bellringer compare and explain in complete sentences what is a saturated solution

BELLRINGER

Compare and explain in complete

sentences what is

a saturated solution.

Previous homework

Finish and submit 4 BRs for the previous week.

SOLUTIONSIII

Water and Solutions

Concentration and Solubility

4 9.2 Concentration and Solubility

Suppose you dissolve 10.0 g of sugar in 90.0 g of water. What is the mass percent concentration of sugar in the solution?

Asked: The mass percent concentration

Given: 10 g of solute (sugar) and 90 g of solvent (water)

Relationships: 100%mass of solute

concentrationtotal mass of solution

5 9.2 Concentration and Solubility

Suppose you dissolve 10.0 g of sugar in 90.0 g of water. What is the mass percent concentration of sugar in the solution?

Asked: The mass percent concentration

Given: 10 g of solute (sugar) and 90 g of solvent (water)

Relationships:

Solve:

100%mass of solute

concentrationtotal mass of solution

10

100%10 90

10%g sugar

concentrationg of solution

sugar

6 9.2 Concentration and Solubility

( )( )

( )

( )( / )

( )

( )(%) 100

( )

,

mass of solute gconcentration g L

volume of solution L

mass of solute gconcentration

m

mol

ass of solution

es of solute mmol

oleconcentration

volume of solarity M

n

g

utio L

Concentration

There are several ways to express concentration

7 9.2 Concentration and Solubility

Concentration

Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.

8 9.2 Concentration and Solubility

Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.

Concentration

Asked: Molarity of solution

Given: Volume of solution = 100.0 mL, mass of solute (NaCl) = 6.0 g

Relationships:

22.99 35.45 58.44 /

1,000 1.0 , 100 0.10

molesM

L

Formula mass of NaCl g mole

mL L therefore mL L

9 9.2 Concentration and Solubility

Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.

Concentration

Asked: Molarity of solution

Given: Volume of solution = 100.0 mL, mass of solute (NaCl) = 6.0 g

Relationships:

Solve:

22.99 35.45 58.44 /

1,000 1.0 , 100 0.10

molesM

L

Formula mass of NaCl g mole

mL L therefore mL L

0.

0.1031.03

16.0

58.

0.100

344

10mole NaCl

moles NaCl g NaClg NaC

mole

moles Na

s

Cl

M

l

ML

10 9.2 Concentration and Solubility

Calculate the molarity of a salt solution made by adding 6.0 g of NaCl to 100 mL of distilled water.

Concentration

Asked: Molarity of solution

Given: Volume of solution = 100.0 mL, mass of solute (NaCl) = 6.0 g

Relationships:

Solve:

Answer: 1.03 M solution of NaCl

22.99 35.45 58.44 /

1,000 1.0 , 100 0.10

molesM

L

Formula mass of NaCl g mole

mL L therefore mL L

16.0 0.103

58.4

0.

4

103

0.101 03

0.

mole NaClmoles NaCl g NaCl moles NaCl

g NaCl

Mmoles

ML

11 9.2 Concentration and Solubility

sugar

100 mLH2O

10 g

What happens when you add 10 g of sugar to 100 mL of water?

Conc. (%) = 10 g/110 g

Solubility

12 9.2 Concentration and Solubility

100 mLH2O

What happens when you add 10 g of sugar to 100 mL of water?

Conc. (%) = 10 g/110 g

Water molecules dissolve sugar molecules

sugar10 g

Solubility

13 9.2 Concentration and Solubility

What happens when you add 10 g of sugar to 100 mL of water?

But when two sugar molecules find each other, they will become “undissolved” (solid) again…

Solubility

14 9.2 Concentration and Solubility

What happens when you add 10 g of sugar to 100 mL of water?

But when two sugar molecules find each other, they will become “undissolved” (solid) again…

… then, they become redissolved in water again.

Solubility

15 9.2 Concentration and Solubility

What happens when you add 10 g of sugar to 100 mL of water?

This is an aqueous equilibrium!

Equilibrium

Solubility

16 9.2 Concentration and Solubility

Solubility

low

high

Co

nce

ntr

atio

n

Equilibrium

dissolving “undissolving”

10 g sugar

100 mLH2O Conc. (%) = 10 g/110 g

20oC

17 9.2 Concentration and Solubility

Solubility

low

high

Co

nce

ntr

atio

n

Equilibrium

dissolving “undissolving”

18 9.2 Concentration and Solubility

saturation: situation that occurs when the amount of dissolved solute in a solution gets high enough that the rate of “undissolving” matches the rate of dissolving.

Equilibrium

dissolving “undissolving”

19 9.2 Concentration and Solubility

saturation: situation that occurs when the amount of dissolved solute in a solution gets high enough that the rate of “undissolving” matches the rate of dissolving.

204 g sugar

100 mLH2O Conc. = 204 g/100 mL

20oC

Solubility

20 9.2 Concentration and Solubility

Solubility

low

high

Co

nce

ntr

atio

n

Equilibrium

dissolving “undissolving”

250 g sugar

100 mLH2O

Conc. = 250 g/100 mL

20oC

Undissolved sugar

21 9.2 Concentration and Solubility

210 gsugar

100 mLH2O

20oC

Undissolved sugar

Temperature and solubility

210 gsugar

100 mLH2O

30oC

All the sugar is dissolved

22 9.2 Concentration and Solubility

Temperature has an effect on solubility

Temperature and solubility

210 gsugar

100 mLH2O

20oC

Undissolved sugar

210 gsugar

100 mLH2O

30oC

All the sugar is dissolved

23 9.2 Concentration and Solubility

ACTIVITY

READ THE TEXTBOOK FROM PAGE 239.

WORK PROBLEMS FROM PAGES 244 and 245.

24 9.2 Concentration and Solubility

Homework

FINISH YOUR ACTIVITY ASSIGNMENT AND SUBMIT IT

TOMORROW.