class6 shearstrength directsheartest 150416085805 conversion gate02
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CE 3121: Geotechnical Engineering Laboratory
Class 6
Shear Strength
(Direct Shear Test)
Sources:
Soil Mechanics – Laboratory Manual, B.M. DAS (Chapter 15)
Soil Properties, Testing, Measurement, and Evaluation, C. Liu, J. Evett
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Shear strength in soils
Introduction
Definitions Direct shear test
Introduction
Procedure
Calculation
Results and Figures
Class Outlines
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Shear Strength
The strength of a material is the greatest
stress it can sustain
The safety of any geotechnical structure is
dependent on the strength of the soil
If the soil fails, the structure founded on it can
collapse
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Slope Failure in Soils
Failure due to inadequate
strength at shear interface
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Shear Failure in Soils
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Transcosna Grain Elevator Canada(Oct. 18, 1913)
West side of foundation sank 24-ft
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Significance of Shear Strength
Engineers must understand the nature ofshearing resistance in order to analyze soilstability problems such as;
Bearing capacity Slope stability
Lateral earth pressure on earth-retainingstructures
Pavement
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Shear Strength in Soils
The shear strength of a soil is its resistance toshearing stresses.
It is a measure of the soil resistance to deformationby continuous displacement of its individual soilparticles
Shear strength in soils depends primarily oninteractions between particles
Shear failure occurs when the stresses between the
particles are such that they slide or roll past eachother
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Shear Strength in Soils (cont.)
Soil derives its shear strength from two
sources:
Cohesion between particles (stress
independent component)
Cementation between sand grains
Electrostatic attraction between clay particles
Frictional resistance between particles (stressdependent component)
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Shear Strength of Soils; Cohesion
Cohesion (C), is a measure of the forces thatcement particles of soils
Dry sand with no cementation Dry sand with some cementation
Soft clay
Stiff clay
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Shear Strength of Soils; Internal Friction
Internal Friction angle (f ), is the measure of theshear strength of soils due to friction
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Mohr-Coulomb Failure Criteria
This theory states that a material fails
because of a critical combination of normal
stress and shear stress, and not from their
either maximum normal or shear stressalone.
The relationship between normal stress and
shear is given as
f tanc sfrictioninternalof angle
cohesionc
strengthshears
f
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Shear
Strength,S
Normal Stress, n = = h
C
f = f
Mohr-Coulomb Failure Criterion
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General State of Stress
σ1
σ1 major principle stress
σ3 σ3Minor principle stress
Confining stress
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State of Stresses in Soils
σ1
Shear
stress σ3σ3
Normal stress σnConsider the following situation:
- A normal stress is applied vertically
and held constant
- A shear stress is then applied until
failure
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Determination of Shear Strength
Parameters
The shear strength parameters of a soil are
determined in the lab primarily with two types of tests;
Direct Shear Test
Triaxial Shear Test
Soil
Normal stress σn
Shear stress σ3
3
1
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Direct Shear Test
Direct shear test is Quick and Inexpensive
Shortcoming is that it fails the soil on a
designated plane which may not be the
weakest one
Used to determine the shear strength of both
cohesive as well as non-cohesive soils
ASTM D 3080
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Direct Shear Test (cont.)
The test equipment consists ofa metal box in which the soilspecimen is placed
The box is split horizontallyinto two halves
Vertical force (normal stress)is applied through a metalplaten
Shear force is applied bymoving one half of the boxrelative to the other to causefailure in the soil specimen
Soil
Normal stress σn
Shear stress σ3
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Direct Shear Test
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Direct Shear Test
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Direct Shear Test
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Direct Shear Test Data
S h e a r s t r e s s
Residual Strength
Peak Strength
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Direct Shear Test Data
Volume change
H
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Direct Shear Test (Procedure)
1.Measure inner side or diameter of shear box and find the area
2.Make sure top and bottom halves of shear box are in contact andfixed together.
3.Weigh out 150 g of sand.
4.Place the soil in three layers in the mold using the funnel.Compact the soil with 20 blows per layer.
5.Place cover on top of sand
6.Place shear box in machine.
7. Apply normal force. The weights to use for the three runs are
2 kg, 4 kg, and 6 kg if the load is applied through a lever arm, or 10kg, 20 kg, and 30 kg, if the load is applied directly.
Note: Lever arm loading ratio 1:10 (2kg weight = 20 kg)
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Direct Shear Test (Procedure)
8. Start the motor with selected speed (0.1 in/min) so that the
rate of shearing is at a selected constant rate
9. Take the horizontal displacement gauge, vertical displacement
gage and shear load gage readings. Record the readings on
the data sheet.10. Continue taking readings until the horizontal shear load peaks
and then falls, or the horizontal displacement reaches 15% of
the diameter.
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Calculations
1. Determine the dry unit
weight, gd
2. Calculate the void
ratio, e
3. Calculate the normal
stress & shear stress
1d
wGs
e
g
g
A
V
A
N ;
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Figures
S h e a r
s t r e
s s , s
Peak Stress
N1 = 10 kg
N2 = 20 kg
N3 = 30 kg
Horizontal displacement, H
s3
s2
s1
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Figures (cont)
S
h e a r
S t r e s s , s
( p s f )
C
f
(1,s1)
(3,s3)(2,s2)
Normal Stress , psf
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Figures (cont)
V e r t i c a l d i s p l a c e m e n t
Horizontal displacement
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