frequency planning part 1 - ti.com

Post on 18-Dec-2021

0 Views

Category:

Documents

0 Downloads

Preview:

Click to see full reader

TRANSCRIPT

Frequency planning part 1 TI Precision Labs – Clock and timing system design considerations

Presented by Rob Rodrigues

Prepared by Hao Zheng

1

Clock generator overview

2

.

.

....

PLL1

PLL2

D0

M

U

X

Reference

Input D1

D2

D3_4

Output 0

Output 1

Output 2

Output 3

Output 4

1/N

VCOLoopFilterPhase

Detector/Charge Pump

N Divider

KPD Z(s)

R Divider

1/D

Output DividerReference

Oscillator

1/N

1/R

VCOLoopFilterPhase

Detector/Charge Pump

N Divider

KPD Z(s)

25MHz 156.25MHz

Frequency calculation

3

R = 1

4.8 ~ 5.4 GHz

D = 31,

32,

33,

34

5000MHz

N = 200

Locked

25MHz

32,

156.25MHz

4800 / 156.25 = 30.72

5400 / 156.25 = 34.56

Frequency calculation (cont.)

4

R Divider

1/D

Output DividerReference

Oscillator

1/N

1/R

VCOLoopFilterPhase

Detector/Charge Pump

N Divider

KPD Z(s)

25MHz 156.25MHz

R = 1

25MHz

4.8 ~ 5.4 GHz

D = 31,

32,

33,

34 5156.25MHz

N + NUM/DEN = 206 + 1/4

Locked

33,

156.25MHz

One PLL, two output frequencies

5

N = 200

R DividerReference Oscillator

1/N

1/R

VCOLoopFilterPhase

Detector/Charge Pump

N Divider

KPD Z(s) 1/D0

1/D1

4.8 ~ 5.4 GHz

25 MHz R = 1

25MHz

2500MHz

5000MHz

7500MHz . . .

100MHz

156.25MHz

D0 = 50

D1 = 32

5000MHz

100MHz

156.25MHz

R DividerReference Oscillator

1/N

1/R

VCOLoopFilterPhase

Detector/Charge Pump

N Divider

KPD Z(s) 1/D0

1/D1

48MHz 48MHz

One PLL, two output frequencies (cont.)

6

2.4 ~ 2.8 GHz

24 MHz

32.768kHz

R = 1

N = 200

24MHz

2400MHz D0 = 50

D1 = 73242

2.56 ppm

0 ppm

D1 and D2

must be

divisible by 4,

5, or 6

32.768kHz

1/P

Prescaler/4, /5, /6

1/CH

Channel divider

To find more clocks and timing technical resources and search products, visit ti.com/clocks

7

Short Quiz

8

1. True or False:

The relationship between fVCO (VCO frequency), D (output divider value) and fout (output

frequency) is fout = fVCO * D

Short Quiz

9

1. True or False:

The relationship between fVCO (VCO frequency), D (output divider value) and fout (output

frequency) is fout = fVCO * D

Short Quiz

10

2. Choose one:

The relationship between fPD (phase detector frequency), N (N divider value), NUM (numerator of

fractional divider), DEN (denominator of fractional divider) and fVCO for fractional PLL is

(a) fVCO = fPD * (N - NUM/DEN) (b) fVCO = fPD * (N + NUM/DEN) (c) fVCO = fPD / (1/N + NUM/DEN)

Short Quiz

11

2. Choose one:

The relationship between fPD (phase detector frequency), N (N divider value), NUM (numerator of

fractional divider), DEN (denominator of fractional divider) and fVCO for fractional PLL is

(a) fVCO = fPD * (N - NUM/DEN) (b) fVCO = fPD * (N + NUM/DEN) (c) fVCO = fPD / (1/N + NUM/DEN)

Short Quiz

12

3. True or False:

There is only one combination of reference input frequency, phase detector frequency and divider

values that can generate the desired output frequency fout,

Short Quiz

13

3. True or False:

There is only one combination of reference input frequency, phase detector frequency and divider

values that can generate the desired output frequency fout,

Short Quiz

14

4. Choose all that apply:

Which constraints determine the relationship between fVCO, fout1 (frequency of output 1), fout2

(frequency of output 2) fVCO_min and fVCO_max for generating 0ppm outputs?

a) fVCO is common multiple of fout1 and fout2

b) fVCO/N = integer

c) fVCO_min < fVCO < fVCO_max

Short Quiz

15

4. Choose all that apply:

Which constraints determine the relationship between fVCO, fout1 (frequency of output 1), fout2

(frequency of output 2) fVCO_min and fVCO_max for generating 0ppm outputs?

a) fVCO is common multiple of fout1 and fout2

b) fVCO/N = integer

c) fVCO_min < fVCO < fVCO_max

TI Information – Selective Disclosure

top related