essenceneely& ist220& lab&3& 7june2015&...
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Essence Neely IST 220 Lab 3 7 June 2015 1. IP address: 130.01.020.151.88 TCP port number: 52834
2. IP address of gaia.cs.umass.edu: 128.119.245.12 Port number send/receiver tcp: http (80)
3. SEQ of the TCP SYN: 0 Identifies segment as a SYN: SYN flag 1
4. Sequence number of SYNACK: 0 The value of the ACKnowledgement: 1 Determine the value? By adding the SYN segment and the ACK segment, therefore getting 1. Identifies the segment as a SYNACK? When both flags are set to 1.
5. TCP Length: 330 ACK number: 331 The relationship between 331 and 330: The tcp length (330) plus the relative sequence number (1)
6. TCP Packet lengths of each 6 segments (client to server): 1380
7. IP Header length Packet Number Ack number Window size 11 3091 12800 16 5851 18688 21 8611 24448 26 11371 30336 31 14131 36224 36 16891 41984 37 19651 47872 46 22411 53632 51 25171 59520 52 27931 61440 61 30691 64128 62 34831 64128 73 38971 64128 80 41731 64128 85 47251 64128 94 54151 64128 104 62431 64128 115 70711 64128 124 78991 64128 131 85891 64128 137 92791 64128 141 95551 70016 142 98311 75776 143 101071 81664 144 103831 87552 145 106591 93312 146 109351 99200 147 112111 104960 148 114871 110848 149 117631 116736 150 120391 122496 151 125911 124288 152 128671 124288 153 134191 124288 154 136951 124288 155 142471 124288 156 145231 124288 157 149371 124288 158 152131 124288 Packet number Slowstart phase end: 1500-‐20 (header)-‐0(tcp)=1480 bytes TCP Collision Avoidance phase begin: increase at 1/53632(window size)
8. a)SEQ number: 331 b)Time sent: 9.249969
c)SEQ number: 152131 d)Time sent: 9.369988
9. Amount of data sent: (152131-‐331) = 151820 Amount of time: (9.369988*8)-‐ (9.249969 *8)= 0.97 10. Calculations with packet 1 and 160: Doing packet number 1 and 60 would not adequately represent when the text was received and finally got through.
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