC. Octagon

1.3 (b) GEOMETRY

LEVEL 1

B1.1MO1.3(b)()L1

Figure 3

Figure 3 shows the graph of a function. From the graph, find the equation that represents the line.

A. 2y = 5x + 20

B. 2y = -5x + 20

C. 2y = -5x - 20

LEVEL 2

Question 1B1.1MO1.3(b)(1)L2

A. B. C.

Figure 4

Which of the graphs in Figure 4, represents the function y = 9 – x2?

Question 2BM01.3(b)(2)L2

A straight line passes through the points (3,4) and (6,10). The equation of this line is

A.B.C. (ans)

Question 3BM01.3(b)(3)L2

The y intercept of 4y = 4x + 8 is

A. 8B. 4C. 2

Question 4BM01.3(b)(4)L2

What is the slope between the points (3,1) and (6,4) ?

A. 1B. 3

C.

Question 5BM01.3(b)(5)L2

What is the gradient, when the equation is 2y = 5x + 3?

A.

B.

C. (ans)

Question 6BM01.3(b)(6)L2

What is the equation of this line?

A. (ans)B.C.

y

x

1.3 (c) GEOMETRY

LEVEL 2

Question 1B1.1MO1.3(c)()L2

Figure 5

Figure 5 shows a triangle with LMN as a straight line. Find the value of cos

A. -4/5B. 4/5C. -3/5

Question 2B1.1MO1.3(c)()L2

Given that tan 560 = 1.483. Find the angle when tan 2 = 1.483 for 0° £ £ 360°

A. 280 , 620 , 2080, 2420

B. 560 , 2360 , 4160, 5960

C. 280 , 1180 , 2080, 2980

Question 3BM01.3(c)(3)L2

Given that sine = 0.8 and cosine = 0.2, the value of tan would be

A. 0.16B. 4C. 0.25