ee2301: block a unit 31 block a unit 3 outline one port network > thevenin transformation >...
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EE2301: Block A Unit 3 1
Block A Unit 3 outline
One port network> Thevenin transformation
> Norton transformation
> Source transformation
Two port network> Hybrid (H) parameters
> Reciprocity theorem
One port networks: G. Rizzoni, “Fundamental of EE”, Chapter 3.6 – 3.7
EE2301: Block A Unit 3 2
One-Port Network
Represented as:
One-port Network
+
v–
A one port network is simply a two terminal device (that we can think of as a block or black box), which can be described by its I-V (current-voltage) characteristic.
EE2301: Block A Unit 3 3
Thevenin’s Theorem
Any one-port network composed of ideal voltage and current sources, and linear resistors, can be represented by an equivalent circuit consisting of an ideal voltage source VT in series with an equivalent resistance RT
One-port network
+-VT
RT
This is an extremely power method is you want to find the load condition for maximum power transfer.
i.e. what is the RL you need to achieve maximum power transfer for a given one port network?
EE2301: Block A Unit 3 4
Norton’s Theorem
Any one-port network composed of ideal voltage and current sources, and linear resistors, can be represented by an equivalent circuit consisting of an ideal current source IN in parallel with an equivalent resistance RN
One-port network IN RN
This is an extremely power method is you want to find the load condition for maximum power transfer.
i.e. what is the RL you need to achieve maximum power transfer for a given one port network?
EE2301: Block A Unit 3 5
Finding RN or RT
Method Summary Remove the load (assumption: you need to know what the
load is). Never forget this step! Zero all independent voltage & current sources
> Short-circuit voltage sources (0V across source)
> Open-circuit current sources (0A through source) Calculate the total resistance seen across the load terminals
to obtain equivalent resistance RN or RT
> Combine resistors in series and parallel (REF previous unit)
Applies to both Thevenin & Norton
EE2301: Block A Unit 3 6
Zeroing the Sources
That is as if the source never existed
Vs
+
-
IN
Voltage Source
Current Source
No voltage
=> Short
No current
=> Open
EE2301: Block A Unit 3 7
Illustration of finding RN or RT
R1
R2
R3
RL+
-vs
Step 1: Remove load
R2+
-vs
R2
R1 R3
Step 2: Zero all independent sources
R1 R3
Step 3
Compute total resistance between the terminals
Thevenin Resistance: RT = R3 + R1||R2
EE2301: Block A Unit 3 8
Equivalent R: Example 1
+-VS
R1
R2
+-VS R1
R2
RthR1 R2RthR2
Rth = R1 || R2 Rth = R2
EE2301: Block A Unit 3 9
Equivalent R: Example 2
IS
R1
R2 IS R1
R2
RthR2 R1Rth
Rth = R2 Rth = R1 + R2
EE2301: Block A Unit 3 10
Finding Thevenin voltage VT
Method Summary Remove load (never forget this step) Define open circuit voltage Voc across the
open load terminals Solve for Voc using any preferred method to
obtain the Thevenin voltage VT = Voc
Definition of VT - The Thevenin equivalent voltage is equal to the open-circuit voltage present at the load terminals (with the load removed)
EE2301: Block A Unit 3 11
Finding Thevenin VT
R1
R2
R3
RL+
-vs
Step 1: Remove load!
R2+
-vs
R1 R3+
Voc
-
Step 2: Define open circuit voltage Voc across the open load terminalsStep 3: Solve for Voc using any preferred method
Note that current through R3 = 0 due to open circuit (ie no voltage drop across R3)
Therefore voc = voltage across R2
Voltage divider rule: voc = [R2 / (R1 + R2)] vs
*Thevenin voltage vT = voc
EE2301: Block A Unit 3 12
Thevenin example 1
Problem 3.55
Find the Thevenin equivalent circuit as seen by the resistor RL
EE2301: Block A Unit 3 13
Thevenin example 1 solution
This slide is meant to blank
1kΩ 1kΩ
1Ω 3Ω
Rth = 504Ω
Note that with RL removed, no current runs through 3Ω resistor
Mesh 1:
10 = 2000i1 - (1000)(0.01)
i1 = 10mA
Mesh 2:
-V = (1001)(0.01) - (1000)(0.01)
V = -10mV
Vth = V = -10V
+ -
504Ω
-10mV
EE2301: Block A Unit 3 14
Thevenin example 2
Problem 3.52
Find the voltage across the 3Ω resistor by replacing the remainder with the its Thevenin equivalent
-
V1
+
EE2301: Block A Unit 3 15
Thevenin example 2 solution
This slide is meant to blank
Equivalent resistance seen by 3Ω resistor is simply 4Ω resistor
Mesh 1:
V1 = 2(4+2) - i (2)
2i + V1 = 12
Mesh 2:
3 = i(2+2) - 2 (2)
i = 1.75A
V1 = 8.5V
Vth = (1.5)(2) - 8.5 = -5V
+ -
4Ω
-5V
V3Ω = 3/(3+4) * -5 = -5.14V
EE2301: Block A Unit 3 16
Finding Norton current IN
Method Summary Replace load with short circuit (SC) Define SC current isc to be Norton equivalent
current Solve for isc using any preferred method to
obtain IN = isc
Definition of IN - The Norton equivalent current is equal to the short-circuit current that would flow if the load were replaced by a short circuit
EE2301: Block A Unit 3 17
Finding Norton IN (1)
R1
R2
R3
RL+
-vs
Step 1: Short circuit load
R2+
-vs
R1 R3
Step 2: Define short circuit current isc
Step 3: Solve for isc using any preferred method
isc
sa
aaas
vRRRRRR
RRv
R
v
R
v
R
vv
133221
32
321
0
Apply KCL at node A:
3R
vi asc
A
EE2301: Block A Unit 3 18
Norton example 1
Problem 3.51 (modified)
Find the Norton equivalent circuit to the left of the 3Ω resistor
EE2301: Block A Unit 3 19
Norton example 1 solution
This slide is meant to blank
5Ω 4Ω
1Ω
RN = 3.22Ω
Norton current is given by the current through 1Ω resistor
V966.436
54||1
4||11
RV
A966.4111 RVII RRN
EE2301: Block A Unit 3 20
Norton example 2
Problem 3.53
Find the Norton equivalent circuit to the left of the 2Ω resistor
EE2301: Block A Unit 3 21
Norton example 2 solution
This slide is meant to blank
KCL at node 1:
637
1312
21
2111
VV
VVVV
KCL at node 2:
643
321
21
221
VV
VVV
Solve for V2: V2 = -1.263V
IN = V2 / 3 = -0.42A
1Ω 3Ω
1Ω 3Ω
Rth = 4.75Ω
EE2301: Block A Unit 3 22
Source Transformation
+
-
RT
RTVT IN
We can transform between the two equivalent circuits, observing each time that:
VT = IN RT
For example using one of the previous circuits as shown below:
R2+
-
R1 R3
VS
R2R1
R3
I1
VS and R1 form a Thevenin circuit which we can transform to a Norton circuit defined by current source I1 = VS/R1 and parallel resistance R1. Note that R1 and R2 and be combined.
EE2301: Block A Unit 3 23
Transformation illustration
R1||R2
R3
I1
+
-
R3
V1
The parallel combination of R1 & R2 (R1||R2) and current source I1 form a new Norton circuit (with a different value of parallel resistance than in the first instance), which can in turn be transformed back into a Thevenin circuit as follows. This Thevenin circuit comprises of a series resistor R1||R2, and a voltage source of V1 = I1(R1||R2).
R1||R2
Finally, it will now become obvious that this Thevenin resistor is in series with R3, and therefore can be easily combined. Therefore, in summary we see thatVT = V1 = [R2/(R1+R2)]VS and RT = R1||R2 + R3 (same result as before)
Note that V1 is NOT the same as VS. Hence the transformed circuit values are not to be confused with the original values – never make this mistake!
Source Transformation: Proof
EE2301: Block A Unit 3 24
Comes directly from the theorem:Thevenin to Norton – Any network can be composed of a current source in parallel with a resistor; this would therefore also include a Thevenin circuitNorton to Thevenin – Any network can be composed of a voltage source in series with a resistor; this would therefore also include a Norton circuit
Two-port network
EE2301: Block A Unit 3 25
Looking back
A port refers to a pair of terminals through which a current may enter or leave a network
We have focused only on one-port networks so far, where we consider the voltage across or current through a single pair of terminal
The rest of this unit deals with two-port networks
A two-port network is an electrical network with two separate ports for input and output
We will see examples of two-port networks (op amps and transistor circuits) later on in this course
Like for a one-port network, knowing the parameters of a two-port network enables use to treat it as a “black-box” placed within a larger network.
In a two-port network, we need to relate V1, V2, I1, I2
The terms relating these currents and voltages are known as parameters
Impedance parameters
EE2301: Block A Unit 3 26
As shown in the figure, a two-port network may be voltage-driven or current-driven.
The terminal voltages and currents represent 4 variables, of which two are independent.
The terminal voltages can be related to the terminal currents
V1 = z11I1 + z12I2
V2 = z21I1 + z22I2
These z terms are known as impedance parameters (since there are defined by V over I), or simply z parameters.
2
1
2221
1211
2
1
I
I
zz
Zz
V
V
It can also be expressed in matrix form:
The voltages V1 and V2 are the dependent variables in this case
Handling parameter subscripts
EE2301: Block A Unit 3 27
11: Input from port 1 and output back to port 1
21: Input from port 1 and output to port 2
12: Input from port 2 and output to port 1
22: Input from port 2 and output back to port 2
z parameters
EE2301: Block A Unit 3 28
The values of the parameters can be obtained by setting:
I1 = 0 (input port open-circuited) or
I2 = 0 (output port open-circuited)
Therefore:
0I2
222
0I1
221
0I2
112
0I1
111
12
12
I
Vz,
I
Vz
I
Vz,
I
Vz
z11: Open-circuit input impedance
z12: Open-circuit transfer impedance from port 1 to port 2
z21: Open-circuit transfer impedance from port 2 to port 1
z22: Open-circuit output impedance
Deriving z parameters
EE2301: Block A Unit 3 29
We can see from the definition of the z parameters, we obtain z11 and z21 by connecting V1 to port 1 and leaving port 2 open-circuited (I2 = 0)
[Referring to Figure (a)]:
z11 = V1/I1, z21 = V2/I1
Likewise, we obtain z12 and z22 by connecting V2 to port 2 and leaving port 1 open-circuited (I1 = 0)
[Referring to Figure (b)]:
z12 = V1/I2, z22 = V2/I2
z11 and z22 are known as driving-point impedances
z21 and z12 are known as transfer impedances
Z parameter example 1
EE2301: Block A Unit 3 30
Determine the Z-parameters for the following circuit
We first apply V1 at port 1 and open-circuit port 2 (I2 = 0) [Figure (a)]
z11 = V1/I1 = (20 + 40)I1/I1 = 60Ω
z21 = V2/I1 = 40I1/I1 = 40Ω
Next we apply V2 at port 2 and open-circuit port 1 (I1 = 0) [Figure (a)]
z12 = V1/I2 = 40I2/I2 = 40Ω
z22 = V2/I1 = (40 + 30)I2/I2 = 70Ω
Z parameter example 2
EE2301: Block A Unit 3 31
Determine the Z-parameters for the following circuit
z11 = 14, z12 = z21 = z22 = 6Ω
Hybrid parameters
EE2301: Block A Unit 3 32
The z parameters do not exist for all two-port networks, so there is a need to develop an alternative set of parameters to describe such types of two-port networks. This particular set of parameters is based on making V1 and I2 the dependent variables.
V1 = h11I1 + h12V2
I2 = h21I1 + h22V2
These h terms are known as hybrid parameters, since there are a hybrid (mix) of ratios, or simply h parameters.
This set of parameters is very useful for describing electronic devices such as transistors (which we will cover in Block C); namely because they are easier to measure compared to z or y parameters.
0I2
222
0V1
221
0I2
112
0V1
111
12
12
V
Ih,
I
Ih
V
Vh,
I
Vh
The h parameters are defined as:
h parameters
EE2301: Block A Unit 3 33
We can see that:
h11 represents an impedance; h12 represents a voltage ratio
h21 represents a current ratio; h22 represents an admittance
This is why they are known as hybrid (which means a mixture) parameters
h11: Short-circuit input impedance
h12: Open-circuit reverse voltage gain
h21: Open-circuit forward current gain
h22: Short-circuit output admittance
To find h11 and h21:
Short-circuit port 2 and apply I1 to port 1
To find h22 and h12:
Open-circuit port 1 and apply I2 to port 2
h parameter example 1
EE2301: Block A Unit 3 34
Find the h parameters for the following circuit.
To find h11 and h21:
Short-circuit port 2 and apply I1 to port 1 [Fig (a)]
h11 = V1/I1 = (2 + 3||6)I1/I1 = 4Ω
h21 = I2/I1 = -2/3 (current divider)
To find h12 and h22:
Open-circuit port 1 and apply V2 to port 2 [Fig (b)]
h12 = V1/V2 = 6/(6+3) = 2/3 (voltage divider)
h22 = I2/V2 = I2/(3+6)I2 = 1/9S
h parameter example 2
EE2301: Block A Unit 3 35
Find the h parameters for the following circuit.
h11 = 1.2Ω, h12 = 0.4, h21, = -0.4, h22 = 0.4S
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