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Psychology Online Video Classes
https://vyomadaily.in/product/psychology-online-video-classes/
PROGRESSIONS
Write a progression for the data?
10th ClassSpecial
K. KumarSr. Faculty
Hyderabad94929 56214
7�� 6, 2019 - ntadilabad.comntnews.com
@Venkey99
Model-I1. (a) Tomato (b) Cabbage
(c) Calliflower (d) Brinjal(e) cucumber
2. (a) Foot (b) finger(c) Tongue (d) Eye(e) Ear
3. (a) Wall (b) sand(c) stone (d) Cement(e) lime
4. (a) Lizard (b) cobra(c) snake (d) Earthworm(e) Fox
5. (a) vollyball (b) Hockey(c) Football (d) cricket(e) Polo
6. (a) Bird (b) mynah(c) Duck (d) crow(e) Parrot
7. (a) Jujube (b) Turnip(c) Banana (d) Pomegranate(e) mango
8. (a) sanders (b) champa(c) Rose (d) marigold(e) Jasmine
9. (a) Television (b) Drama(c) Cinema (d) play(e)Radio
10. (a) Polite (b) Gentle(c) Religious (d) Humble(e) good
11. (a) cow (b) pomther(c) ox (d) crocodile (e) lion
12. (a) oil (b) chimney(c) Wick (d) Flame(e) Lamp
13. (a) Earth (b) cloud(c) Horizon (d) sun(e) Moon
14. (a) Bull (b) Horse(c) Goat (d) Buffalo(e) cow
15. (a) Brown (b) paint(c) white (d) yellow(e) Black
16. (a) petticoat (b) saree(c) Turban (d) Blouse
17. (a) Wolf (b) Elephant(c) Deer (d) wild(e) wild Buffalo
18. (a) Quarter (b) Garage(c) Apartment (d) Flat
19. (a) Lorry (b) Truck(c) Tractor (d) Ski
20. (a) Direction (b) Advice(c) consultation (d) suggestion
21. (a) Tractor (b) khurpa(c) Farmer (d) spade(e) plough
22. (a) Root (b) stem(c) plant (d) mango(e) Tree
23. (a) piano (b) Guitar(c) Harmonium (d) musician(e) Flute
24. (a) pedlar (b) Trader(c) Tailor (d) seller
25. (a) Banana (b) Barfi(c) Rubber (d) Juice
26. (a) silk (b) cloth(c) cotton (d) Jute
27. (a) spine (b)Navel(c) Eye (d) Elbow
28. (a) kathak (b) kathakali(c) karnatic (d) manipuri
29. (a) swarm (b) Flock(c) union (d) Team
30. (a) walk (b) Run(c) Listen (d) slip
31. (a) Hill (b) valley(c) Dam (d) River (e) Mountain
32. (a) clutch (b) Wheel(c) Break (d) car(e) Gear
33. (a) copper (b) silver(c) Gold (d) Diamond(e) platinum
34. (a) sesame (b) mustard(c) potato (d) coconut (e) ground nut
35. (a) coal (b) Aluminium(c) plastic (d) Iron(e) Wood
36. (a) pistol (b) sward(c) Gun (d) Rifle(e) cannon
37. (a) poland (b) Turkey(c) spain (d) sweden
38. (a) carrot (b) potato(c) Tomato (d) Ginger(e) Beetroot
39. (a) charmeleon (b) crocodile (c) Alligator(d) Locust (e) salamander
40. (a) Tiger (b) Leopard (c) Elephant (d) Dog(e) cat
41. (a) Editor (b) Doctor(c) Author (d) proof-reader (e) Translater
42. (a) cube (b) Rhombus
(c) Trapezium (d) square(e) parallelogram
43. (a) clock (b) speedometer (c) Thermometer (d) Galvano meter (e) compass- needle
44. (a) Elegy (b) Epic(c) Fable (d) Ballad(e) Ode
45. (a) Fist (b) Gums(c) Arm (d) Lung(e) Tears
46. (a) Hockey (b) polo(c) Tennis (d) cricket(e) Golf
47. (a) Apple (b) orange(c) papaya (d) Water-melon (e) Mango
48. (a) Vit-A (b) Vit-B(c) Vit-C (d) Vit-D(e) Vit-K
49. (a) Aryabhatta (b) Apple(c) Rohini (d) Apollo-soyuz (e) Bhaskara
50. (a) Ere (b) Eve(c) Ewe (d) Eke(e) Ese
51. (a) January (b) march(c) June (d) october(e) september
52. (a) Apple (b) Banana(c) peach (d) Fig(e) Turnip
53. (a) Trousers (b) spectacles(c) scissors (d) scales(e) pilers
54. (a) Watch man (b) Retailer(c) Boatsman (d) Physician(e) Abattoir
55. (a) Rice (b) Wheat(c) Barley (d) mustard(e) Bajra
56. (a) tortoise (b) Frog(c) Rat (d) mangoose(e) snake
57. (a) Listen (b) Feel(c) think (d) sing(e) Hear
58. (a) Three (b) Four(c) Five (d) Six(e) nine
59. (a) pencil (b) sharpener(c) Black Board (d) Chalk(e) pen
60. (a) cheese (b) Butter
(c) milk (d) curd(e) Ghee
61. (a) Now (b) After(c) Then (d) Before(e) Again
62. (a) Ammonia (b) Urea(c) potash (d) Nitrogen(e) manure
63. (a) Jupiter (b) mars(c) Earth (d) Uranium(e) pitcher
64. (a) Bucket (b) Tap(c) Bottle (d) Glass(e) pitcher
65. (a) Rose (b) Jasmine(c) Hibiscus (d) marigold(e) Lotus
Model -II
� In each of the following questions threeof the given four pairs are alike in acertain way and so form a group. Findthe odd one out.
66. (a) criminal and prison (b) Bird and Nest (c) student and Teacher(d) Fish and River
67. (a) cow and calf (b) sheep and Lamb (c) ox and Buffalo (d) Bitch and puppy
68. (a) Ear- Nose (b) Head- Hair (c) mouth- Teeth (d) Face-mouth
69. (a) Disease-Death (b) pleasure-Delight (c) Distress-War (d) peace-pleasure
70. (a) Lion and Roar (b) Tambourine and pat (c) Bird and Trumpet (d) ASS and Bray
ANSWERS 1-a 2-c 3-a 4-e 5-e 6-c7-b 8-a 9-e 10-c 11-d 12-d 13-b 14-e 15-b 16-c 17-c 18-b 19-d 20-a 21-c 22-d 23-d 24-c 25-c 26-b 27-a 28-c 29-d 30-c31-c 32-d 33-a 34-c 35-c 36-b 37-e 38-c 39-d 40-c 41-b 42-a 43-c 44-c 45-e 46-e 47-e 48-e49-d 50-e 51-a 52-e 53-d 54-e 55-d 56-e 57-d 58-d 59-b 60-c61-e 62-e 63-d 64-b 65-e 66-c67-c 68-a 69-c 70-c
G. RamakrishnaReasoning faculty
Hyderabad9247345095
Classification or
Odd man out
Find the odd one out?
For AllCompetitive
Exams
10 �� 6, 2019 - ntadilabad.comntnews.com
@Venkey99
@Venkey99
@Venkey99
Ð]l*¨Ç {ç³Ô¶æ²Ë$
1.
ÑË$Ð]lMýS$ çÜÐ]l* ]lOÐðl$…¨?
1) 2)
3) 4)
2. ÑË$Ð]l? 1) 21 2) 233) 25 4) 27
3. MìS…¨ Ðé°ÌZ Oò³£éVøÇĶæ$ Œl {†MýS… M>°¨?1) 3, 4, 52) 6, 8, 103) 8, 15, 174) 10, 24, 25
4. AƇ$$™ól 2x − 7 ÑË$Ð]l?
1) 2)
3) 0 4)
5. VýS$×æM>Æý‡ ÑÌZÐ]l*ÌS ÌSºª…?
1) 2)
3) 4)
6. ™èl$ÚëÆŠæ 250 Ñ$.Î. ´ëË$ MýSÍW ]l V>ÏçÜ$ÌZ2/5Ð]l ¿êVýS… ™éW™ól, V>ÏçÜ$ÌZ Ñ$WÍ ]l´ëË$ (Ñ$.Î.ÌSÌZ)?1) 50 2) 1003) 150 4) 200
7. 0.238MýS$ çÜÐ]l* ]lOÐðl$ ]l À¯]l²…?
1) 2)
3) 4)
8. {ç³Ò$ÌS B§éĶæ$…, ´÷§ýl$ç³# (savings)ÌS°çÙµ†¢ 4:1 AƇ$$ ]l BÐðl$ ´÷§ýl$ç³#(savings) Ô>™èl…ÌZ?1) 20% 2) 25%3) 40% 4) 80%
9. DÔèæÓÆŠæ Æý‡*. 5000 Ððl¬™é¢°MìS 4ççÜ…Ð]l™èlÞÆ>ËMýS$V> ]l$ Æý‡*. 2500Ë$ Ð]lyîlzðlÍÏ…^éyýl$. AƇ$$¯]l ðlÍÏ…_ ]l Ð]lyîlzÆó‡r$(çÜ…Ð]l™èlÞÆ>°MìS)?1) 10% 2) 12.5%3) 20% 4) 25%
10. 5 Ð]l$…¨ Ð]lÅMýS$¢Ë$ MýSÍíÜ JMýS ç³°° 10ÆøkÌSÌZ ç³NÇ¢ ólíÜ ]l JMóS Ð]lÅMìS¢ B ç³°°G°² ÆøkÌZÏ ç³NÇ¢ ólÝë¢yýl$?1) 2 2) 103) 20 4) 50
11. ABCD èl™èl$Æý‡$Âf…ÌZ° Mø×êÌS °çÙµ†¢Ð]lÆý‡$çÜV> 3 : 7 : 6 : 4 AƇ$$ ]l ABCDJMýS___
1) V>Íç³r…2) çÜÐ]l*…™èlÆý‡ ^èl™èl$Æý‡$Âf…3) çÜÐ]l$ èl™èl$Æý‡$Âf…4) çÜÐ]l$ÌS…º èl™èl$Æý‡$Âf…
12. çÜç³¢¿¶æ$hÌZ VýSË MýSÆ>~ÌS çÜ…QÅ?1) 42 2) 213) 14 4) 7
13. Ayýl$z, °Ë$Ð]l# ÝûçÙxÐ]l Æó‡QÌS ]l$ MýSÍW ]l B…VýSÏA„ýSÆý‡…?1) X 2) E3) M 4) K
14. Æð‡…yýl$ ç³NÆý‡MýS Mø×êÌS ¿ôæ§ýl… 30° AƇ¬™ólB Mø×êË$?1) 20°, 50° 2) 30°, 60°3) 40°, 70° 4) 75°, 105°
15. ©Æý‡ƒ èl™èl$Æý‡{çÜ… ´÷yýlÐ]l# 12 òÜ….Ò$., MýSÆý‡~…15 òÜ….Ò$. AƇ¬™ól §é° èl$r$tMöÌS™èl?1) 27 cm 2) 42 cm3) 54 cm 4) 108 cm
16. ©Æý‡ƒ èl™èl$Æý‡{çÜ…, ^èl™èl$Æý‡{çÜ… ^èl$r$tMöÌS™èlË$çÜÐ]l* ]l…. ©Æý‡ƒ èl™èl$Æý‡{çÜ… ´÷yýlÐ]l#,ÐðlyýlË$µË$ Ð]lÆý‡$çÜV> 35 òÜ….Ò$, 25òÜ….Ò$. AƇ¬™ól Ðésìæ OÐðlÔ>ÌêÅÌS ¿ôæ§ýl…?1) 10 cm2 2) 25 cm2
3) 35 cm2 4) 60 cm2
17. JMýS çÜÐ]l$ èl™èl$Æý‡$Âf… ÐðlÔ>ÌSÅ… 216 èl.òÜ….Ò$., §é° MýSÆ>~ÌSÌZ JMýSsìæ 24 òÜ….Ò$.AƇ¬™ól Æð‡…yø MýSÆý‡~… òÜ….Ò$.ÌSÌZ?1) 9 2) 123) 18 4) 36
18. 40, 50, 99, 68, 98, 60, 94ÌS Ð]l$«§ýlÅVýS™èl…?1) 99 2) 683) 60 4) 40
19. §ýl™é¢…Ôèæ…ÌZ VýSÇçÙt, MýS°çÙt ÑË$Ð]lÌS ¿ôæ§ýl…?1) ´û ]l@ç³# ]lÅ… 2) ™èlÆý‡VýS† A…™èlÆý‡…3) ÐéÅí³¢ 4) »êçßæ$âýæMýS…
20. Ð]lÊyýl$ ÑÀ ]l² çÜçßæf çÜ…QÅÌS çÜVýSr$ 40.ÐésìæÌZ _ ]l²çÜ…QÅ 19 AƇ¬™ól Ñ$WÍ ]lÆð‡…yýl$ çÜ…QÅÌSÌZ Ý뫧ýlÅÐ]l$Äôæ$Å Ñ$MìSPÍò³§ýlª çÜ…QÅ?1) 40 2) 713) 81 4) 91
119500
119250
238500
238100
98125
12598
52
25
25 5,
14 7
1319
1319−19
13
5 24 ,
3 5x x− =
604 441+
02 53 7
×
32 53 7
×
62 53 7
×
92 53 7
×
3 32 53 7
×
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IBPS Clerks - General English
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f¯]lÆý‡ÌŒæ çÜtyîl‹Üf¯]lÆý‡ÌŒæ çÜtyîl‹Üf¯]lÆý‡ÌŒæ çÜtyîl‹Üf¯]lÆý‡ÌŒæ çÜtyîl‹Üf¯]lÆý‡ÌŒæ çÜtyîl‹ÜBÆŠæBÆŠæ½BÆŠæBÆŠæ½BÆŠæBÆŠæ½BÆŠæBÆŠæ½BÆŠæBÆŠæ½
sñæsŒæ/ yîlGïÜÞsñæsŒæ/ yîlGïÜÞsñæsŒæ/ yîlGïÜÞsñæsŒæ/ yîlGïÜÞsñæsŒæ/ yîlGïÜÞsñæsŒæ/ yîlGïÜÞÐ]l*Å£ýlÐðl$sìæMŠæÞÐ]l*Å£ýlÐðl$sìæMŠæÞÐ]l*Å£ýlÐðl$sìæMŠæÞÐ]l*Å£ýlÐðl$sìæMŠæÞÐ]l*Å£ýlÐðl$sìæMŠæÞ
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sñæsŒæ/ yîlGïÜÞ
çÜÐ]l*«§é¯éË$
1. 3;
= am × bm = (ab)m
2. 3;
3. 4; 32 + 42 = 52
62 + 82 = 102
82 + 152 = 172
102 + 242 ≠ 252
∴10, 24, 25 Oò³£éVøÇĶæ$ Œæ {†MýS… M>§ýl$
4. 2;
19x = 60
2x −7 ÑË$Ð]l
5. 2;
VýS$×êM>Æý‡ ÑÌZÐ]l$…=
6. 3; V>ÏçÜ$ÌZ ´ëË$ = 250 Ñ$.Î.™èl$ÚëÆŠæ ™éW ]l ´ëË$
= 250 × =100 Ñ$.Î.
Ñ$WÍ ]l ´ëË$ = 250 − 100 = 150 Ñ$.Î.
7. 4; 0.238
8. 2; {ç³Ò$Ë B§éĶæ$…, ´÷§ýl$ç³#Ë °çÙµ†¢ = 4 : 1
´÷§ýl$ç³# Ô>™èl…
9. 2;P = 5000t = 4 çÜ…Ð]l™èlÞÆ>Ë$I = 2500
10. 4; M1D1 = M2D2M1 = 5 M2 = 1D1 = 10 D2 = ?
11. 4, èl™èl$Æý‡$Âf Mø×êË °çÙµ™èl$¢Ë Ððl¬™èl¢…
= 3 + 7 + 6 + 4 = 20Mø×êË Ððl¬™èl¢… = 360°
Ððl¬§ýlsìæ Mø×æ…
∠Α = 54°
Æð‡…yø Mø×æ…
∠Β = 126°
Ð]lÊyø Mø×æ…
∠C = 108°
¯éË$Vø Mø×æ…
∠D = 72°
Oò³ ç³r… B«§éÆý‡…V> BC || AD A§ólÑ«§ýl…V>∠Α + ∠Β = 126° + 54° = 180°∠ΑDC = 180° − ∠BCD = 180° −108° = 72°A§ól Ñ«§ýl…V>∠A + ∠B = 126° + 54° = 180°∠C + ∠D = 108 ° + 72° = 180°ABCD çÜÐ]l$ÌS…º ^èl™èl$Æý‡$Âf…({sñæï³hĶæ$…) AÐ]l#™èl$…¨
12. 3;çÜç³¢¿¶æ$hÌZ ¿¶æ$gêË çÜ…QÅ = 7MýSÆ>~Ë çÜ…QÅ
13. 1; Ayýl$z, °Ë$Ð]l# ÝûçÙtÐ]l Æó‡QË$ MýSÍW ]l A„ýSÆý‡…X
14. 2;Æð‡…yýl$ ç³NÆý‡MýS Mø×êË ¿ôæ§ýl… = 30°ç³NÆý‡MýS Mø×êË Ððl¬™èl¢… = 90°ç³NÆý‡MýS Mø×êË$ = x, y A¯]l$Mö…sôæx + y = 90°x − y = 30°Æð‡…yìl…sìæ° Ý뫨… èlV>x = 60°y = 30°
15. 2;©Æý‡ƒ èl™èl$Æý‡{çÜ… ´÷yýlÐ]l# = 12 òÜ….Ò$.MýSÆý‡~… = 15 òÜ….Ò$.
ÐðlyýlË$µ
èl$r$t MöË™èl = 2(´÷. + Ððl.)= 2(12 + 9)= 42 òÜ….Ò$.
16. 2; ©Æý‡ƒ èl™èl$Æý‡{çÜ… èl$r$tMöË™èl = 2(´÷ +Ððl)èl™èl$Æý‡{çÜ… èl$r$t MöË™èl = 4 × ¿¶æ$f…©Æý‡ƒ èl™èl$Æý‡{çÜ… ´÷yýlÐ]l#, ÐðlyýlË$µ
= 35 òÜ….Ò$, 25 òÜ….Ò$.©. èl. èl$r$t MöË™èl
= 2(35 + 25) = 120 òÜ….Ò$.èl™èl$Æý‡{çÜ… èl$r$t MöË™èl 4 × ¿¶æ$f…
= 120òÜ….Ò$¿¶æ$f… = 30 òÜ….Ò$.èl™èl$Æý‡{çÜ OÐðlÔ>ËÅ…
= (30)2
= 900 ^èl.òÜ….Ò$.©. èl. OÐðlÔ>ËÅ… = 35 × 25= 875 ^èl.òÜ….Ò$.
Ðésìæ OÐðlÔ>ÌêÅË ¿ôæ§ýl… = 900 òÜ….Ò$.2 − 875 òÜ….Ò$.2= 25 òÜ….Ò$.2
17. 3; çÜÐ]l$ ^èl™èl$Æý‡$Âf… OÐðlÔ>ËÅ…= 216 ^èl.òÜ….Ò$.½d1d2 = 216d1d2 = 432d1 = 24
òÜ….Ò$.
18. 2; 40, 50, 99, 68, 98, 60, 94ËÐ]l$«§ýlÅVýS™èl…40, 50, 99, 68, 98, 60, 94˯]l$BÆøçßæ×æ {MýSÐ]l$…ÌZ Æ>õÜ¢40, 50, 60, 68, 94, 98, 99Æ>Ô¶æ$Ë çÜ…QÅ = 7
Ð]l$«§ýlÅVýS™èl…
Ð]l Æ>Õ
∴ Ð]l$«§ýlÅVýS™èl… = 6819. 3;
ÐéÅí³¢ = VýSÇçÙt ÑË$Ð]l − MýS°çÙt ÑË$Ð]l20. 3;
Ð]lÊyýl$ ÑÀ ]l² çÜçßæf çÜ…QÅË$ x1, x2, x3
x1 + x2 + x3 = 120x1 = 19x2 + x3= 120 − 19 = 101 Bç³Û ŒæÞ B«§éÆý‡…V> ò³§ýlª çÜ…QÅV> 91¡çÜ$MýS$…sôæ _ ]l²çÜ…QÅ 120&19&91 = 10AÐ]l#™èl$…¨. M>± §ýl™é¢…Ô¶æ… {ç³M>Æý‡…_ ]l²çÜ…QÅ 19 E…yéÍ. M>ºsìæt M>ÐéÍÞ ]lçÜ…QÅ 81.
1 2 3
340
x x x+=
+ =
7 1 84
2 2+= = =
n 12+=
2
432d 18
24= =
225 144 81 9= − = =
2 215 12= −
n(n 3) 7(7 3) 7 414
2 2 2− − ×= = = =
4360 72
20= × ° = °
6360 108
20= × ° = °
7360 126
20= × ° = °
3360 54
20= × = °
25 10
D 501
×= =
100 250012.5%
5000 4×= =
×
100Ir
Pt=
1100 25%
4= × =
238 1191000 500
= =
25
25 7 514 5 2
× =
75
57
1319−=
60 120 120 1332 7 7
19 19 19− − = − =
6019
x =
194
15x =
25 64
15x x− =
5 24
3 5x x− =
441 21
604 21 625 25
=
+ = =
32 53 7
= ×
3 32 53 7
×
108°72°
D C
A
B54° 126°
15
cm
12 cm
@Venkey99
MODEL QUESTIONS
Directions (Q. 1-05): Read eachsentence to find out whether there isany grammatical mistake/ error init. The error, if any, will be in onepart of the sentence. Mark thenumber of that part with error asyour answer. If there is 'No error',mark (5) as your answer.1. The prestigious Nobel Peace
Prize for 2019 will be awarded toPrime Minister Abiy Ahmed Aliof Ethiopia, (1)/ he was selectedfor his efforts to achieve peaceand international cooperation,(2)/ and in particular for hisdecisive initiative to resolving(3)/ the border conflict withneighbouring Eritrea. (4)/ Noerror (5)
2. Britain's Chancellor of theExchequer Sajid Javid said thatthe U.K. government has decided(1)/ to issue a commemorativecoin (2)/ to mark the 150thbirthday anniversary (3)/ toMahatma Gandhi. (4)/ No error(5)
3. The 2022 World Cup qualifierbetween Team Melli andCambodia at Tehran's AzadiStadium (1)/ mark a decades-long push by Iranian women (2)/to be able to watch matches, (3)/something hard-liners in Iran'sShiite theocracy to this day stilloppose. (4)/ No error (5)
4. Belgium's advertising regulatorsaid on Wednesday that it hasreceived (1)/ hundreds ofcomplaints over a viral ham-burger advertisement (2)/ show-ing a comic-book version of aman punching a woman (3)/ forhanding him the wrongsandwich. (4)/ No error (5)
5. Curtailing of the ongoing wintersession of the legislature to threedays led to some heated arguments(1)/ among the Opposition and theruling BJP on the opening day, (2)/with the former seeking extensionto discuss the disaster caused byfloods and rains (3)/ across theState of Karnataka. (4)/ No error(5)Directions (Q. 06-10): Each
question below has a blank/ blanks,each blank indicating that some-thing has been omitted. Choose theright options for each blank thatbest fits the meaning of the sentenceas a whole.6. Star batsman Virat Kohli on
Friday_____legendary SachinTendulkar and Virender Sehwagby_____ a record seventh double
hundred, the highest in Indiancricket history.a) eclipsed, amassing b) hid, gatheringc) crossed, accruing1) only a2) only b3) only c4) both a & c 5) both a& b
7. Prime Minister Narendra Modiand Chinese President Xi Jinpingwill be discussing a ______ ofissues pertaining to Sino-Indianrelations,______, at the shores ofMamallapuram near Chennai.a) easily, casuallyb) myriad, informallyc) numerous, unofficially1) only b 2) both a & b3) both b & c 4) both a & c5) a, b & c
8. The arrest of Ukraine-born LevParnas and Belarus-born IgorFruman at an airport outsideWashington carrying one-waytickets to Vienna was the ______dramatic development in apolitical saga that______Trump's presidency.a) latest, threatensb) recent, exposesc) fresh, attacks1) only b 2) only c3) both b & c 4) both a & c5) a, b & c
9. Many low lying areaswere______with the heavydownpour last night in______parts of the city. a) inundated, someb) flooded, manyc) marooned, several1) only b 2) both a & b3) both b & c 4) both a & c5) a, b & c
10. The rise of hooligans accordingto some analysts is an______ofthe growing______of the peoplewith the ruling government. a) mark, delightb) indication, displeasurec) warning, anger1) only b 2) both a & b3) both b & c 4) both a & c 5) a, b & cDirections (Q. 11-15): Rear-
range the following six sentences(A), (B), (C), (D), (E) and (F) in aproper sequence to form ameaningful paragraph and thenanswer the questions given below.A) "Bheem's fight took place much
before Pakistan-Hindustan fou-ght," he recalled of the period inwhich the martyr had waged hisstruggle against the then rulerdemanding rights.
B) Assumed to be about 100 yearsold, Mr. Mane is perhaps the lastsurvivor.
C) The frailty wrought by age,surprisingly, has not affected hisvision, sense of hearing ormemory for that matter.
D) Tekam Mane, the geriatricKolam tribal from the historicBabejhari village, vividlyremembers some of thehappenings associated with therebel campaign of legendaryAdivasi leader Kumram Bheem,whose 79th martyrdomanniversary will be organised atJodeghat on October 13 as perAdivasi customs.
E) To cultivate in forest lands in the12 villages which lie on eitherside of the 22 km stretch of roadbetween Hatti and Jodeghat inpresent day Kerameri mandal ofKumram Bheem Asifabaddistrict.
F) Who had witnessed the eventsleading to Bheem's killing by thearmed forces of the Nizam ofHyderabad on September 1,1940.
11. What is the SECOND sentenceafter rearrangement?1) A 2) B 3) C4) D 5) F
12. What is the THIRD sentenceafter rearrangement?1) A 2) B 3) C4) D 5) E
13. What is the FOURTH sentenceafter rearrangement?1) C 2) B 3) D4) E 5) F
14. What is the FIRST sentenceafter rearrangement?1) B 2) A 3) C4) D 5) E
15. What is the FIFTH sentenceafter rearrangement?1) A 2) B 3) C4) D 5) FDirections: (Questions 16- 20)
Which of the phrases (1), (2), (3),and (4) given below each sentenceshould replace the phraseunderlined in the sentence to makeit grammatically correct? If thereis no error mark (5) No correctionrequired as your answer.16. The Brexit negotiations are
faltering and the UK gove-rnment's hopes to opening talkson a future trade deal with theEU this autumn looks likely to beincreasingly dashed, the EU'schief negotiator, Michel Barnier,has reported back to the bloc'smember states.1) hopes of opening talks on a
future trade deal with the EUlooks increasingly likely to bedashed this autumn
2) hopes to open talks on a futuretrade deal with the EU thisautumn look likely to beincreasingly dashed
3) hopes of opening talks on afuture trade deal this autumnwith the EU look likely to bedashed increasingly
4) hopes of opening talks on afuture trade deal with the EUthis autumn look increasinglylikely to be dashed
5) No correction required17. It was found that camels, in
contrast to horses', are not easilyspooked by gunfire or shelldetonations which, together withtheir hardiness, made them idealfor desert warfare.1) unlike horses,2) as contrasted with horses,3) unlike in case of horses4) opposed to horses,5) No correction required
18. Because scarcity of clean waterhas caused operational costs ofbusinesses to escalate, manylarge organizations are looking toshift base to places where theresource is cheaper.1) Because of escalating costs of
business operations, which isdue to scarcity of clean water,
2) Because operating costs ofbusinesses have been esca-lating, which resulted fromscarcity of clean water,
3) Due to escalating operationalcosts of businesses fromscarcity of clean water,
4) Due to scarcity of clean water,with the result that operational
costs of businesses haveescalated,
5) No correction required19. India has moved up two spot to
become seventh most valuablenation brand in the world.1) India moved up two spot to
become the seventh most valuable nation brand in the world.
2) India moves up two spots tobecome the seventh mostvaluable nation brand inworld.
3) India has moved up two spotsto become the seventh mostvaluable nation brand in theworld.
4) India has moved up two spotsto become the seventh valu-able nation brand in the world.
5) No correction required20. The triumphant leader lead his
guest to the venue which not onlymarked a milestone in diplomacybut also possibly a new politicalbeginning in the region.1) The triumphant leader is
leading his guest at the venuethat
2) The triumphant leader led hisguest out of the venue that
3) The triumphant leader led hisguest in the venue which
4) The triumphant leader leadshis guest through the venuewhich
5) No correction required
KEY
1) 3 2) 4 3) 2 4) 1 5) 26) 4 7) 1 8) 5 9) 5 10) 1
11) 4 12) 2 13) 5 14) 3 15) 116) 4 17) 1 18) 5 19) 3 20) 2
What is the FIFTH sentence after rearrangement?
K. Lalitha BaiSubject Expert
17
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@Venkey99
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IBPS CLERK PRELIMS MODEL PAPER
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Key
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General English
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Swiss Government
Excellence ScholarshipsScholarship: Swiss Government
Excellence Scholarships 2020-21
Description: Scholars will PG and PhD
degrees are invited for this excellence
award. The main objective of the
scheme is to promote research coopera-
tion and international exchange betw
een Switzerland and other countries.
Eligibility: PhD degree and PG degree
are required for postdoctoral and PhD
scholarships respectively. The applicant
must be willing to relocate to
Switzerland and must comply with all
the regulatory requirements.
Prizes & Rewards: The selected stu-
dents will receive CHF 3,500/month
(Postdoctoral) and CHF 1,920/month
(PhD scholarship) with multiple other
benefits.
Last Date to Apply: 12-11-2019
Application mode: Apply online
Short Url:
http://www.b4s.in/nava/SGE4
Commonwealth Master's
Scholarship Scholarship: Commonwealth Master's
Scholarship 2020, UK
Description: Commonwealth Schola
rship Commission (CSC), UK and
MHRD, India; is providing financial
assistance to Indian students who wish
to pursue one-year masters programmes
in various disciplines at any UK based
university. Students who have been
accepted for studies in the UK are invit-
ed to apply for this scholarship.
Eligibility: Indian students who would
have completed bachelor’s degree stud-
ies by October 2020 and have currently
been accepted for September/October
2020 intake sessions at any UK based
university are eligible to apply for this
scholarship.
Prizes & Rewards: Selected students
will receive financial assistance to
cover complete tuition fees, thesis
expenses, study travel expenses, airfare.
Each scholar will also receive a month-
ly stipend of GBP 1,362.
Last Date to Apply: 15-11-2019
Application mode: Apply online
Short Url:
http://www.b4s.in/nava/CMS2
kÕÿ\sYwæ|t‡
Courtesy: www.buddy4study.com /
Call: 08448709545, 08527484563
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@Venkey99
13ôV’≤<äsêu≤<é
ãT<Ûäyês¡+ 6.11.2019
4) Diagonals of Trapezium ABCD with
AB��DC, intersect each other at the
point ‘O’ if AB = 2CD, Find the
ratio of Areas of triangles AOB and
COD .
Sol: From the
figure In
trapezium
ABCD,
AB��DC
Also given AB = 2 CD
In ΔAOB and ΔCOD ∠AOB =
∠COD (vertically opposite anlges )
∠OAB = ∠OCD (alternate interior
angles)
ΔAOB ~ ΔCOD (by AA similarity)
5) Two poles of heights 6m and 11m
stand on a plane ground. If the dis-
tance b/w the feet of the poles is 12m
find the distance b/w their tops.
Sol: From the figure
Let the height of the first pole
AB = 6m Let the height of the second
pole CD = 11 m
Distance b/w the poles (AC) = 12m
From the figure ACEB is a rectangle
∴AB = CE = 6m
ED = CD – CE = 11 – 6 = 5m
Now 2m BED
BP2=BE2+DE2=122+52=144+25
=169
BD= √169 = 13m ∴distance b/w
the tops of the poles = 13m
1) Construct a tri-
angle shadow
similar to the
given ?ABC,
with its sides
equal to 5 / 3rd
of the corre-
sponding sides of the triangle ABC
Sol: Steps of construction :-
→ Draw a ΔABC with certain meas-
urement
Proof:- In ΔABC, ΔA1BC1
∠B=∠B= (common angle); ∠BCA
= BC1A1(∴corresponding angles)
∴By AA similarity ?ABC ~ ?A1BC1
2) ABCD is a
Tr a p e z i u m
in which AB
|| DC and its
d i a g o n a l s
intersect each other at point ‘o’
show that AO/BO = DO/CO
Sol: Given: In Trapezium ABCD, AB ||
DC ; Diagonals AC, BD intersect
each other at O
R.T.P: AO/BO = CO/DO
Construction: Draw a line EF passing
through the point ‘O’ and parallel to
CD and AB Proof: In ΔACD , EO ||
CD
3) Equilateral triangles are drawn on
the three sides of a right angle tri-
angle S.T the area of the triangle on
the hypotenuse is equal to the sum
of the areas of triangles on the
other two sides
Sol: Given:
In ΔABC ; ∠C
=900 ΔABD,
ΔBCE, ΔACF
are equilateral
triangles on
the sides of
ΔABC R.T.S : ΔABD = ΔBCE + ΔACF
4) A girl of height 90cm is walking
away from the base of a lamp- post
at a speed of 1.2 m/sec if the lamp
post is 3.6m above the ground. Find
the length of her shadow after 4
seconds.
Sol: Given :
A lamp-post AB of height =3.6 m=
360 cm
Speed of the girl = 1.2m/sec
Distance traveled in 4 sec = speed ×
Time = 1.2 × 4 = 4.8 m = 480 cm
Height of the girl = 90 cm
Let the length of the shadow at 2 dis-
tance of 4.8 m from the lamp post =
χcm
From the figure ΔABE ~ ΔDCE
MATHS
CompetitiveExams Special
Mr. K. KumarSenior Faculty
Hyderabad
ph:9492956214
D C
BA
O
4
1
2 2
2 2
2
2
Ar( AOB) AB (2DC) = =
Ar( COD) DC (DC)
4DC=
DC
Ar AOB and Ar COD = 4 : 1
Δ
Δ
=
Δ Δ
B
A C
D
6 m
11 m
12 m
12 m
5 m
6 m
4 Marks
A
C1
C1
C
x
B
B1B2 B3
B4 B5
1 1 2 3 4 4 5
3
Draw a ray BX which makes acute
angle with BC
Make '5' equal parts on BX such
that BB = B B = B B = B B
Join B C
→
→
→
����
����
3
1
5
Draw a parallel line to B C through
B which will meet produced BC at c
Draw
→
→1 1
1 1
a parallel line to AC through
C which will meet produced BA at A
DA BC lines are required similar
triangle
→
1 1 1 1
1
5
3
1 1 1 1
5
3
5
3
A B BC A C
AB BC AC
BBBCWe knowthat
BC BB
A B BC A C
AB BC AC
= =
D C
BA
E FO
( )
( )
( )
............... 1 . .
,
............... 2
1 2
AO BO AO COAtequendo
CO DO BO DO
Hence Proved
AO AEB P T
CO DE
In ABD EO AB
BO AEInvertendo
DO ED
from and
= ⇒ =
Δ
=
�
�
�
�
F
A D
B
E
C a
cb
2
2
2
3
4
' '
3.............. 1
4
3................ 2
4
Area of an equilateral triangle
= a
Where a is side
ABC C
BCE a
∴Δ =
Δ =
Proof :
2
2 2 2
4
3................ 3
4
3
ACF b
By using pythagorasTheorem
C a b
Multiplying both the sides by
Δ =
= +
4
( )2 2 2
2 2 2
3 3
4 4
3 3 3
4 4 4
we get C a b
C a b
ABC BCE ACF
Hence proved
= +
= +
Δ = Δ + Δ
A
BC
D
90cm
36m
=360cm
E χ
( )
( )
090
4803 480 160 1.6
3
360 480
90
4 480 4 480
B C E E common
x x cm m
AB BE AEAA simlicity
DC CE DE
x
x
x x x x
∴ ∠ = ∠ = ∠ = ∠
⇒ = ⇒ = = =
+
= + ⇒ − =
�
�
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Find the length of her shadow after 4 seconds
@Venkey99
ãß<Ûäyês¡+ 6
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GENERALAWARENESS
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16. {Á≥´ßëØ˲–ö $Ö{Ü {V>“$◊˝ Á‹yÊ˛Mä¸ ƒÒ˝*fØ˲ (Ô≥GÖiGã‹– ˛O) –ö˛$*yÊ˛–ö˛ ßÊ˛‘Ë˝ AÖ‘ÈÀØ˲$ Á≥«÷ÕÖ_Á‹ΔˇOØ˲ –ÈsÏ˝∞ Vʸ$«¢Ö^˲ÖyÏ˛.1) ßÛ˛‘Ë˝–È≈Á≥¢ÖV> ÀÑ>- CΔÊˇ–˛O AΔˇ$$ßÊ˛$ –Û˛À Mϸ.“$
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4) Δ>ÁŸâÖÃZ °{–ö˛–ÈßÊ˛ {Á≥øÍ—ô˲ hÃÍœÃÒ˝OØ˲ {÷M>Mʸ$‚Ê˝Ö, —fƒÊ˝$Ø˲VʸΔÊˇÖ, —‘ÈQ, ô˲*ΔÊˇ$µ V¯ßë–ö˛« hÃÍœÃZœ –ö˛$Δ¯ 53 Mϸ.“$ Δ¯yÊ˛œ ∞Δ>√◊˝Ö –ö˛$ÖlΔˇOÖ®.
5) 1, 2, 3, 417. A◊˝$ Áú$rMʸ –ÈƒÊ˝$$ M>À$ÁŸ≈ÖÚ≥O ¥˘Δ>yÛ˛ÖßÊ˛$MÊ $
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18. Aô˲≈Öô˲ A´ßÊ˛$ØÈô˲Ø˲–˛$OØ˲ fÃÍÖô˲Δ>Y—$ Ø˲$Ö_{Á≥ƒÒ˝*WÖ^Û˛ gÙ˝GÃå˝&3 QÖyëÖô˲ΔÊˇ ÑϸÁ≥◊Ï˝∞ HßÛ˛‘Ë˝Ö CsÓ˝–ö˛À —fƒÊ˝$–ö˛ÖôË ÖV> {Á≥ƒÒ˝*WÖ_Ö®? 1) ^˛OØÈ 2) A–˛$«M> 3) f¥ÎØå˛ 4) ΔÊˇ⁄Î≈
19. {Á≥Á≥Ö^˲ ßÛ˛‘ÈÀ Á‹*¶À gÍ°ƒÒ˝*ô˲µÜ¢ (iyÓ˛Ô≥)Δ>≈ÖMä¸ & 2018 {Á≥Á≥Ö^˲ ªÍ≈ÖMä¸ ∞–Û˛®Mʸ {Á≥M>ΔÊˇÖA–˛$«M> –˛$$ßÊ˛sÏ˝ ›Î¶Ø˲ÖÃZ EÖyÊ˛V> øÍΔÊˇô¨˛ H›Î¶Ø˲ÖÃZ ∞Õ_Ö®? 1) 3 2) 5 3) 6 4) 7
20. 2022 Á‹Ö–ö˛ô˲fiΔÊˇÖ ØÈsÏ˝Mϸ ßÛ˛‘Ë˝ÖÃZ G∞≤ –Û˛À –˛$V>–Èrœ ›Î–ö˛$ΔÊˇ ¶≈ÖVʸÀ ›˘ÃÍΔäˇ —ßÊ˛$≈ô¨˛ ¥ÎœÖrœØ˲$∞«√Ö^ÈÀ∞ MÛ¸Ö{ßÊ˛ {Á≥øÊ˝$ô˲”Ö ÀÑ>-≈∞≤ ∞ΔÛˇÆ’Ö^˲$Mʸ$Ö®? 1) 25 2) 30 3) 35 4) 40
21. Δ>ÁŸâ–È≈Á≥¢ÖV> 2019 BVʸÁ‹$t 31Ø˲ 70–ö˛ –ö˛Ø˲–ö˛$ÁflZô˲fi–È∞≤ BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ –ö˛$$Q≈–ö˛$Ö{Ü –˛O.Gã‹.fVʸØå˛, y¯MϸÁ≥{Δ Êˇ$ {V>–ö˛$Ö –ö˛ßÊ˛ ™ – ˛$$MʸP ØÈsÏ˝ÃÍÖb˲Ø˲ÖV> {¥ÎΔÊˇÖ¿Ö^ÈΔÊˇ$. AΔˇ$$ôÛ˛ D {V>–ö˛$ÖH hÃÍœÃZ EÖ®? 1) ô˲*ΔÊˇ$µ V¯ßë–ö˛« 2) Á≥’a–ö˛$ V¯ßë–ö˛« 3) Mʸñ⁄Î~ 4) Vʸ$Ör*ΔÊˇ$
22. Á≥Ör Mʸ±Á‹ –ö˛$ßÊ˛Æô˲$ ´ßÊ˛ΔÊˇ (GÖGã‹Ô≥) ÁúÀÖ ΔˇOô˲$ÀMʸ$ –ö˛*{ô˲–Û˛$ ^Û˛ΔÊˇyë∞Mϸ ı‹Mʸ«Ö^Û˛ A∞≤ ΔÊˇM>ÀÁ≥Ör Eô˲µô˲$¢ÀØ˲$ B´ßëΔäˇô¯ AØ˲$Á‹Ö´ßë∞Ö Ë˛$rMʸ$, D Q»ãú Ô‹fØå˛ÃZ MÛ¸Ö{ßÊ˛ {Á≥øÊ˝$ô˲”Ö HΔ>ÁŸâÖÃZ∞ 4 hÃÍœÃZœ Ú≥OÀså˝ {¥ÎgÒ˝Mʸ$tØ˲$ ^Û˛Á≥yÊ˛$ô¯Ö®?1) JyÏ˛‘È 2) BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ 3) ô˛ÀÖV>◊˝ 4) MʸΔ>~rMʸ
23. H Δ>ÁŸâ Á≥Δ>≈rMʸ ‘ÈQMʸ$ Á‹∏λ CÖyÏ˛ƒÊ˝* &
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24. {Á≥Á≥Ö^˲ ›Î¶Δˇ$$ÃZ gÍ°ƒÊ˝$ ¥˘ŒÁ‹$ —‘Ë˝”—ßë≈ÀƒÊ˝*∞≤ GMʸPyÊ˛ HΔ>µr$ ^Û˛ƒÊ˝$Ø˲$Ø˲≤r$œ MÛ¸Ö{ßÊ˛ÁflZÖ ‘ÈQ {Á≥MʸsÏ˝Ö_Ö®?1) {VÛ¸rΔäˇ Ø¯Δˇ$$yë 2) ¥ÎsÍ≤ 3) ÌŸÃÍœÖVä¸ 4) ^˛Ø˛O≤
25. BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ ¥˘Œã‹ —øÍV>∞Mϸ ^˛Ö®Ø˲ AÖô˲Δ>j°ƒÊ˝$ Ì‹”–ö˛$√Δäˇ GÖ. ô˲$ÀÔ‹ ^˛Oô˲Ø˲≈, M>rŒØÈ^ÈØ˛Ãå˝Ø˲$ D®Ø˲ ôˆÕ ô˛À$Vʸ$ Ì‹”–ö˛$√ΔäˇV> «M>ΔÊˇ$z›Î´®Ö^ÈΔ Êˇ$. AΔˇ$$ôÛ˛ D bÈØ ˛Ãå˝ H ßÛ˛‘Ë˝ÖÃZEÖ®?1) {÷ÀÖMʸ 2) ØÛ˛¥ÎÃå˝ 3) A–˛$«M> 4) MʸfMϸ›Î¶Øå˛
26. BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ÃZ – ˛$$ô˲ ¢Ö 2051 {¥Î£Ê˛—$Mʸ–ö˛≈–ö˛›ÎƒÊ˝$ Á‹Áfl˝M>ΔÊˇ Á‹ÖÁú*ÀØ˲$ (Ô≥HÔ‹Gã‹)Ø˲$Á≥N«¢›Î¶Δˇ$$ÃZ MʸÖÁ≥N≈r»Mʸ«Ö^ÈÀ∞ ∞Δ Êˇ ~Δˇ$$Ö^ÈΔ Êˇ$. CÖßÊ˛$ÃZ G∞≤ Ô≥HÔ‹Gã‹À$ ÃÍøÍÃZœEØÈ≤Δˇ$$?1) 1,240 2) 1,300 3) 1,320 4) 1422
27. ∞ΔÊˇΔÊˇ¶Mʸ BÁ‹$¢À (ΔÊˇ*.116.52 M¯r$œ) M>ΔÊˇ◊˝ÖV>BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ÃZ AΔˇ$$ßÊ˛$ hÃÍœ MÛ¸Ö{ßÊ˛ Á‹Áfl˝M>ΔÊˇªÍ≈ÖMʸ$À$ B«¶MʸÖV> ∫ÀÔfl˝Ø˲–ö˛$ƒÊ˝*≈Δˇ$$.AΔˇ$$ôÛ˛ “sÏ˝∞ Vʸ$«¢Ö^˲ÖyÏ1) —fƒÊ˝$Ø˲VʸΔÊˇÖ, {Á≥M>‘Ë˝Ö, MʸyÊ˛Á≥2) MʸΔÊˇ*≤À$, AØ˲Öô˲Á≥#ΔÊ Ö3) Ø˛À*œΔÊˇ$, Vʸ$Ör*ΔÊˇ$, {Á≥M>‘Ë˝Ö, MʸΔÊˇ*≤À$, MʸyÊ˛-Á≥4) 1, 2
28. BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ –ö˛$$Q≈–ö˛$Ö{Ü – ˛OGã‹ fVʸØå˛,–˛OG›ÎfiΔäˇ ΔˇOô˲$ øÊ˝Δ¯›Î & Ô≥GÖ Mϸ›ÎØå˛ Á≥£Ê˛M>∞≤2019 AM¯t∫ΔÊˇ$ 15Ø˲ GMʸPyÊ˛ {¥ÎΔÊˇÖ¿Ö^ÈΔÊ $? 1) M>Mʸ$r*ΔÊˇ$ (Ø˛À*œΔÊˇ$) 2) Ø˲Ößë≈À (MʸΔÊˇ*≤À$)3) WßÊ˛™À*ΔÊˇ$ ({Á≥M>‘Ë˝Ö) 4) Bô˲√Mʸ*ΔÊˇ$ (Ø˛À*œΔÊˇ$)
29. BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ AÖ‘ÈÀØ˲$ Á≥«÷ÕÖ_ Á‹ΔˇOØ˲–ÈsÏ˝∞Vʸ$«¢Ö^˲ÖyÏ .1) {Á≥´ßëØ˲–ö˛$Ö{Ü Á‹yÊ˛Mä¸ ƒÒ˝*fØ˲ (Ô≥GÖiGã‹–˛O)
Á≥£Ê˛MÊ¸Ö –ö˛$*yÊ˛–ö˛ ßÊ˛‘Ë˝ A–ö˛$À$ÃZ øÍVʸÖV> MÛ¸Ö{ßÊ˛Ö ßÛ˛‘Ë˝ –È≈Á≥¢ÖV> 1.25 ÀÑʸÀ MϸÃZ“$rΔÊˇœ {V>“$◊˝ ÕÖMʸ$ Δ¯yÊ˛œ ∞Δ>√◊˝Ö M¯Á‹Ö Δ>⁄ÎâÀMʸ$ B«¶Mʸ Á‹‡ƒÊ˝$Ö ^Û˛Á‹$¢Ö®.
2) BÖ{´ßÊ˛{Á≥ßÛ˛‘å Mʸ$ 3,285 MϸÃZ“$rΔÊˇœ ¥˜yÊ˛–˛OØ˲ Δ¯yÊ˛œØ˲$ –ö˛$ÖlΔÊˇ$ ^Û˛Ì‹Ö®. “sÏ˝ ∞ΔÊˇ”Áfl˝◊˝ –ö˛≈ƒÊ˝$ÖÃZ 60 ‘ÈôË˛Ö ∞´ßÊ˛$À$ MÛ¸Ö{ßÊ˛ {Á≥øÊ˝$ô˲”Ö, —$WÕØ˲ 40 ‘ÈôË˛Ö ∞´ßÊ˛$À$ Δ>ÁŸâ {Á≥øÊ˝$ô˲”Ö øÊ˝«›Î¢Δˇ$$.
3) CsÓ˝–ö˛À ÁflZÖV>ΔÊˇ$zÀ Δ¯k–È» –Û˛ô˲ØË˛Ö ΔÊˇ*.600 Ø˲$Ö_ ΔÊˇ*.710ÀMÊ $ Ú≥Ö^ÈΔÊˇ$.
4) 1, 2, 330. BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝ÃZ "–ÈrΔäˇ {Wyä˛ {¥ÎgÒ˝Mä¸t' {Á≥◊Í„Mʸ
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CÖsÏ˝Mϸ Mʸ$‚ÍΔˇ$$À ßë”Δ> 2022 ØÈsÏ˝Mϸ Á‹ΔÊˇÁúΔ> ^Û˛ƒÊ˝*ÀØÛ˛ ÀÑʸ≈Öô¯ D {¥ÎgÒ˝Mʸ$tMʸ$ ΔÊˇ*Á≥MʸÀµØ˲ ^Û˛‘ÈΔÊˇ$.
2) {V>“$◊˝ {¥ÎÖôÈÃZœ∞ 46,982 ∞–ÈÌ‹ô˲ {¥ÎÖôÈÀô¯ ¥Îr$ Δ>ÁŸâÖÃZ∞ 110 Á≥rt◊˝, Ø˲VʸΔÊˇ ¥ÎÀMʸ {¥ÎÖôÈÀMʸ$ –ÈrΔäˇ {Wyä˛ {¥ÎgÒ˝Mʸ$t ßë”Δ> ôÈVʸ$ ±sÏ˝∞ Á‹ΔÊˇÁúΔ> ^Û˛›Î¢ΔÊˇ$.
3) D {¥ÎgÒ˝Mʸ$t A–ö˛$À$Mʸ$ HÌŸƒÊ˝$Øå˛ y˛–ö˛Àã≥–˛$Öså˝ ªÍ≈ÖMä¸ (HyÓ˛Ω) Ø˲$Ö_ ΔÊˇ*.2,500 M¯rœ ΔÊˇ$◊˝Ö °Á‹$M¯–ÈÀ∞ ∞ΔÊˇ~Δˇ$$Ö^ÈΔÊˇ$.
4) –ö˛$*yÊ˛$ ßÊ˛‘Ë˝ÃZœ D {¥ÎgÒ˝Mʸ$tØË $ A–ö˛$À$ ^Û˛›Î¢ΔÊˇ$. 31. Δ>ÁŸâÖÃZ∞ {Á≥øÊ˝$ô˲” HgÒ˝±fiÀ$ ÃÙ˝ßë ›Î¶∞Mʸ A´®
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^Û˛Ì‹Ö®? 1) 100 2) 200 3) 250 4) 300
32. Ø˲*≈{sÏ˝ÁŸØå˛ CÖrΔÛˇ≤ÁŸØ˲Ãå˝ Á‹ΔÛˇ” {Á≥M>ΔÊˇÖ Aô˲≈´®Mʸ‘ÈôË˛Ö –ö˛$Ö® AƒÒ˝*y˛Ogå˝z EÁ≥#µØ˲$ f–ö˛$$√ Mʸ÷√ΔäˇÃZ—∞ƒÒ˝*WÁ‹$¢ØÈ≤ΔÊˇ$. AΔˇ$$ôÛ˛ ©∞∞ AÜ ô˲Mʸ$P–ö˛V>—∞ƒÒ˝*WÁ‹$¢ØË ≤ Δ>ÁŸâÖ H®?1) ØÈV>ÃÍÖyä˛ 2) –ö˛$´ßÊ˛$ΔÊˇ 3) ô˲—$‚Ê˝ØÈyÊ˛$ 4) BÖ{´ßÊ˛{Á≥ßÛ˛‘å˝
33. {Á≥ôÈ≈–ö˛*≤ƒÊ˝$ AyÊ˛–ö˛#À Ú≥ÖÁ≥MʸÖ, AyÊ˛–ö˛#ÃZœ M>«a^˲$aÀØ˲$ AyÊ˛$zM¯–ö˛yÊ˛Ö, i–ö˛ –˛O—´ßÊ˛≈ ∞ΔÊˇ”Áfl˝◊˝,øÊ˝*›ÎΔ Êˇ Á≥«Δ ÊˇÑʸ◊˝ Á‹‡ Áfl˝«ô˲ M>Δ Êˇ≈MʸÃÍ¥ÎÀM¯Á‹Ö MÛ¸Ö{ßÊ˛ Á≥Δ>≈–ö˛ΔÊˇ◊˝ –ö˛$Ö{Üô˲” ‘ÈQ 27 Δ>⁄ÎâÀMʸ$ G∞≤ –Û˛À M¯rœ ΔÊˇ*¥ÎƒÊ˝$ÀØ˲$ –ö˛$ÖlΔÊˇ$^Û˛Ì‹Ö®?1) 47,000 2) 48,500 3) 49,200 4) 50,250
34. BΔˇ$$Ãå˝ AÖyä˛ ØÛ˛^˲$ΔÊˇÃå˝ V>≈ã‹ M>Δ¯µΔÛˇÁŸØå˛ (KGØå˛iÔ‹) H Δ>ÁŸâÖÃZ ^˲–ö˛$$ΔÊˇ$ AØÛ˛”ÁŸ◊˝, Eô˲µÜ¢M¯Á‹Ö Δ>ªZƒÙ˝$ AΔˇ$$ßÛ˛‚Ê œÃZ 13 –Û˛À M¯rœ ΔÊˇ*¥ÎƒÊ˝$À Ú≥r$t∫yÊ˛$À$ Ú≥yÊ˛$ô˲$Ø˲≤r$œ {Á≥MʸsÏ˝Ö_Ö®? 1) BÖ{´ßÊ˛{Á≥ßÛ˛‘å 2) A›˘Ö 3) AΔÊˇ$◊Í^˲Ãå˝ {Á≥ßÛ˛‘å˝ 4) ØÈV>ÃÍÖyä˛
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36. BßëƒÊ˝$ »ôÈ≈ øÍΔ Êˇô¨˛ÃZ AÜ Ú≥ßÊ˛ ™ Á‹ÖÁ‹¶V>B—ΔÊˇ¬—Ö_Ø˲® H®?1) CÖyÏ˛ƒÊ˝$Øå˛ BΔˇ$$Ãå˝ M>ΔˆµΔÛˇÁŸØå˛ 2) «ÀƒÊ˝$Øå˛fi CÖyÊ˛Ô‹âã‹ 3) KGØå˛iÔ‹ 4) V>≈ã‹ A£ë«sÓ˝ Bãú CÖyÏ˛ƒÊ˝* Õ—$sÒ˝yä˛5) Ô‹tÃå˝ A£ë«sÓ˝ Bãú CÖyÏ˛ƒÊ˝* Õ—$sÒ˝yä˛
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38. øÍΔÊˇô¨˛ ôˆÕ›Î«V> ^Û˛Á≥sÙ˝t ôˆÕ –ö˛*Ø˲–ö˛ Á‹Ìfl˝ô˲AÖô˲«Ñʸ ƒÊ˝*{ô˲ "VʸVʸØå˛ƒÊ˝*Øå˛' M¯Á‹Ö C{›˘ HÁ‹ÖÁ‹¶ô¯ JÁ≥µÖßÊ˛Ö Mʸ$ßÊ˛$ΔÊˇ$aMˆÖ®? 1) yÓ˛BΔäˇyÓ˛K 2) GØå˛GÖyÓ˛Ô‹ 3) ΩyÓ˛GÃå˝ 4) 2, 3
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—–ö˛ΔÊˇ◊˝À$45. Value of A's share = (2/5)*50000
= Rs 20,000 Value of C's share = (1/5)*50000 = Rs 10,000 Required difference = 20000 - 10000 = Rs 10,000
46. Let the cost price of the article be x. Then as per the question 678 - x = x – 452 2x = 1130 => x = 565
47. Passed (Science) = 60% Passed (Maths) = 80%Failed (Maths + Science) = 8% Percentage of students passed in at least oneof the subjects = 100 - 8 = 92% Passed (Maths + Science) = 80 + 60 - 92 = 48% Total number of students = 100/48 x 96 = 200
48. Total bill = Rs 5000 Amount paid by Amar = (15/100)*5000 Amount paid by Srishti = (10/100)*5000 Difference = (15/100)*5000 - (10/100)*5000 = Rs 250
49. Let the total bill amount be Rs 'x' Difference between the amounts paid byPayal and Rohit = (30/100)*x - (25/100)*x = Rs 5x/100 Sum of the amount paid by Srishti and Rahul = (10/100)*x + (20/100)*x = Rs 30x/100 Ratio = 5x/100 : 30x/100 = 1:6
50. Let the total bill amount be Rs 'x' Amount paid by Amar = (15/100)*x = Rs 15x/100 Amount paid by Rohit = (30/100)*x = Rs 30x/100 Given, 15x/100 = 30x/100 – 900 15x/100 = 900 x = Rs 6,000 Sum of the amount paid by Srishti andRahul = (10/100)*6000 + (20/100)*6000 = Rs 1,800
51. Let the total bill amount originally be Rs 'x'.New bill amount = x(1 + 20/100) = 120x/100 Amount paid by Payal originally = (25/100)*x = 25x/100 Amount paid by payal in new bill = (20/100)*(120x/100) = 24x/100 Given, 24x/100 = 25x/100 – 40 => x = Rs 4,000
52. Let the total bill amount be Rs 'x' Sum of amount paid by Amar, Srishti andPayal = (15/100)*x + (10/100)*x + (25/100)*x = 50x/100 = x/2
53. P*5*2T/100 - P*5*T/100 = 200 P*5*T/100 = 200 P*T = 4000 Since the time period is not given, we can't determine the sum.
54. ? � (240/4) - 16 x 4 + 3� 512 = 60 - 64 + 8 = 4
55. ? = 2100 ÷ 84 x 33 - 23= 25 x 33 - 23 = 825 - 23
= 802
56. 173 = 4913, 63 = 216, 143 = 2744 17+6+14 = 37
57. (?)2 = 332 - 4 - 53
= 1089 - 4 - 125 = 960
58. (40 X 2820/100) + � 196 - 645 = 1128 + 14 - 645 = 497
59. Average speed = (total distance)/(total time) Average speed of the truck = 368/8 = 46 kmph. Average speed of the car = 46+18 = 64 kmph. Time taken by the car = (total distance)/(total time) = (368 + 16)/64 = 6 hrs.
60. Sum of all students in dance in all classes = 32 + 22 + 42 + 40 + 41 = 177 Sum of all students in debate in all classes= 37 + 44 +32 + 44 + 29 = 186 Ratio = 177: 186 = 59: 62
61. Total number of students in art and craft = 28 + 36 + 18 + 18 + 36 = 136Total number of students in all classes = 798 Required percentage = (136/798) X 100 = 17%
62. Students in debate and dance in class 11TH
= 84 Students in dance and drama in class 8TH
= 66 Required percentage = [(84 - 66)/66] X 100= 27.3%
63. Sum of students in dance and art and craftin all classes = 177 + 136 = 313 Sum of student in music and debate in allclasses = 156 + 186 = 342 Difference = 342 - 313 = 29
64. Total number students in debate in all classes = 186 Number of students left debate = (1/6) X 186 = 31 Total number students in music in all classes = 156 Number of students left music = (1/3) X 156 = 52 Total strength of students in communityservice = 52 + 31 = 83
65. Let's assume B can do 'n' units per dayhence A will do '2n' units per day and C willdo '6n' units per day. According to the question A alone can complete the work in 35 days hence total work = (35 X 2n) units = 70n Total number of units done by A, B and Ctogether in one day = (n + 2n + 6n) units = 9n units Hence number of days taken to completethe work = 70n/9n = (7) (7/9) days
LOGICAL REASONING
(66-70):
Day Teacher Subject Monday T Chemistry Tuesday P Geography Wednesday S Economics Thursday U English Friday R Biology Saturday Q Mathematics Sunday V Physics
(71-75):
76. This means Q is either the tallest or the second tallest. So his height could be possibly 158cm (in case he is the second tallest)
77. Q is either the tallest or the second tallest.So there are either three or four personsshorter than him.
78 - 82
Floor Number Person Apartment7 B 2-BHK6 A 1-BHK5 E 2-BHK4 D 1-BHK3 F 2-BHK2 G 1-BHK1 C 2-BHK
83 - 84
85 - 86
87. Y > H > Z < W < S Conclusions I. S > Y (False) II. Y = W (False) So neither I nor II is true. Hence, option e.
88. L > O < J < G < C Conclusions I. O = C (False) II. C > O (True) So only II is true. Hence, option b.
89. Q < R, Q = P, R < N, O < PO < P = Q < R < N Conclusions I. R > P (False) II. N > O (True) So, only conclusion II is true.
90. V < L, J > V, E > H, H > LJ > V < L < H < E Conclusions I. J > E (False) II. V < H (False) So, neither conclusion I nor conclusion II is true.
91. If all the numbers are arranged in ascendingorder we get, 314, 452, 563, 648, 724, 897Sum of third digit of first two numbers andsecond digit of next two numbers and thethird digit of last two numbers = 4+2+6+4+4+7=27
92. If in al the numbers 1st and 2nd digits are
interchanged 653 987 542 274 134 468 Sum of highest and lowest number and the= 987+134=1121 Sum of second highest and second lowestnumber 653+274=927 Difference between the sum of highest andlowest number and the sum of second high-est and second lowest number 1121-927=194
93. If all the digits in all the numbers arereversed 365 798 254 427 413 846
94. If the 1st and 3rd digit is interchanged in allthe numbers, 365 798 254 427 413 846 427 is the 3rd highest Product of all the digits of 3rd highest number = 4 X 2 X 7=56.
95. First we break the series, Now, ACFJO / BDGKP / CEHLQ / DFIM_ABCDEFGHIJKLMNO -> ➞ ACFJO (gap of 1 alphabet between 1st& 2nd element, then gap of 2 alphabetsbetween 2nd & 3rd element & so on) BCDEFGHIJKLMNOP - >➞ BDGKP (gap of 1 alphabet between 1st& 2nd element, then gap of 2 alphabetsbetween 2nd & 3rd element & so on) CDEFGHIJKLMNOPQ -> ➞ CEHLQ (gap of 1 alphabet between 1st& 2nd element, then gap of 2 alphabetsbetween 2nd & 3rd element & so on) So, DEFGHIJKLMNOPQR -> DFIMR, SO ANSWER IS '' R''
96. Now if each odd digit number is decreasedby 1 and each even digit number isincreased by 2 in 3265794, we get 2484686So, the numbers 4, 6 and 8 are the numberswhich appears twice.
97. 4th 5th 7th 8th C O A T
Meaningful words: Coat, Octa, Taco etc.More than one meaningful words can beformed from the above letters.
98
Both Conclusions follow
99.
None of the conclusions follow
100.
Conclusion II follows.
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