allu da maj aka అల్లుడా మజాకా lindsay krause & ellen sederdahl

Post on 30-Dec-2015

226 Views

Category:

Documents

0 Downloads

Preview:

Click to see full reader

TRANSCRIPT

Alluda Majaka

అల్లు�� డామజాకాLindsay Krause & Ellen Sederdahl

Video Explanation•Chiranjeevi is being chased by over a dozen men on either horseback or in Jeeps•He steals one of their horses and continues to be chased•As he and the horse continue down the road, a tractor trailer

completely blocks the intersection•In order to elude his followers, he gets the horse to fall, to slide

underneath the inconvenient tractor trailer, and get back up again, continuing his chase

• Find the force of friction• Use distance formula to find the

stopping distance in the movie• Use force of friction to determine acceleration• Use acceleration to determine the time it should

have taken the horse and Chiranjeevi to stop• Substitute the new time into the distance formula to

find the distance they should have traveled

Physics Explanation

Chiranjeevi• 5’9”• Average weight• 165 lbs = 75 kg

Horse• Average weight of riding horse• 1,200 lbs = 544kg

Total Weight75 kg + 544 kg = 619 kg

Estimations

Chiranjeevi begins at a distance of approximately 4

cars (3 cars and one car-sized space between the first car

and the tractor trailer)Approx. 1 ft between each car

Length of Car•Approximately 6.5 tires• 1 tire = 20 approx. inches

20 in.

Estimations

6.5 (length of one car in tires)X 20 (tire length in inches)130 inches per car 130 (car length)X 4 (number of cars + car sized space)520 total inches of cars & space (43.3 feet) 520 (total inches of cars & space)+ 24 (distance between the three cars) 544 = 13.817 meters

Distance traveled before fall:

13.817 meters

Calculations

CalculationsTime traveling before fall:

3:64 seconds

Velocity = distancetime

Velocity = 13.8 m3.63 sec

Velocity = 3.8 m/s

Velocity before fall

Coefficient of friction (µ)

Force of FrictionFk = µ·Fnorm = µ·m·gFk = .4(619 kg)(9.81 m/s²)

Fk = 2,429 N

Calculations

(brick and sand)

µ = .4

Stopping Distanced = ½(vi + vf)td = ½(3.8 m/s)(4.54 sec)

d = 8.6 meters

Calculations

Calculations

Fk = m·a-2,429 = (619 kg)aa = -3.924 m/sa = vf - vi

Time horse and Chiranjeevi should have stopped

t0

t = -via

t = -3.8-3.924

t = 0.97 seconds

CalculationsDistance Chiranjeevi and horse

should have stoppedd = ½(vi + vf)td = ½(3.8 m/s)(0.97 sec)d = 1.84 meters

Conclusion

In the film Chiranjeevi and the horse traveled about 8.6 meters in 4.54 seconds as they were sliding. However, in reality they should have traveled only 1.84 meters in .97 seconds. In the movie Chiranjeevi and the horse traveled

6.76 meters too long and 3.57 seconds too long.

8.6 m – 1.84 m = 6.76 meters too long

4.54 sec – .97 sec = 3.57 seconds too long

8.6 meters = 28.2 ft 1.84 meters = 6.0 ft

• Chiranjeevi height– http://www.imdb.com/name/nm0158112/bio

• Average Male Weight– http://www.halls.md/ideal-weight/met.htm

• Horse weight– http://en.wikipedia.org/wiki/Horse#Size_and_measurement

• Coefficient of Sand– http://www.supercivilcd.com/FRICTION.htm

• Alluda Majaka video– http://www.youtube.com/watch?v=uIFxEnkufnk

• Pictures– http://lifestyle.iloveindia.com/lounge/images/chiranjeevi.jpg– http://raveendrareddy.files.wordpress.com/2008/09/reenacreations-chiranjeevi1.jpg– http://www.window2india.com/cms/admin/userfiles/Image/Chiranjeevi.jpg– http://www.extramirchi.com/wp-content/uploads/2008/08/padmabhushan_chiranjeevi.jpg– http://s.chakpak.com/se_images/39651_-1_564_none/south-indian-superstar-chiranjeevi-wal

lpaper.jpg– http://bkr.8k.com/– http://s.chakpak.com/se_images/39653_-1_564_none/south-indian-superstar-chiranjeevi-wal

lpaper.jpg

References

top related